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Turning Operations Turning Operations

Turning Operations - PowerPoint Presentation

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Turning Operations - PPT Presentation

L a t h e Turning Operations Machine Tool LATHE Job workpiece rotary motion Tool linear motions Mother of Machine Tools Cylindrical and flat surfaces Some Typical Lathe Jobs ID: 388318

operations lathe tool turning lathe operations turning tool time cutting diameter length min workpiece feed machining speed minute facing

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Slide1

Turning Operations

L a t h eSlide2

Turning Operations

Machine Tool – LATHE Job (workpiece) – rotary motionTool – linear motions

Mother of Machine Tools “

Cylindrical and flat surfacesSlide3

Some Typical Lathe Jobs

Turning/Drilling/Grooving/Threading/Knurling/Facing...Slide4

The LatheSlide5

The Lathe

Bed

Head Stock

Tail Stock

Carriage

Feed/Lead ScrewSlide6

Main Parts

BedHeadstockFeed and lead screwsCarriageTailstock

6Slide7

Lathe Bed

Heavy, rugged castingMade to support working parts of latheOn top section are machined waysGuide and align major parts of lathe

7Slide8

Lathe Bed

8Slide9

Headstock

Clamped on left-hand end of bedHeadstock spindleHollow cylindrical shaft supported by bearingsProvides drive through gears to work-holding devices

Live center, faceplate, or chuck fitted to spindle nose to hold and drive work

Driven by stepped pulley or transmission gears

Feed reverse lever

Reverses rotation of feed rod and lead screw

9Slide10

Headstock

10Slide11

Headstock

11

Back Gear arrangement

Headstock belt driveSlide12

Quick-Change Gearbox

Contains number of different-size gearsProvides feed rod and lead-screw with various speeds for turning and thread-cutting operationsFeed rod advances carriage when automatic feed lever engagedLead screw advances the carriage for thread-cutting operations when split-nut lever engaged

12Slide13

Quick-Change Gearbox

13Slide14

Carriage

Used to move cutting tool along lathe bedConsists of three main partsSaddleH-shaped casting mounted on top of lathe ways, provides means of mounting cross-slide and apronCross-slide

Apron

14Slide15

15

Carriage

< Saddle

< ApronSlide16

Carriage

16Slide17

Carriage

17Slide18

18

Apron

The apron attached to the front of the carriage, holds most of the control levers. These include the levers, which engage and reverse the feed lengthwise (Z-axis) or crosswise (X-axis) and the lever which engages the threading gears.

The apron is fastened to the saddle, houses the gears and mechanisms required to move the carriage and cross-slide automatically.

The apron hand wheel can be turned manually to move the carriage along the Lathe bed. This hand wheel is connected to a gear that meshes in a rack fastened to the Lathe bed.

The automatic feed lever engages a clutch that provides the automatic feed to the carriageSlide19

Cross-slide

Mounted on top of saddleProvides manual or automatic cross movement for cutting toolCompound rest (fitted on top of cross-slide)

Used to support cutting tool

Swiveled to any angle for taper-turning

Has graduated collar that ensure accurate cutting-tool settings (.001 in.) (also cross-slide)

19Slide20

Cross-slide

20Slide21

21Slide22

Top Slide (Compound slide)

Fitted to top of Cross slideCarries tool post and cutting toolCan rotate to any angleIs used to turn tapers

22Slide23

Tailstock

Upper and lower tailstock castingsAdjusted for taper or parallel turning by two screws set in baseTailstock clamp locks tailstock in any position along bed of latheTailstock spindle has internal taper to receive dead center

Provides support for right-hand end of work

23Slide24

24

Tailstock

Supports long

workpieces

when machining.

60 degree rotating center point.

Drill Chuck

Turn the tailstock handwheel to advance the ram.Slide25

Tailstock

25Slide26

Lead Screw and Feed Rod

26

< Lead

Screw

< Feed RodSlide27

Types of Lathes

Engine LatheSpeed LatheBench LatheTool Room LatheSpecial Purpose Lathe

Gap Bed Lathe

…Slide28

Size of Lathe

Workpiece Length

SwingSlide29

Size of Lathe ..

Example: 300 - 1500 LatheMaximum Diameter of Workpiece that can be machined = SWING

(= 300 mm)

Maximum Length of Workpiece that can be held between Centers (=1500 mm)Slide30

Workholding Devices

Equipment used to holdWorkpiece – fixturesTool - jigs

Securely

HOLD

or

Support

while machiningSlide31

Chucks

Three jaw Four Jaw

Workholding Devices

..Slide32

32

ChucksUsed extensively for holding work for lathe machining operations

Work large or unusual shape

Most commonly used lathe chucks

Three-jaw universal

Four-jaw independent

Collet chuckSlide33

33

Three-jaw Universal Chuck

Holds round and hexagonal work

Grasps work quickly and accurate within few thousandths/inch

Three jaws move simultaneously when

adjusted by chuck wrench

Caused by scroll plate into which all three jaws fit

Two sets of jaw: outside chucking and inside chuckingSlide34

34

Three-jaw Universal ChuckSlide35

35

Three jaw self centering chuckSlide36

36

Four-Jaw Independent Chuck

Used to hold round, square, hexagonal, and irregularly shaped workpieces

Has four jaws

Each can be adjusted independently by chuck wrench

Jaws can be reversed to hold work by inside diameterSlide37

37

Four-Jaw Independent ChucksSlide38

Four-Jaw Independent Chucks

38

With the four jaw chuck, each jaw can be adjusted independently by rotation of the radially mounted threaded screws.

Although accurate mounting of a workpiece can be time consuming, a four-jaw chuck is often necessary for non-cylindrical workpieces. Slide39

Mandrels

Workpiece (job) with a hole

Workholding Devices

..Slide40

Mandrels

40

Holds internally machined workpiece between centers so further machining operations are concentric with bore

Several types, but most common

Plain mandrel

Expanding mandrel

Gang mandrel

Stub mandrelSlide41

41

Mandrels to Hold Workpieces for Turning

Figure 23.8 Various types of mandrels to hold workpieces for turning. These mandrels usually are mounted between centers on a lathe. Note that in (a), both the cylindrical and the end faces of the workpiece can be machined, whereas in (b) and (c), only the cylindrical surfaces can be machined.Slide42

Rests

Workholding

Devices

..

Steady Rest Follower RestSlide43

43

Steadyrest

Used to support long work held in chuck or between lathe centers

Prevent springing

Located on and aligned by ways of the lathe

Positioned at any point along lathe bed

Three jaws tipped with plastic, bronze or rollers may be adjusted to support any work diameter with steadyrest capacitySlide44

44

SteadyrestSlide45

45

Follower Rest

Mounted on saddle

Travels with carriage to prevent work from springing up and away from cutting tool

Cutting tool generally positioned just ahead of follower rest

Provide smooth bearing surface for two jaws of follower restSlide46

46

Follower RestSlide47

Operating/Cutting Conditions

Cutting Speed vFeed f

Depth of Cut

dSlide48

Operating ConditionsSlide49

Cutting Speed

The Peripheral Speed of Workpiece past the Cutting Tool =Cutting Speed

Operating Conditions

..

D

– Diameter (mm)

N

– Revolutions per Minute (rpm)Slide50

Feed

f – the distance the tool advances for every rotation of workpiece (mm/rev)

Operating Conditions

..Slide51

Depth of Cut

perpendicular distance between machined surface and uncut surface of the Workpiece d = (D1 –

D

2

)/2 (mm)

Operating Conditions

..Slide52

3 Operating ConditionsSlide53

Selection of ..

Workpiece Material Tool MaterialTool signature Surface FinishAccuracy

Capability of Machine Tool

Operating Conditions

..Slide54

Material Removal Rate

MRRVolume of material removed in one revolution

MRR =

D

d

f

mm

3

Job makes

N

revolutions/min

MRR

=  D d

f

N

(mm

3

/min)

In terms of

v

MRR is given by

MRR

= 1000

v d f

(mm

3

/min)

Operations on Lathe

..Slide55

MRR

dimensional consistency by substituting the units

Operations on Lathe

..

MRR

:

D

d

f

N

(mm)(mm)(mm/rev)(rev/min)

= mm

3

/minSlide56

Operations on Lathe

TurningFacingknurling

Grooving

Parting

Chamfering

Taper turning

Drilling

Threading

Operations on Lathe

..Slide57

Turning

Cylindrical job

Operations on Lathe

..Slide58

Turning ..

Cylindrical job

Operations on Lathe

..Slide59

Turning ..

Excess Material is removed to reduce DiameterCutting Tool: Turning Tool

a

depth of cut

of 1 mm will reduce diameter by 2 mm

Operations on Lathe

..Slide60

Facing

Flat Surface/Reduce length

Operations on Lathe

..Slide61

Facing ..

machine end of job  Flat surfaceor to Reduce Length of Job

Turning Tool

Feed

: in direction perpendicular to workpiece axis

Length of Tool Travel = radius of workpiece

Depth of Cut

: in direction parallel to workpiece axis

Operations on Lathe

..Slide62

Facing ..

Operations on Lathe

..Slide63

Eccentric Turning

Operations on Lathe

..Slide64

Knurling

Produce rough textured surfaceFor Decorative and/or Functional Purpose

Knurling Tool

A

Forming

Process

MRR

~0

Operations on Lathe

..Slide65

Knurling

Operations on Lathe

..Slide66

Knurling ..

Operations on Lathe

..Slide67

Grooving

Produces a Groove on workpieceShape of tool  shape of groove

Carried out using

Grooving Tool

 A

form tool

Also called

Form Turning

Operations on Lathe

..Slide68

Grooving ..

Operations on Lathe

..Slide69

Parting

Cutting workpiece into TwoSimilar to groovingParting ToolHogging – tool rides over – at slow feedCoolant use

Operations on Lathe

..Slide70

Parting ..

Operations on Lathe

..Slide71

Chamfering

Operations on Lathe

..Slide72

Chamfering

Beveling sharp machined edgesSimilar to form turningChamfering tool – 45

°

To

Avoid Sharp Edges

Make Assembly Easier

Improve Aesthetics

Operations on Lathe

..Slide73

Taper Turning

Taper:

Operations on Lathe

..Slide74

Taper Turning..

Methods

Form Tool

Swiveling Compound Rest

Taper Turning Attachment

Simultaneous Longitudinal and Cross Feeds

Operations on Lathe

..

ConicitySlide75

Taper Turning

..By Form Tool

Operations on Lathe

..Slide76

Taper Turning ,,

By Compound Rest

Operations on Lathe

..Slide77

Drilling

Drill – cutting tool – held in TS – feed from TS

Operations on Lathe

..Slide78

Process Sequence

How to make job from raw material 45 long x 30 dia.?

Operations on Lathe

..

Steps

:

Operations

Sequence

Tools

Process Slide79

Process Sequence ..

Possible Sequences

TURNING - FACING - KNURLING

TURNING - KNURLING - FACING

FACING - TURNING - KNURLING

FACING - KNURLING - TURNING

KNURLING - FACING - TURNING

KNURLING - TURNING – FACING

What is an Optimal Sequence?

Operations on Lathe

..

X

X

X

XSlide80

Machining Time

Turning TimeJob length Lj mmFeed f mm/rev

Job speed

N

rpmf N

mm/min

Operations on Lathe

..Slide81

Manufacturing Time

Manufacturing Time = Machining Time + Setup Time

+ Moving Time

+ Waiting Time

Operations on Lathe

..Slide82

Example

A mild steel rod having 50 mm diameter and 500 mm length is to be turned on a lathe. Determine the machining time to reduce the rod to 45 mm in one pass when cutting speed is 30 m/min and a feed of 0.7 mm/rev is used. Slide83

Example

calculate the required spindle speed as: N = 191 rpm

Given data:

D

= 50 mm,

L

j

= 500 mm

v

= 30 m/min,

f

= 0.7 mm/rev

Substituting the values of

v

and

D

inSlide84

Example

Can a machine has speed of 191 rpm? Machining time:

t

= 500 / (0.7

191)

= 3.74 minutesSlide85

Example

Determine the angle at which the compound rest would be swiveled for cutting a taper on a workpiece having a length of 150 mm and outside diameter 80 mm. The smallest diameter on the tapered end of the rod should be 50 mm and the required length of the tapered portion is 80 mm. Slide86

Example

Given data: D1 = 80 mm, D2 = 50 mm, Lj = 80 mm (with usual notations) tan

=

(80-50) / 2

80

or

= 10.620

The compound rest should be swiveled at 10.62

oSlide87

Example

A 150 mm long 12 mm diameter stainless steel rod is to be reduced in diameter to 10 mm by turning on a lathe in one pass. The spindle rotates at 500 rpm, and the tool is traveling at an axial speed of 200 mm/min. Calculate the cutting speed, material removal rate and the time required for machining the steel rod.Slide88

Example

Given data: Lj = 150 mm, D1 = 12 mm, D2 = 10 mm, N = 500 rpm

Using Equation (1)

v =



12

500 / 1000

= 18.85 m/min.

depth of cut =

d

= (12 – 10)/2 = 1 mmSlide89

Example

feed rate = 200 mm/min, we get the feed f in mm/rev by dividing feed rate by spindle rpm. That is f

= 200/500 = 0.4 mm/rev

From Equation (4),

MRR

= 3.142

12

0.4

1

500 = 7538.4 mm3/min

from Equation (8),

t

= 150/(0.4

500) = 0.75 min.Slide90

Example

Calculate the time required to machine a workpiece 170 mm long, 60 mm diameter to 165 mm long 50 mm diameter. The workpiece rotates at 440 rpm, feed is 0.3 mm/rev and maximum depth of cut is 2 mm. Assume total approach and overtravel distance as 5 mm for turning operation.Slide91

Example

Given data: Lj = 170 mm, D1 = 60 mm, D2 = 50 mm, N = 440 rpm,

f

= 0.3 mm/rev,

d= 2 mm,

How to calculate the machining time when there is more than one operation? Slide92

Example

Time for Turning:Total length of tool travel = job length + length of approach and overtravel

L

= 170 + 5 = 175 mm

Required depth to be cut = (60 – 50)/2 = 5 mm

Since maximum depth of cut is 2 mm, 5 mm cannot be cut in one pass. Therefore, we calculate number of cuts or passes required.

Number of cuts required = 5/2 = 2.5 or 3 (since cuts cannot be a fraction)

Machining time for one cut =

L

/ (

f

N

)

Total turning time = [

L

/ (

fN)]  Number of cuts

= [175/(0.3440)]  3= 3.97 min.Slide93

Example

Time for facing: Now, the diameter of the job is reduced to 50 mm. Recall that in case of facing operations, length of tool travel is equal to half the diameter of the job. That is,

l

= 25 mm. Substituting in equation 8, we get

t

= 25/(0.3

440)

= 0.18 min.Slide94

Example

Total time: Total time for machining = Time for Turning + Time for Facing = 3.97 + 0.18

= 4.15 min.

The reader should find out the total machining time if first facing is done.Slide95

Example

From a raw material of 100 mm length and 10 mm diameter, a component having length 100 mm and diameter 8 mm is to be produced using a cutting speed of 31.41 m/min and a feed rate of 0.7 mm/revolution. How many times we have to resharpen or regrind, if 1000 work-pieces are to be produced. In the taylor’s expression use constants as

n

= 1.2 and

C = 180 Slide96

Example

Given D =10 mm , N = 1000 rpm, v = 31.41 m/minute

From Taylor’s tool life expression, we have

vT n

= C

Substituting the values we get,

(31.40)(

T

)1.2 = 180

or

T

= 4.28 minSlide97

Example

Machining time/piece = L / (fN

)

= 100 / (0.7

1000) = 0.142 minute.

Machining time for 1000 work-pieces = 1000

0.142 = 142.86 min

Number of resharpenings = 142.86/ 4.28

= 33.37 or 33 resharpenings Slide98

Example

6: While turning a carbon steel cylinder bar of length 3 m and diameter 0.2 m at a feed rate of 0.5 mm/revolution with an HSS tool, one of the two available cutting speeds is to be selected. These two cutting speeds are 100 m/min and 57 m/min. The tool life corresponding to the speed of 100 m/min is known to be 16 minutes with

n

=0.5. The cost of machining time, setup time and unproductive time together is Rs.1/sec. The cost of one tool re-sharpening is Rs.20.

Which of the above two cutting speeds should be selected from the point of view of the total cost of producing this part? Prove your argument.Slide99

Example

Given T1 = 16 minute, v1 = 100 m/minute,

v

2 = 57 m/minute,

D = 200mm, l = 300 mm, f

= 0.5 mm/rev

Consider Speed of 100 m/minute

N

1 = (1000

v

) / (

 D

) = (1000100) / (200) = 159.2 rpm t1 =

l / (fN) = 3000 / (0.5 159.2) = 37.7 minute Tool life corresponding to speed of 100 m/minute is 16 minute.

Number of resharpening required = 37.7 / 16 = 2.35

or number of resharpenings = 2Slide100

Example

Total cost = Machining cost + Cost of resharpening  Number of resharpening = 37.760

1+ 20

2 = Rs.2302Slide101

Example

Consider Speed of 57 m/minute

Using Taylor’s expression

T

2 = T1

(

v

1 /

v

2)2 with usual notations

= 16

(100/57)2 = 49 minute

Repeating the same procedure we get

t

2 = 66 minute, number of

reshparpening

=1 and total cost = Rs. 3980. The cost is less when speed = 100 m/minute. Hence, select 100 m/minute. Slide102

Example

Write the process sequence to be used for manufacturing the component

from raw material of 175 mm length

and 60 mm diameter Slide103

ExampleSlide104

Example

To write the process sequence, first list the operations to be performed. The raw material is having size of 175 mm length and 60 mm diameter. The component shown in Figure 5.23 is having major diameter of 50 mm, step diameter of 40 mm, groove of 20 mm and threading for a length of 50 mm. The total length of job is 160 mm. Hence, the list of operations to be carried out on the job are turning, facing, thread cutting, grooving and step turning Slide105

Example

A possible sequence for producing the component would be:Turning (reducing completely to 50 mm)Facing (to reduce the length to 160 mm)Step turning (reducing from 50 mm to 40 mm)

Thread cutting.

Grooving