Chapter 55 Linear Approximation A useful characteristic of the tangent line to a curve at a point is that for values near the point the curve is approximately linear In fact the function values of the curve are approximated by the derivative values near the point of tangency ID: 627645
Download Presentation The PPT/PDF document "Linearization and Differentials" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.
Slide1
Linearization and Differentials
Chapter 5.5Slide2
Linear Approximation
A useful characteristic of the tangent line to a curve at a point is that, for
-values near the point, the curve is approximately linear
In fact, the function values of the curve are approximated by the derivative values near the point of tangencyWe say that differentiable curves are always locally linearIn this section we will explore local linearity
2Slide3
Linear Approximation
3Slide4
Linear Approximation
4Slide5
Linear Approximation
5Slide6
Linearization
DEFINITION:
If
is differentiable at
, then the equation of the tangent line,
defines the
linearization of
at
. The approximation
is the
standard linear approximation of
at
. The point
is the
center of approximation
.
6Slide7
Example 1: Finding a Linearization
Find the linearization of
at
, and use it to approximate
without a calculator. Then use a calculator to determine the accuracy of the approximation.
7Slide8
Example 1: Finding a Linearization
Find the linearization of
at
, and use it to approximate
without a calculator. Then use a calculator to determine the accuracy of the approximation.
Note that we are approximating
. The center of the approximation is at
; that is,
in
Find the derivative:
; find
and
. So our linear approximation is
Therefore,
8Slide9
Example 1: Finding a Linearization
Find the linearization of
at
, and use it to approximate
without a calculator. Then use a calculator to determine the accuracy of the approximation.
The calculator value is
The difference is
Note that as we choose values farther from zero, the approximation becomes less accurate. For example, the approximation for
would be
, which differs from the true value by
or about
. We
could
get a better approximation by choosing a center closer to
9Slide10
Example 1: Finding a Linearization
10Slide11
Example 1: Finding a Linearization
11Slide12
Example 2: Finding a Linearization
Find the linearization of
at
and use it to approximate
without a calculator. Then use a calculator to determine the accuracy of the approximation.
12Slide13
Example 2: Finding a Linearization
Find the linearization of
at
and use it to approximate
without a calculator. Then use a calculator to determine the accuracy of the approximation.
Here,
, so
The approximation is
The calculator value to 9 decimal places is
. The difference is
This amounts to a percent difference of about
13Slide14
Example 3: Approximating Binomial Powers
Example 1 introduces a special case of a general linearization formula that applies to powers of
for small values of
:
If
is a positive integer this follows from the Binomial Theorem, but the formula actually holds for
all
real values of
. Use this formula to find polynomials that will approximate the following functions for values of
close to zero:
a)
b)
c)
d)
14Slide15
Example 3: Approximating Binomial Powers
a)
b)
c)
d)
The first example does not seem to follow the pattern. One technique to use when this happens is to substitute a variable so that the pattern is the same. Let
. The function is therefore
. Now back-substitute to get
This example shows that we need merely use the term in place of
in the formula. So the rest of the examples are:
15Slide16
Example 4: Approximating Roots
Use linearization to approximate. State how accurate your approximation is.
16Slide17
Example 4: Approximating Roots
Use the function
and center it around
. Then
and
,
. So,
. Linearization means that
at values of
near the center. Therefore,
.
The difference between
and our approximation is:
This number is less than
, so
17Slide18
Example 4: Approximating Roots
The nearest perfect cube to 123 is
, so we will center around
. Our function is
and we want an approximation to
. Linearization requires
.
Now,
and
. Our linearization formula is
. Use this to approximate
:
The difference between
and
is
18Slide19
Differentials
The notation
was Leibniz means of representing the derivative of a function
It is written as a ratio because Leibniz believed that it was a ratio (so did Newton)
But this was their thinking prior to the development of the limit concept almost 200 years laterRecall that we define this notation as
It is not a ratio, then, but a
limit
19Slide20
Differentials
This matters because it is a mistake to think that, since it is written as a ratio, then all the laws relating to ratios also apply
In mathematics, we can often decide what we want something to mean (within reason) by defining what it means
Our definition cannot be such that other theorems are contradicted by results obtained from our definitionWe will define the “numerator” and “denominator” of
separately in a way that allows us to use them separately
20Slide21
Differentials
DEFINITION:
Let
be a differentiable function so that
. The
differential
is an independent variable (that is, it’s a number) and the
differential
is
Note that
is a dependent variable and also a function dependent on both
and
.
21Slide22
Example 5: Finding the Differential
Find the differential
for the given values of
and
.
22Slide23
Example 5: Finding the Differential
Find the differential
for the given values of
and
.
In differential form, we can write
Now,
We could also take the derivative as we have in the past
Then rewrite this is
23Slide24
Example 5: Finding the Differential
Find the differential
for the given values of
and
.
In differential notation,
Then
24Slide25
Example 5: Finding the Differential
Find the differential
for the given values of
and
.
We can begin by solving the equation for
, but we can also use implicit differentiation
Now gather like terms together on each side and solve for
25Slide26
Example 5: Finding the Differential
Find the differential
for the given values of
and
.
If
, then using the original equation we have
. Therefore,
26Slide27
Differential Notation
Using differential notation can make our work more concise
, which corresponds to
, which corresponds to
, which corresponds to
27Slide28
Example 6: Finding Differentials of Functions
Find
28Slide29
Example 6: Finding Differentials of Functions
Find
We need the Chain Rule here to deal with the inner function,
:
29Slide30
Example 6: Finding Differentials of Functions
Find
Use the Quotient Rule:
30Slide31
Estimating Change with Differentials
We can use local linearity to approximate the change in some differentiable function
; that is, to approximate
The equation of the tangent line at some point
is
If
is some small number, then
is a number near
and
31Slide32
Estimating Change with Differentials
32Slide33
Differential Estimate of Change
DEFINITION
Let
be differentiable at
. The approximate change in the value of
when
changes from
to
is
33Slide34
Example 7: Estimating Change with Differentials
The radius
of a circle increases from
m to 10.1 m. Use
to estimate the change in the circle’s area . Compare this estimate with the true change
, and find the approximation error (i.e., the difference between the true value and the approximate value).
34Slide35
Example 7: Estimating Change with Differentials
The actual change in area is
The approximate change in area (given
) is
Note that
and
. So the approximate change in area is
The actual change is
The error of approximation is
35Slide36
Absolute, Relative, and Percentage Change
We can describe the change in
as
changes from to
in three ways
Absolute change:
actual
;
approximate
Relative change:
actual
;
approximate
Percentage change:
actual
;
approximate
36Slide37
Example 8: Changing Tires
Inflating a bicycle tire changes its radius from 12 inches to 13 inches. Use differentials to estimate the absolute change, the relative change, and the percentage change in the perimeter of the tire.
37Slide38
Example 8: Changing Tires
We have
and
, so
. Since
, then the approximate change (absolute) is
The relative change is
The percentage change is
38Slide39
Example 9: Estimating the Earth’s Surface Area
Suppose the earth were a perfect sphere and we determined its radius to be
miles. What effect would the tolerance of
miles have on our estimate of the earth’s surface area?
39Slide40
Example 9: Estimating the Earth’s Surface Area
40Slide41
Example 9: Estimating the Earth’s Surface Area
We can use algebra to determine the upper and lower values of the interval where the “true” surface area lies.
From this we see that the “true” surface area is within about
square miles of the measured value.
41Slide42
Example 9: Estimating the Earth’s Surface Area
Now let’s compare this with the estimate using differentials.
We are looking for the approximation of
, where
and
Your textbook claims that this is an area about the same size as the state of Maryland.
42Slide43
Example 10: Determining Tolerance
About how accurately should we measure the radius
of a sphere to calculate the surface area
within 1% of its true value?
43Slide44
Example 10: Determining Tolerance
44Slide45
Example 10: Determining Tolerance
We see from the previous slide that
Since
, then
The radius should be measured to within 0.5% of its true value.
45Slide46
Example 11: Unclogging Arteries
In the late 1830s, the French physiologist Jean
Poiseuille
, discovered the formula we use today to predict how much the radius of a partially clogged artery has to be expanded to restore normal flow. His formula,
, says that the volume
of fluid flowing through a small pipe or tube in a unit of time at a fixed pressure is a constant time the fourth power of the tube’s radius
. How will a 10% increase in
affect
?
46Slide47
Example 11: Unclogging Arteries
First recognize that the percentage change is
, and that we seek
.
So a 10% increase in the radius results in a 40% increase in blood flow.
47