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Power Electronics Dr. Imtiaz Hussain Power Electronics Dr. Imtiaz Hussain

Power Electronics Dr. Imtiaz Hussain - PowerPoint Presentation

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Power Electronics Dr. Imtiaz Hussain - PPT Presentation

Assistant Professor email imtiazhussainfacultymuetedupk URL httpimtiazhussainkalwarweeblycom Lecture6 Thyristor Gate Control Circuits 1 Outline Introduction Voltage Divider Triggering ID: 934446

firing gate delay voltage gate firing voltage delay supply angle circuit circuits figure triggering current scr total load lead

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Slide1

Power Electronics

Dr. Imtiaz HussainAssistant Professoremail: imtiaz.hussain@faculty.muet.edu.pkURL :http://imtiazhussainkalwar.weebly.com/

Lecture-6Thyristor Gate Control Circuits

1

Slide2

Outline

IntroductionVoltage Divider TriggeringRC TriggeringDouble RC Triggering

Slide3

Introduction

The popular terms used to describe how SCR is operating are conduction angle and firing delay angle. Conduction angle is the number of degrees of an ac cycle during which the SCR is turned ON.Firing delay angle is the number of degrees of an ac cycle that elapses before the SCR is turned ON.

Of course, these terms are based on the notion of total cycle time (3600)

Slide4

Introduction

An SCR is fired by a short burst of current into the gate (IG).The amount of gate current needed to a fire particular SCR is symbolized as IGT.Most SCRs require current between 0.1 and 50mA.

Since there is a standard pn-junction between gate and cathode, voltage between these two terminals (VGK) must be slightly greater than 0.7 volt.

Slide5

Example-1

For the circuit shown in figure below, what voltage is required at point X to fire the SCR? The gate current needed to fire 2N3669 is 20mA under normal conditions.

Solution

The voltage between point X and cathode must be sufficient to forward bias the junction between X and K (0.7V).

And also at least cause 20mA

to flow

from 150

Ω

resistor.

For 20mA current to flow in XG branch we need

Therefore,

 

 

 

Slide6

Gate Control Circuits

Gate Control Circuit DesignConsideration must be given to the following points when designing gate control circuits.

The gate signal should be removed after the thyristor has been turned on. A continuous gate signal will increase the power loss in the gate junction.

No gate signal should be applied when the thyristor is reversed biased. If a gate signal is applied under these conditions, the thyristor may fail due to an increased leakage current.

The width of the gate pulse must be greater than the time required for the anode current to rise to the holding current. In practice, the gate pulse width is made wider than the turn-on time of the thyristor.

6

Slide7

A simple type of gate control circuit (triggering circuit) is shown in following figure.

Gate Control Circuits

When SW is closed, there will be current into the gate when supply voltage goes positive.

Firing delay angle is determined by setting of R

2

.

Slide8

One disadvantage of this simple triggering circuit is that the firing delay angle is adjustable is only from about 0

0 to 900.Gate Control Circuits

This can be understood by referring to following figure.

Slide9

Example-2

For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 20o. To what value should R2

be adjusted?

Solution

At 20o instantaneous supply voltage is

34

 

 

3K

Ω

40

Ω

Voltage drop across Load

 

 

Slide10

Example-2

Total resistance in the gate lead is given by

3K

Ω

40

Ω

Therefore, R

2

is

 

 

 

 

Slide11

Example-3

For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 30o. To what value should R2

be adjusted?

Solution

At 30o instantaneous supply voltage is

 

 

3K

Ω

40

Ω

Voltage drop across Load

 

 

Slide12

Example-3

Total resistance in the gate lead is given by

3K

Ω

40

Ω

Therefore, R

2

is

 

 

 

 

Slide13

Example-4

For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 60o. To what value should R2

be adjusted?

Solution

At 30o instantaneous supply voltage is

 

 

3K

Ω

40

Ω

Voltage drop across Load

 

 

Slide14

Example-4

Total resistance in the gate lead is given by

3K

Ω

40

Ω

Therefore, R

2

is

 

 

 

 

Slide15

Example-5

For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 90o. To what value should R2

be adjusted?

Solution

At 90o instantaneous supply voltage is

 

 

3K

Ω

40

Ω

Voltage drop across Load

 

 

Slide16

Example-5

Total resistance in the gate lead is given by

3K

Ω

40

Ω

Therefore, R

2

is

 

 

 

 

Slide17

Example-6

For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 150o. To what value should R2

be adjusted?

Solution

3K

Ω

40

Ω

At 150

o

instantaneous supply voltage is

 

 

Voltage drop across Load

 

 

Slide18

Example-6

Total resistance in the gate lead is given by

3K

Ω

5

Ω

Therefore, R

2

is

 

 

 

 

R

2

is same as it was for firing angle of 30

o

. Therefore with this circuit arrangement it is not possible to fire SCR beyond 90

o

.

Slide19

Example-7

For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 10o. To what value should R2

be adjusted?

Solution

At 10o instantaneous supply voltage is

3

 

 

3K

Ω

40

Ω

Voltage drop across Load

 

 

Slide20

Example-7

Total resistance in the gate lead is given by

3K

Ω

40

Ω

Therefore, R

2

is

 

 

 

 

Cannot have firing angle of 10

o

. For extended firing angle R

3

can be made smaller.

Slide21

Example-8

For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 18o. To what value should R2

be adjusted?

Solution

At 15o instantaneous supply voltage is

 

 

3K

Ω

40

Ω

Voltage drop across Load

 

 

Slide22

Example-8

Total resistance in the gate lead is given by

3K

Ω

40

Ω

Therefore, R

2

is

 

 

 

 

Slide23

Conclusion

The value of resistor R2 is increasing as firing angle is further delayed. S. NoFiring Angle

R21

10o-1.21KΩ

218160Ω3

20o

600

Ω

4

30

o

2.3K

Ω

5

60

o

9.3K

Ω690o7.7KΩ7150o2.37.7KΩ

Range of Firing Angles

Slide24

RC Triggering Circuits

The simplest method of improving gate control is to add a capacitor at the bottom of the gate lead resistance as shown in following figure.

Advantage of this circuit is that the firing delay angle can be adjusted past 90

o

.

Slide25

RC Triggering Circuits

This can be understood by focusing on the voltage across Capacitor C.

When the ac supply is –

ve

, the reverse voltage across SCR is applied to RC triggering circuit, charging the capacitor –

ve

on top plate and +

ve

on bottom plate.

When the supply enters its positive half cycle, the forward voltage drop across SCR tends to charge C in opposite direction.

However, voltage buildup in new direction is delayed until the –

ve

charge is removed.

Slide26

RC Triggering Circuits

The idea can be extended to achieve even extended firing angles by modifying the circuit slightly.

A resistor has been inserted into the gate lead, requiring the capacitor to charge higher than 0.7 V to trigger the SCR.

With the resistor in place, capacitor voltage must reach a value large enough to force sufficient current (I

GT

) through the resistor.

Slide27

RC Triggering Circuits

The firing delay angle can further be extended by the use of double RC network as shown in following figure.

The delayed voltage across C

1

is

used

to charge C

2

resulting in even further delay in building up the gate voltage.

Slide28

Triggering

50Hz sine wave takes 1/50 seconds to complete one cycle.

 

 

 

 

Slide29

RC Triggering Circuits

Capacitors in RC triggering circuits usually fall in the range from 0.01µF to 1µF.

For the given capacitor sizes minimum firing delay angle (maximum load current) is set by fixed resistors R

1

and R

3

.

The maximum firing angle (minimum load current) is set mostly by variable resistor R

2

.

When these gate control circuits are used with 50Hz AC supply, the time constant of the RC circuit should fall in the range of 1-20ms.

Slide30

RC Triggering Circuits

For single RC circuit of fig (a) the product (R

1

+R

2

)C

1

should fall in the range 1ms to 20ms.

For double RC circuit of fig(b

) (R

1

+R

2

)C

1

should fall in that range and R

3C2 should also fall in that range.

 

 

 

Fig(a)

Fig(b)

Slide31

Example-9

For the circuit shown in following figure approximate the R1, R2 and R3 to give wide range of firing adjustment.

 

 

Slide32

Example-9

The total time constant must fall in the range of 1ms-20ms.Let us set

and

. RC ntwork-1 must provide 1ms-18ms of firing delay and RC netwrork-2 2ms of delay.

 

 

 

Minimum time constant occurs in RC network-1 when R

2

is set to minimum.

 

 

 

 

 

Slide33

Example-9

 

 

Maximum time constant occurs in RC netwrok-1 when R

2

is set to maximum.

 

 

 

 

Slide34

Example-9

 

 

Time constant of RC netwrok-2 is 2ms.

 

 

 

 

Slide35

Example-9

 

 

Minimum and maximum firing angles are (18

o

=1ms)

 

 

 

 

 

Slide36

Example-10

For the circuit shown in following figure, to what value the potentiometer be set to obtain a firing delay angle of 120o.

 

 

 

 

Slide37

Use of Break Over Devices

The firing circuits discussed so far share two disadvantages.Temperature dependenceInconsistent firing behaviour between SCRs of same typeThese problems can be eliminated by introducing a break over device at gate terminal

Slide38

Use of Break Over Devices

Four layer diode (Shockley Diode) has certain break over voltage.

Slide39

Shockley Diode

Slide40

End of Lecture-6

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