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17.2   Primary Structure of Nucleic Acids 17.2   Primary Structure of Nucleic Acids

17.2 Primary Structure of Nucleic Acids - PowerPoint Presentation

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17.2 Primary Structure of Nucleic Acids - PPT Presentation

Each nucleic acid has its own unique sequence of bases that carries the genetic information from one cell to the next Learning Goal Describe the primary structures of DNA and RNA Nucleic Acid Structure ID: 918499

group nucleic acid phosphate nucleic group phosphate acid sugar solution sequence free cytidine nucleotide dinucleotide hydroxyl nucleotides rna bond

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Slide1

17.2 Primary Structure of Nucleic Acids

Each nucleic acid has its own unique sequence of bases that carries the genetic information from one cell to the next.

Learning Goal Describe the primary structures of DNA and RNA.

Slide2

Nucleic Acid Structure

Nucleic acids are polymers of many nucleotides in which the 3′-hydroxyl group of the sugar in one nucleotide bonds to the phosphate group on the 5′-carbon atom in the sugar of the next nucleotide

have a unique sequence of bases, which is called their primary structurehave one terminal end with an unreacted or free sugar with a 5′-phosphate have a sugar at the other end with a free 3′-hydroxyl group

Slide3

Nucleic Acid Structure

The link between the sugars in adjacent nucleotides is referred to as a phosphodiester bond.

Slide4

Study Check

Draw the condensed structural formula for the RNA dinucleotide formed by two cytidine-5′-monophosphates.

Slide5

Solution

Draw the condensed structural formula for the RNA dinucleotide formed by two cytidine-5′-monophosphates.

SOLUTION: The dinucleotide is drawn by connecting the 3′-hydroxyl group on the first cytidine-5′-monophosphate with the 5′-phosphate group on the second.

Slide6

Solution

Draw the condensed structural formula for the RNA dinucleotide formed by two cytidine-5′-monophosphates.

Slide7

Nucleic Acid Sequence

A nucleic acid sequence is read from the sugar with free 5′-phosphate to the sugar with the free

3′-hydroxyl group.The sequence is written using the letters of the bases: — A C G U —

Slide8

Study Check

Fill in the blank.

In a nucleic acid, the nucleotides are joined by a _____________ bond that joins the 3′-OH group of the sugar to the phosphate group on the 5′C on the next nucleotide.

Slide9

Solution

Fill in the blank:

In a nucleic acid, the nucleotides are joined by a phosphodiester bond that joins the 3′-OH group of the sugar to the phosphate group on the 5′C on the next nucleotide.

Slide10

Study Check

In the nucleic acid — C G A U

—, which base is at the free5′-phosphate end? cytosine uracil thymine adenine

Slide11

Solution

In the nucleic acid — C G A U

—, which base is at the free5′-phosphate end? cytosine uracil thymine adenineThe correct answer is A. Cytosine is at the free 5′-phosphate end.