/
Limits Graphical Solutions Limits Graphical Solutions

Limits Graphical Solutions - PDF document

catherine
catherine . @catherine
Follow
353 views
Uploaded On 2021-09-30

Limits Graphical Solutions - PPT Presentation

1Graphical LimitsLet be a function defined on the interval 611 whose graph is given as The limits are defined as the value that the function approaches as it goes to an x value Using this definition ID: 890934

x008f x008e limits limit x008e x008f limit limits function rule left equal find graph denominator method defined point general

Share:

Link:

Embed:

Download Presentation from below link

Download Pdf The PPT/PDF document "Limits Graphical Solutions" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

1 1 Limits: Graphical Solutions
1 Limits: Graphical Solutions Graphical Limits Let ݂ be a function defined on the interval [ - 6,11] whose graph is given as: The limits are defined as the value that the function approaches as it goes to an x value. Using this definition, it is possible to find the value of the limits given a graph. A few examples are below: Ž  ି ଷ ݂ Ͳ Ž  ଶ ݂ Ͷ Ž  ଼ ݂ െ – In general, you can see that these limits are equal to the value of the function. This is true if the function is continuous . Continuity Continuity of a graph is loosely defined as the ability to draw a graph without having to lift your pencil. To better understand this, see the graph below: Let’s investigate at the flowing points: െ ͵ Discontinuous at this point The value is not defined at - 3 “Removable discontinuity” Ͳ Discontinuous at this point The limit of the left is not equal to the limit from the right “Hump discontinuity” – Discontinuous at this point The limit from the left is equal to the right, but is not equal to the value of the function “Removable discontinuity” Ͷ Continuous at this point The limit from the left is equal to the limit from the right and equal to the value of the function Í· Continuous at this point The limit from the left is equal to the limit from the right and equal to the value of the function ͸ Discontinuous at this point The value of the limit is equal to negative infinity and therefore not defined “=nfinite discontinuity” Limits 2 One - Sided Limits : General Definition One - sided limits are differentiated as right - hand limits ( when the limit approaches from the right) and left - hand limits ( when the limit approaches from the left) whereas ordinary limits are sometimes referred to as

2 two - sided limits . Right - hand limits
two - sided limits . Right - hand limits approach the specified point fro m positive infinity. Left - hand limits approach this point from negative infinity. The right - handed limit: Ž  ݂ Ü® The left - handed limit: Ž  ݂ Ü® A. Now you try some! Determine if the following limits exist s : Ž  ି ଷ ݂ Ž  ି ଶ ݂ Ž  ଴ ݂ Ž  ଵ ݂ Ž  ଶ ݂ Ž  ଷ ݂ A More Formal Definition of Continuity From this information, a more formal definition can be found. Continuity, at a point a , is defined when the limit of the function from the left equals the limit from the right and this value is also equal to the value of the function. Using notation, for all points a where ݈ ݉ ݂ ݈ ݉ ݂ ݂ , the function is said to be continuous . - 7 - 4 - 4 4 4 7 3 Summary: When does a limit not exist?  A general limit does not exist if the left - and right - hand limits aren’t equal (resulting in a discontinuity in the function).  A general limit does not exist wherever a function increa ses or decreases infinitely (“without bound” ) as it approaches a given x - v alue.  A general limit does not exist in th e cases of infinite oscillation when approaching a fixed point . Limits: Numeric Solutions Now that you know how to solve a limit graphically͕ you may be asking yourself: ‘That’s great͕ but what about when there isn’t a graph in the problem?’ That is a good question͕ and that is what this next s ection is about. There are a many better (and more accurate ) ways to find the value of the limit tha n graphing or plugging in numbers that get close r and closer to the val ue

3 of interest . These solution methods fa
of interest . These solution methods fall under three categories: substitution, factoring , and the conjugate method. But first things first͕ let’s discuss some of the general rules for limits. Limit Rules Here are some of the general limit rules ( with Ž  ௖ ݂ Ü® and Ž  ௖ ݃ ܯ ) : 1. Sum Rule : The limit of the sum of two functions is the sum of their limits Ž  ௖ ( ݂ ൅ ݃ ) Ž  ௖ ݂ ൅ Ž  ௖ ݃ Ü® ൅ ܯ 2. Difference Rule : The limit of the difference of two functions is the difference of their limits Ž  ௖ ( ݂ െ ݃ ) Ž  ௖ ݂ െ Ž  ௖ ݃ Ü® െ ܯ 3. Product Rule : The limit of a product of two functions is the product of their limits Ž  ௖ ( ݂ ݃ ) Ž  ௖ ݂ Ž  ௖ ݃ Ü® ܯ 4. Constant Multiple Rule : The limits of a constant tim es a function is the constant ti mes the limit of the function Ž  ௖ ( ݇ ݂ ) ݇ Ž  ௖ ݂ ݇ Ü® 5. Quotient Rule : The limit of a quotient of two functions is the quotient of their limits, provided the limit of the denominator is not zero Ž  ௖ ( ݂ ݃ ) Ž  ௖ ݂ Ž  ௖ ݃ Ü® ܯ ܯ Ͳ Limit Rule Examples Find the following limits using the above limit rules: 1. Ž  ௖ ଷ ൅ Ͷ ଶ െ ͵ Ž  ௖ ଷ ൅ Ž  ௖ Ͷ ଶ െ Ž  ௖ ͵ ଷ ൅ Ͷ ଶ െ ͵ 2. Ž  ௖ à°° ା à°® ି ଵ à°® ା ହ à­ª à­« ( à°° ା à°® ି ଵ ) à­ª à­«

4 à°® ା ହ Ž &#
à°® ା ହ Ž  ௖ ସ ൅ Ž  ௖ ଶ െ Ž  ௖ ͳ Ž  ௖ ଶ ൅ Ž  ௖ Í· ସ ൅ ଶ െ ͳ ଶ ൅ Í· 4 3. Ž  ଵ à°° ା à°® ି ଵ à°® ା ହ à­ª à­« à°­ ( à°° ା à°® ି ଵ ) à­ª à­« à°­ à°® ା ହ Ž  ଵ ସ ൅ Ž  ଵ ଶ െ Ž  ଵ ͳ Ž  ଵ ଶ ൅ Ž  ଵ Í· ͳ ସ ൅ ͳ ଶ െ ͳ ͳ ଶ ൅ Í· ͳ ͸ B. Now you try some! 1. Ž  ௖ – ൅ Í· 2. Ž  ଺ ͺ െ Í· െ ͹ 3. Ž  ଶ ା ଶ à°® ା ହ ା ଺ Limits of Rational Functions : Substitution Method A rational function is a function t hat can be written as the ratio of two algebraic expressions . If a function is considered rational and the denominator is not zero, the limit can be found by substitution. This can be seen in the example below (which is similar to the example #3 above, but now done in one quick, convenient step): Ž  ି ଵ ଷ ൅ Ͷ ଶ െ ͵ ଶ ൅ Í· െ ͳ ଷ ൅ Ͷ െ ͳ ଶ െ ͵ െ ͳ ଶ ൅ Í· Ͳ ͸ Ͳ This can be defined more formally as: If and are algebraic expressions and Ͳ , then: Ž  ௖ C. Now you try some! 1. Ž  ି ହ à°® ା ଷ ି ହ ା ଻ 2. Ž  ଶ ା ଷ ା ଺ Factoring Method Consider the function à°® ି ଽ ା ଷ . How would you find the limit of ݂ as approaches - 3? If you try to use substitution to find the limit, world - ending paradoxes

5 ensue : Ž  ି ଷ
ensue : Ž  ି ଷ ଶ െ Í» ൅ ͵ െ ͵ ଶ െ Í» െ ͵ ൅ ͵ Ͳ Ͳ But fear not, t his answer just tells us that we must use a different method to find the limit, because the function likely has a “ hole ” at the given x value. Therefore, the factoring method can be tried . To start this method, the numerator and denominator must be factored (in this case the denominator is “factored” already) . Ž  ି ଷ ൅ ͵ െ ͵ ൅ ͵ The factor ൅ ͵ can be canceled to get the much sim pler limit expression of Ž  ି ଷ െ ͵ that can easily be evaluated via substitution: Ž  ି ଷ െ ͵ െ ͵ െ ͵ െ ͸ 5 Therefore , the result of t he limit can be found, with the understanding that there is a “ hole ” in the graph at െ ͵ . Hence, Ž  ି ଷ à°® ି ଽ ା ଷ െ ͸ . D. Now you try some! a) Ž  ହ ଶ à°® ି ଻ ି ଵହ ି ହ b) Ž  ଵ à°¯ ି ଵ ି ଵ Conjugate Method The conjugate of a binomial expression (i.e. an expression with two terms , you can tell this because of the Latin root bi - meaning two ) is the same expression with opposite middle sign s . For example, the conjugate of √ െ Í· is √ ൅ Í· . This is really useful if you have a radical in your limit. This is be cause t he product of two conjugates containing radicals will, itself, contain no radical expressions. See below: ( √ െ Í· ) ( √ ൅ Í· ) √ ଶ ൅ Í· √ െ Í· √ െ –ͷ െ –ͷ You should use the conjugate method whenever you have a limit problem containing radicals for which substitutio n does not work. Example : Evaluate Ž  ହ √ ା ଵଵ ି ସ ି ହ First try the su

6 bstitution method: Ž 
bstitution method: Ž  ହ √ ൅ ͳͳ െ Ͷ െ Í· √ Í· ൅ ͳͳ െ Ͷ Í· െ Í· Ͳ Ͳ Well, another hole in the universe, or at least the graph. =ndicating that you’ll need another method to find the limit since the function probably has a hole at Í· . To start, multiply both the numerator and denominator by the conj ugate of the radical expression ( √ ൅ ͳͳ ൅ Ͷ ) : Ž  ହ √ ൅ ͳͳ െ Ͷ െ Í· ( √ ൅ ͳͳ ൅ Ͷ ) ( √ ൅ ͳͳ ൅ Ͷ ) Ž  ହ ൅ ͳͳ െ ͳ͸ െ Í· ( √ ൅ ͳͳ ൅ Ͷ ) Ž  ହ െ Í· െ Í· ( √ ൅ ͳͳ ൅ Ͷ ) 6 Cancel the െ Í· factor in the numerator and denominator. Ž  ହ ͳ ( √ ൅ ͳͳ ൅ Ͷ ) ͳ ( √ Í· ൅ ͳͳ ൅ Ͷ ) ͳ ͺ E. Now you try some! a) Ž  ି ଶ ା ଶ √ ା ଺ ି ଶ b) Ž  ି ଵ √ ା ଵ଴ ି ଷ ା ଵ Example 1: Testing the Definition Show: Ž  ଵ Í· െ ͵ – We have to find a suitable Ͳ so that if ͳ and x is with in distance , that is if: Ͳ | െ ͳ | Then ݂ is within distance of Ü® – that is | ݂ െ – | | Í· െ ͵ െ – | | Í· െ Í· | Í· | െ ͳ | | െ ͳ | Í· Thus, we can take ହ due to the fact that Ͳ | െ ͳ | , then: | ݂ െ – | Ͳ െ | ݂ െ Ü® | Ž  ݂ Ü® െ െ Ͳ | ݂ െ Ü® | Ž  ݂ Ü® Formal Definition : Limits Limits are more formally defined as “L is the limit of f(x) as x approaches a if for every number Ͳ , there is a corresponding number Ͳ such that for all x. Using

7 notation we write
notation we write Ž  ݂ Ü® IFF Ͳ | െ | | ݂ െ Ü® | From the for mal definition, right - handed limit can be defined as: And written as: Whereas the left - handed limit can be defined as: And written as: 7 So, if | Í· െ ͵ െ – | | Í· െ Í· | Í· | െ ͳ | Í· Í· ( ହ ) therefore , Ͳ | െ ͳ | ହ | ݂ െ – | and Ž  ଵ Í· െ ͵ – . Limits: Advanced Topics Previously , when we found that the result of a limit do ing straight substitution yielded ଴ ଴ we used factoring or conjugation to be able to solve the pr oblem. What happens when neither of those methods prove useful ? You become very grateful for the 17th - century French mathematician Guillaume de L’Hôpital ͘ L’ Hôpital was the man that derived a method of solving these types of equations, known as indeterminate forms͘ This method͕ known as L’ Hôpital ’s Rule͕ is formally defi n ed below. Example 1 : indeterminate form of Find the limit Ž  ଴ ௘ ି ଵ Ž  ଴ ݁ െ ͳ Ͳ Ͳ Ž  ଴ ݁ ͳ Using L’ Hôpital ’s Rule: Ž  ଴ ݁ െ ͳ Ž  ଴ ݁ ͳ ͳ ͳ ͳ Example 2 : indeterminate form of Find the limit Ž  à°® ଶ Ž  ଶ – Using L’ Hôpital ’s Rule: Ž  ଶ – Ž  – – ݈݊ – – ݈݊ – Ž  – Using L’ Hôpital ’s Rule again: – ݈݊ – Ž  – – ݈݊ – Ž  ͳ – ݈݊ – – ݈݊ – ଶ Ž  ͳ – – ݈݊ – à¬

8 ¶ Ͳ Ͳ Ͳ Ͳ േ Ͳ à
¶ Ͳ Ͳ Ͳ Ͳ േ Ͳ േ െ Ͳ ଴ ͳ ଴ Ž  ௖ ݂ ݃ Ž  ௖ ݂ ݃ Formal Definition : L’Hôpital’s Rule If the limit Ž  ௖ ௙ ௚ results i n one of the following forms: And Ž  ௖ ௙ ௚ exits and ݃ Ͳ , then: 8 Example 3 : indeterminate form of െ Find the limit Ž  ଶ ( ସ à°® ି ସ െ ଵ ି ଶ ) Ž  ଶ ( Ͷ ଶ െ Ͷ െ ͳ െ – ) െ Using L’ Hôpital ’s Rule: Ž  ଶ ( Ͷ ଶ െ Ͷ െ ͳ െ – ) Ž  ଶ Ͷ െ ൅ – െ – ൅ – Ž  ଶ – െ ଶ െ Ͷ Ž  ଶ െ ͳ – െ ͳ Ͷ Example 4 : indeterminate form of Find the limit Ž  ଵ à°­ à°­ Ž  ଵ ଵ ଵ ି ͳ Let à°­ à°­ . Then Ž Ž à°­ à°­ ୪୬ ଵ ି Using L’ Hôpital ’s Rule: Ž  ଵ Ž Ž  ଵ Ž ͳ െ Ž  ଵ ͳ െ ͳ െ Ž  ଵ ͳ െ ͳ Therefore Ž  ଵ Ž െ ͳ Ž  ଵ ଵ ଵ ି Ž  ଵ ݁ ି ଵ ͳ ݁ Example 5 : indeterminate form of Find the limit Ž  ଴ Ž Ž  ଴ Ž Ͳ Using L’ Hôpital ’s Rule: Ž  ଴ Ž Ž  ଴ Ž ͳ Ž  ଴ ͳ െ ͳ ଶ Ž  ଴ െ Ͳ

9 F. Now you try some! 1. Ž
F. Now you try some! 1. Ž  ଴ ଷ ସ 2. Ž  ଵ ହ à°° ି ସ à°® ି ଵ ଵ଴ ି ି ଽ à°¯ 3. Ž  ௘ à°¯ 4. Ž  ି ݈݊ 5. Ž  à°­ 6. Why does the Ž  ି ଵ √ ା ସ ି ଷ ା ଵ not equal ͳ – √ ͵ ⁄ ? Note the trick that is needed here – what happens if you use L’Hôpital’s Rule without making this initial change? 9 7. Early in their presentation of limits, most teachers present the following two limit facts as special cases: Ž  ଴ à­¬ ͳ and Ž  ଴ à­­ ି ଵ = 0͘ Verify each by using L’ Hôpital ’s Rule. Limits to Infinity (Horizontal Asymptotes) What happens to a function as it goes further and further out to the left and right? Well, that depends on the function. But half of the answer can be discovered by allowing the independent variable to take on increas ingly large, positive values and keeping an eye on the output (the graph) - this investigates what is happening as we go further and further to the right. The other half is discovered by allowing the independent variable to take on increasingly large, neg ative values and, again, keeping an eye on the output – this investigates what is happening as we go further and further to the left. Here are some basic facts and some generalizations that will be sufficient to evaluate most “limits to infinity”͘ Con sider the function as an algebraic fraction, and consider the ratio of the leading terms. Let the algebraic expression in the numerator be expressed as n(x) and the algebraic expression found in the denominator be expressed as d(x) , then  If the degree of the numerators is lower than the degree of the denominator, then Ž 

10 ௗ Ͳ . In general,
ௗ Ͳ . In general, w henever the denominator grows faster than th e numerator , the limit will go to zero. Thus, in these cases, as the graph extends far to both the left and the right, the output (i.e., the graph) gets closer and closer to zero. Here is a list of functions in order of their rate of growth – qu icke st to slowest: Ͷ ͵ – ସ ଷ ଶ Ž‘ Ž‘ ͕ ͙ ͕ 3͕ 2͕ 1 Example s : a. Ž  ହ à°¯ ି ଶ à°® ା ଻ ି ଵଷ ଵଶ ି ଶ ା à°° Ž  ହ à°¯ à°° Ž  ହ Ͳ b. Ž  ଺ ୪୭ ା ହ ି ଶ ଶ ଶ ି ଵସ ୪୭ Ž  ଺ ୪୭ ଶ Ͳ  If the degree of the numerator is higher than the degree of the denominator, then Ž  ௗ ݋ െ . In general, w henever the numerator grows faster than the denominator, the limit will go to positive or negative infinity . Thus, in these cases, as the graph extends far to both the left and the right, the output (i.e., the graph) increases or decreases without bound . In these cases, each side needs to be considered separately. 10 Example s : a. Ž  ଷ à°± ା à°® ି ହ ଺ ା ା ଻ à°® Ž  ଷ à°± ଻ à°® Ž  ଷ ଻ ଷ whereas Ž  ି ଷ à°± ା à°® ି ହ ଺ ା ା ଻ à°® Ž  ି ଷ ଻ ଷ െ b. Ž  ି ୪୭ ା ଵ ଶ ା ଷ à°± ି ହ ୪୭ Ž  ଶ ൅ [ Note that Ž  ି ି ୪୭ ା ଵ ଶ ା ଷ à°± ି ହ ୪୭ is meaningless since x ! is not defined for negative v

11 alues. ] c. Ž 
alues. ] c. Ž  – ସ െ Í· ൅ ͵ = + ( Note that Ž  ି – ସ െ Í· ൅ ͵ ൅ as well [why?] )  If the degrees are equal, then Ž  ௗ is equal to the leading coefficient of n(x) over the leading coefficient of d(x) . Examples: a. Ž  ଷ à°¯ ି ଶ à°® ା ି ସ ସ ା ଶ ି ହ à°¯ Ž  ଷ à°¯ ି ହ à°¯ Ž  ଷ ି ହ െ ଷ ହ b. Ž  à°­ à°® ଶ à°¯ à°° ଶ ି ୪୭ ା ସ = ଵ ଶ ⁄ ଷ ସ ⁄ ଶ ଷ G. Now you try some! 1. Ž  ି ଶ à°¯ ି ଶ ା ହ ଵଷ à°¯ ା à°® ି ହ ା ଵଷ 2. Ž  ା ହ ା ଵ à°® ି ଷ ା ସ 3. Ž  ି ଶ à°® 4. Ž  ା ଶ à°® 5. Ž  ି െ ͵ ଷ ൅ – ଶ െ Ͷ ൅ Í· 11 Solutions to “ Now You Try Some! ” A. Ž  ି ଷ ݂ ͵ Ž  ି ଶ ݂ DNE (“Does not exist”) Ž  ଴ ݂ െ ͳ Ž  ଵ ݂ Ü° Ž  ଶ ݂ Ͳ Ž  ଷ ݂ െ – B. 1. 2c+5 2. - 8 3. 1/5 C. 1. 5/2 2. 5/8 D. 1. 13 2. 3 E. 1. 4 2. 1/6 F. 1. 3 /4 2. 3/7 3.  (gets larger and larger without bound; technically this limit DNE) 4. DNE – cannot take the logarithm of negative values 5. 1 6. Upon substituting - 1 into the numerator and denominator, we do not get one of the indeterminate forms͖ therefore we cannot use L’Hôpital’s Rule͘ More advanced methods need to be used. G. 1. 2/13 2. 0 3. 0 4. +  5