FASFresh Air Supply Units TGFAS3 MAKEUP AIR HEATING Why the FAS Unit is Needed exhausted from buildings Without sufficient freshair a negative pressure is created inside theexhaust system and hind ID: 828439
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1 STEAM AND HOT WATER MAKE-UP AIR HEATERS
STEAM AND HOT WATER MAKE-UP AIR HEATERS WITH INTEGRAL FACE AND BYPASS COILS FOR EFFECTIVE TEMPERATURE CONTROL FASFresh Air Supply Units TGFAS-3 MAKE-UP AIR HEATING Why the FAS Unit is Needed exhausted from buildings. Without sufficient freshair, a negative pressure is created inside theexhaust system and hindering its performance.Wing FAS Fresh Air Supply units offer a solution tothis problem by delivering a constant volume offresh tempered air.FAS
2 Units maintain effective temperature co
Units maintain effective temperature control byusing integral face and bypass coils with steam orhot water as the heating source. The integral faceFifteen sizes of FAS Units are available to cover arange of airflows from 855 to 26,000 cfm. Designsflow. ontal Air Flo w - Type FASU units areType FASU units are ideal for preheating make-upapplication, please request Application Manual tical Air Flo w Vertical FAS Units are designedheating section o
3 f the FAS Unit. Air is dischargedthrough
f the FAS Unit. Air is dischargedthrough either a fixed (Type FASHCF) or revolvingdischarge (Type FASHCR).Type FASHCF has four different available fixedType FASHCR has Wings unique revolvingof tempered fresh air for comfortable ventilation. Adischarge by means of an idler gear drive. Thecover all directions. The discharge velocity issufficient to carry tempered air to walls, floor andremote corners. Four different discharge types areavailable to c
4 over a wide range mounting heights. By
over a wide range mounting heights. By including an optional mixing box upstream of avertical FAS unit, space heating can be obtained in Model Number Description FASU = Horizontal airflow unitDischarge Type:V, H, HV -- FASU only4R, 5R, 8R or 10R -- FASHCR onlyFASHCF = Vertical airflow unit with 1F, 4F, 5F or 8F -- FASHCF onlyFASHCR = Vertical airflow unit with FASHCF305F DESIGN AND CONSTRUCTION Type:Fin and tube, extended surface type. Tubes: 3/8
5 O.D. copper, 0.028 thick wall forserv
O.D. copper, 0.028 thick wall forservice to 200 psig and 400 degrees F. (Optionalcarbon steel fins). Schedule 40 steel, connected to tubes by l y plates welded to the headers. Tube ends are ace and b s 16 gauge galvannealed steel The heater Type:Aluminum through size 27; steel for larger Type:Totally enclosed, fan-cooled (TEFC)Cface frame through size 27; rigid base Type: 5 FT.10 FT.15 FT.20 FT.1/61/41,15078.055.749.746.243.71/61/41,15079.055
6 .949.946.443.91/41/41,15082.059.153.149.
.949.946.443.91/41/41,15082.059.153.149.647.11/41/41,15084.461.255.251.749.21/21/21,15086.063.657.654.151.61/21/21,15096.376.870.867.364.83/43/41,15098.078.472.468.966.43/43/485092.575.169.065.663.11-1/21-1/285094.576.670.667.164.61-1/21-1/285095.077.171.167.665.12285097.079.073.069.567.53385099.080.274.270.768.23385099.580.774.771.268.755850101.583.577.574.071.57-1/27-1/2850102.884.978.975.472.92. Single-phase units size 30 and larger, and sizes 4
7 0 and 41 for 208/3/60 service are belt-d
0 and 41 for 208/3/60 service are belt-driven. FAS SIZEFAN RPMSOUND PRESSURE LEVEL IN DbaMOTOR HPLEVEL - dB AT DISTANCE FROM UNIT 7 Steam Units Hot Water Units 1.Select FAS Unit with or without filters to meet project make-up air requirements from Table 1.2.Read the base air temperature rise for steam units, BATRS, from Table 1.3.Calculate the air temperature rise correction factor, ATRS: ATRS = (SST-EAT)/250where SST= Saturated steam temperature
8 from Table 2 and EAT= Entering air Calcu
from Table 2 and EAT= Entering air Calculate heat transfer, Q:4.Q = 1.085 x CFM x ATRS x BATRSwhere CFM = Airflow from Table 1.5.Calculate the air temperature leaving the FASunit, LAT: LAT= EAT+ (BATRS x ATRS)6.Calculate the condensate load, CL: CL= Q/LHwhere LH = Latent Heat from Table 2. Select FAS unit without filters for to heat outside air at 12 degrees F. 1.For 7,000 CFM, choose an FAS-30 from Table 1.2.Also from table 1, BATRS = 87.9 degre
9 es F foran FAS-30.3.From Table 2, SST= 2
es F foran FAS-30.3.From Table 2, SST= 227 degrees F, so:ATRS = (227 (-12))/250 = 0.9564.Q = 1.085 x 7,000 x 87.9 x 0.956 = 638,200 Btuh5.LAT= -12 + (87.9 x 0.956) = 72.0 degrees F6.From Table 3, LH = 960, so:CL= 638,200/960 = 664.8 lb/hr.1.Select FAS Unit with or without filters to meet project make-up air requirement from Table 1.2.Read the base air temperature rise for water units, BATRW, from Table 1.3.Calculate the air temperature rise correc
10 tion factor, ATRW:ATRW = (EWT- EAT)/200g
tion factor, ATRW:ATRW = (EWT- EAT)/200given and EAT= Entering air temperature as 4.Using the given water flow rate, calculate the ratio to Base Water Flow Rate from Table 3.5.Using the ratio of step 4, look up the Air Temperature Rise correction factor due to gpm, ATRF, from Table 4.6.Calculate the Heat transfer, Q:Q = 1.085 x CFM x (BATRW x ATRW x ATRF) where CFM = Airflow from Table 1.7.Calculate the air temperature leaving the FAS unit, LAT:LAT
11 = EAT+ (BATRW x ATRW x ATRF)8.Read the B
= EAT+ (BATRW x ATRW x ATRF)8.Read the Base Water Pressure Drop, WPDB, from Table 3 for the unit selected.9.Read the Water pressure Drop correction factor due to flow, WPDF, from Table 4 using the flow ratio of Step 4.10.Calculate the water pressure drop, WPD:11.Calculate the Water temperature Drop, WTD: Select FAS unit with filters for 4,300 CFMwater to heat outside air at 0 degrees F. 1.For 4,300 CFM, choose an FAS-25 from Table 2.Also from tabl
12 e 1,BATRW = 69.2 degrees F for an FAS-25
e 1,BATRW = 69.2 degrees F for an FAS-25.3.ATRW = (210-0))/200 = 1.054.From Table 3, base water flow rate = 35 gpm. Water flow rate/base water flow rate = 42.0/35 =5.From Table 4 at Water flow rate/ base water flowrate = 1.20: ATRF = 1.02.6.Q= 1.085 x 4,300 x (69.2 x 1.05 x 1.02) = 7.LAT= 0 + (69.2 x 1.05 x 1.02) = 74.1 degrees F.8.From Table 3 for FAS-27: WPDB = 10.0 feet 9.From Table 4 at a water flow ratio of 1.20: 10.WPD = (10.0 x 1.44) = 14.4
13 ft. H20.11.WTD = 345,800/(500 x 42.0) =
ft. H20.11.WTD = 345,800/(500 x 42.0) = 16.5 degrees F. 10 Dimensions for Vertical Units C00026 939,8120,65 (4 OUTLETS)TYPE 5R AND 5F(1 OUTLET)TYPE 10R(2 OUTLETS)TYPE 8R AND 8F(2 OUTLETS)TYPE 4R AND 4F D10 D4 D5 D8 D1 D8A W1 W4 W10 W8 W5DTR TRANSITION C000650A FAS25114152129212945243914403145243914403142175035644011/1642175035644011/16574777455747774554215421542311/1686505616542311/1686505616 - - - - - - - - W5D8W8D10Notes: (1) Values shown
14 for D4, D5, D8, and D8A apply to relvol
for D4, D5, D8, and D8A apply to relvolving discharge only. To get dimension of fixed discharge, subtra g h 33 and for lar g (2) To get overall unit height including the transition and discharge, add dimensions C plus D from page 9 to dimension DTR and pp ro p riate from the above table. DIMENSIONS ( inches ) D1W1D4D8AW4D5 TYPICAL INSTALLATIONS AND CONTROLS Typical Vertical Installations C00026 Control Systems Methods of ControlThe FAS is availa
15 ble with either of two methods ofcontrol
ble with either of two methods ofcontrol: Airstream or Room with Low Limit. BothWith Airstream control, the controller is mounted oncontrol uses the Airstream controller as its low limitelectric or pneumatic versions. The standard electricactuators with Viconics controllers. The standardController SetpointsThe FAS heater is a make-up air system and, asRoom with Low Limit control, this insures that if theRoom thermostat is satisfied, the Low Limitbe
16 low the desired temperature. Without thi
low the desired temperature. Without this, or if thebring it back up. The Room with Low limit ControlSequence of OperationShutoff Featurecold outside air. There is no need for a separatemotorized shutoff damper.Additional Control Options Freezestat Uses an averaging sensing Fan Cut-Off Thermostat - Uses a single Discharge Dampers Can be installed on the CONTROLS Control Arrangements C00026 C000608 15 Steam and Hot Water Systems C00026