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Biostatistics Case Studies - PowerPoint Presentation

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Biostatistics Case Studies - PPT Presentation

2016 Youngju Pak PhD Biostatistician ypaklabiomedorg Session 2 Understanding Equivalence and Noninferiority testing Testing Inequality vs Equality Testing Inequality Ha meantreatment mean control 0 ID: 545526

study inferiority fixed inferior inferiority study inferior fixed iop power treatment test margin equivalence superiority difference typical assumed change true population values

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Slide1

Biostatistics Case Studies 2016

Youngju Pak, PhD.

Biostatisticianypak@labiomed.org

Session 2Understanding Equivalence and Noninferiority testingSlide2

Testing Inequality v.s. Equality

Testing InequalityHa: | mean(treatment ) - mean (control ) | ≠ 0H0: | mean(treatment ) - mean (control ) | = 0

Testing equivalence Ha : δ 1< mean(

trt 1) – mean (trt2) < δ 2H0 : mean(trt 1) – mean (trt2) ≤

δ

1 or mean(trt 1) – mean (trt2) ≥ δ 2, δ 1 & δ 2 is called “Equivalence Margin

Testing

Noninferority

, noninfiority ity marginSlide3

Case Study

Ophthalmology 2006; 113:70-76

.Slide4

AbstractSlide5

Primary Outcome and Study Size

Study Size - Page 72 bottom of column 1:

Primary Outcome - Page 72 middle of column 1

:

Needs Consensus

PI’s GambleSlide6

Non-Inferiority Study

Usually a new treatment or regimen is compared with an accepted treatment or regimen or standard of care.

The new treatment is assumed inferior to the standard and the study is designed to show overwhelming evidence that it is at least nearly as good, i.e., non- inferior. It usually has other advantages, e.g., oral vs. inj. A negative inferiority study fails to detect inferiority, but does not necessarily give evidence for non-inferiority.

The accepted treatment is usually known to be efficacious already, but an added placebo group may also be used. Slide7

How to determine Sample Size? For IOP study, we have

Ha

: mean IOP change uf – mean IOP change f < 1.5

H0: mean IOP change uf – mean IOP change f ≥ 1.5 thus, we are only interested in the upper limit of the difference

 Non-inferiority  one-sided T-test

Thus we reject the H

0 if Signal/ Noise < some clinical value.But N for a non-inferiority test require more complicated parameters such as the non-centrality parameter of the t-distribution (a Two One Sided T-test is usually used for the equivalence test ).Slide8

Let’s run a softwarefrom www.stat.uiowa.edu/~rlenth/Power

Information you will need Equivalence Margin

Non-Inferiority Margin(NIM) =1.5 for the IOP studyAssumed mean difference in change of IOP between two groups -> usually zero difference assumed but it is assumed 0.5 for the IOP studySD of changes of IOP = 3.5α (usually set to 2.5%) since the confidence level of the confidence interval is (100-2 x α) %Slide9

Sample size for IOP studySlide10

Three dimensional power curve for a non-inferiority testSlide11

How do we determine if the fixed method is non-inferior to the unfixed method?

Regardless of study aim – to prove treatments equivalent or to prove them different - inference can be based on:

Primary Outcome: IOP reduction D

= Duf – Df , where Df

= mean IOP reduction with fixed therapy

Typical superiority/inferiority study:

Compare to 0.Non-inferiority study: Compare to δ2, a pre-specified margin of equivalence (1.5 here).= 95% CI for D(=

Duf – Df ) = “true (population) values for D”Slide12

Typical Analysis: Inferiority or Superiority

H0

: Duf – Df = 0

H1: Duf – Df ≠ 0Aim: H1 → therapies differ

α

= 0.05 & N=2

•194 Power = 80% when Δ=1, SD=3.5

Fixed is inferior

= 95% CI for

D = “true (population) values for D”

Fixed is superior

0

0

D

u

D

f

[Not used in this paper]

0

No difference detected

D

u

D

f

D

u

D

fSlide13

Typical Analysis: Inferiority Only

H0

: Du – Df ≤ 0

H1: Du – Df > 0Aim: H1 → fixed is inferior

α

= 0.025 & N=2

•194 Power = 80% for when Δ=1, SD=3.5Fixed is inferior

= 95% CI for

D

u

D

f

= “true (population) values for D”

0

0

D

uf

Df

[Not used in this paper]

0

Inferiority not detected

D

uf

D

f

D

uf

D

f

(

α

= 0.05

N=2

•153

)Slide14

Non-Inferiority

H0:

Du – Df ≥ 1.5

H1: Du – Df < 1.5Aim: H1 → fixed is non-inferior

α

= 0.025 & N=2

•194 Power = 80% for When Δ= 0.5, NIM=1.5

Fixed is non-inferior

= 95% CI for

D

u

D

f

= “true (population) values for D”

0

0

D

uf

D

f

[As in this paper]

0

Non-Inferiority not detected

D

uf

D

f

D

uf

D

f

1.5

1.5

Fixed is

inferior

1.5Slide15

Inferiority and Non-Inferiority

Fixed is non-inferior

= 95% CI for

D

u

– Df = “true (population) values for D”

0

0

0

Neither is detected

D

uf

D

f

1.5

1.5

Fixed is inferior

0

1.5

Fixed is “non-clinically” inferior

D^

uf

=

9.0

D^

f

= 8.7

D^

= 0.3 95% CI = -0.1 to 0.7

Observed Results:

Fixed is non-inferior

0

1.5

1.5Slide16

Conclusions: General

“Negligibly inferior” would be a better term than non- inferior.

All inference can be based on confidence intervals. Pre-specify the comparisons to be made. Cannot test for both non-inferiority and superiority. Power for only one or for multiple comparisons, e.g., non-inferiority and inferiority. Power can be different for different comparisons. Very careful consideration must be given to choice of margin of equivalence (1.5 here). You can be risky and gamble on what expected differences will be (0.5 here), but the study is worthless if others in the field would find your margin too large. Slide17

FDA Guidelines : http://www.fda.gov/downloads/drugs/guidancecomplianceregulatoryinformation/guidances/ucm202140.pdf

Where,

M1= Full effect of the active control compare with the test drug

M

2

= NI MarginSlide18

Self-Quiz

Give an example in your specialty area for a superiority /inferiority study. Now modify it to an equivalence study. Now modify it to a non-inferiority study.

T or F: The main point about non-inferiority studies is that we are asking whether a treatment is as good or better vs. worse than another treatment, so it uses a one-sided test.Power for a typical superiority test is the likelihood that you will declare treatment differences (p<0.05) if treatments really differ by some magnitude Δ. Explain what power means for a non-inferiority study.

T or F: Last-value-carried-forward is a good way to handle drop-outs in a non-inferiority study. Explain. continuedSlide19

Self-Quiz

T or F: In a non-inferiority study, you should first test for non-inferiority with a confidence interval, and then use a t-test to test for superiority, but only if non-inferiority was established at the first step.

What is the meaning of the equivalence margin, and how do you determine it?

continuedSlide20

Self-Quiz

Suppose the primary outcome for a study is a serum inflammatory marker. If it’s assay is poor (low reproducibility), then it is more difficult to find treatment

differences in a typical superiority/inferiority study than for a better assay, due to this noise. Would it be easier or more difficult to find non-inferiority with this assay, compared to a better assay?Does the assumed treatment difference (0.5 here) for power calculations have the same meaning as the difference used for power calculations in a typical superiority/inferiority study?