/
Unit 5: Thermodynamics & Unit 5: Thermodynamics &

Unit 5: Thermodynamics & - PowerPoint Presentation

matterguy
matterguy . @matterguy
Follow
342 views
Uploaded On 2020-06-22

Unit 5: Thermodynamics & - PPT Presentation

Thermochemistry Ms DiOrio Rm 109 Contents Heat Heat and Temperature Law of Conservation of Energy Work and Internal Energy EndothermicExothermic Reactions and Potential Energy Diagrams Calorimetry Heat Capacity and Specific Heat ID: 783195

heat energy reaction system energy heat system reaction entropy change temperature law process enthalpy kinetic standard work transfer thermal

Share:

Link:

Embed:

Download Presentation from below link

Download The PPT/PDF document "Unit 5: Thermodynamics &" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

Unit 5:Thermodynamics &Thermochemistry

Ms. DiOrio

Rm 109

Slide2

Contents

Heat

Heat and Temperature

Law of Conservation of Energy, Work, and Internal Energy

Endothermic/Exothermic Reactions and Potential Energy DiagramsCalorimetry, Heat Capacity, and Specific HeatBond EnergiesHeat of Reaction and Standard Enthalpy of FormationHess’s Law

Thermodynamics

Laws of Thermodynamics

Spontaneous Processes and Entropy

Entropy and Enthalpy

Free Energy

Nonspontaneous Processes

Kinetic vs. Thermodynamic Control

Slide3

Heat and Temperature

Slide4

Recall the Kinetic Molecular Theory

All of the molecules in a sample are in motion.

Temperature is a measure of the average kinetic energy of atoms and molecules.

Temperature is a property

The Kelvin temperature of a sample of matter is proportional to the average kinetic energy.As temperature approaches 0 K, the average kinetic energy of a system approaches near zero.

Slide5

The Maxwell-Boltzmann Distribution

At a specific temperature, we can plot the distribution of molecular velocities at any given time.

The peak of this curve is the most probable speed for a molecule at that temperature

Slide6

The Maxwell-Boltzmann Distribution

Kinetic energies become greater (more disperse) as

temperature increases

Slide7

Activation Energy

At a higher temperature, it is more probable to have a molecule that will meet the activation energy requirement for

a reaction to occur

Slide8

HeatTwo systems with different temperatures that are in thermal contact will exchange energy

The quantity of thermal energy transferred from one system to another is called

heat

.

The process of kinetic energy transfer at the particular scale is referred to as heat transferThe spontaneous direction of the transfer is always from a hot to a cold body.

Slide9

Heat Transfer On average, molecules in the warmer body have more kinetic energy than molecules in the cooler body (we saw this in the Maxwell Boltzmann distribution)

Collisions of molecules that are in thermal contact transfer energy

Scientists describe this process as:

“heat transfer”

“heat exchange”“transfer of energy as heat”

Slide10

Heat Transfer Heating a system increases the energy of the system, and cooling a system decreases the energy.

Example:

A liter of water at 50

o

C has more energy than a liter of water at 25oC.

Slide11

Thermal Equilibrium Eventually, thermal equilibrium is reached as the molecular collisions continue.

The average kinetic energy (and therefore the temperatures) of both substances is the same at thermal equilibrium.

Slide12

A Note on HeatHeat is

NOT

a substance or a property.

It makes no sense that an object contains a certain amount of “heat”

“Heat exchange” or “transfer of energy as heat” refers to the process in which energy is transferred from a hot to a cold body in thermal contact

Slide13

Law of conservation of energy, work, and internal energy

Slide14

Energy Energy is defined as the capacity to do work or to produce heat.

Energy is neither created nor destroyed, but only transformed from one form to another

Energy is transferred between systems either through heat transfer or through one system doing work on the other system

Slide15

Conservation of Energy When two systems are in contact with each other and are otherwise isolated, the energy that comes out of one system is equal to the energy that goes into the other system

The combined energy of the two systems remains fixed

Slide16

First Law of Thermodynamics

Thermodynamic quantities are vectors, consisting of a number to indicate magnitude and a sign to indicate direction or flow.

The energy transferred from one system is equal in magnitude to energy transferred to the other system.

 

heat

work

Slide17

Forms of Energy Transfer

Heat

Thermal energy transfer

Work

Work is defined by other scientific frameworks (Newtonian Mechanics or electromagnetism) as force acting over a distance For AP Chem, calculations are limited to those associated with changes in volume of a gas.

Slide18

System vs. Surroundings

In order to describe energy changes, we must define the system and the surroundings.

The system is where the reaction occurs.

Everything else is the surroundings.

Surroundings

System

Slide19

Signs of Heat and Work

Heat

+

Heat absorbed

(endothermic)

-

Heat released

(exothermic)

Work

+

Work done on the system

-

Work done by the system

Slide20

Work by Changing Volume of a Gas

Pushing the piston down compresses the gas, doing work

on

the system

Work is positiveAn expanding gas does work by pushing up the pistonWork is negative

Slide21

Energy Transfer

If a system transfers energy to another system, its energy must decrease. Likewise, if energy is transferred into a system, its energy must increase.

Chemical systems undergo three main processes that change their energy:

Heating/Cooling

Phase Transitions Chemical Reactions

Slide22

Endo/Exothermic Reactions & Potential Energy Diagrams

Slide23

Endo vs Exothermic Macroscopic observations of energy changes are made possible by measuring temperature changes

Net changes in energy for a chemical reaction can be endothermic or exothermic

Endothermic

Exothermic

Heat

required

released

Sign of ∆H

+

-

Slide24

Graphical Representation: Endothermic

Slide25

Graphical Representation: Exothermic

Slide26

Enthalpy

The enthalpy change of reaction gives the amount of energy released (for negative values) or absorbed (for positive values) by a chemical reaction at constant pressure.

 

Internal energy

of the system

Pressure

Change in volume

Work

Slide27

Enthalpy Change

At constant volume, the change in enthalpy (∆H) of the system is equal to the energy flow as heat.

 

Slide28

Calorimetry, heat capacity, and specific heat

Slide29

Phase Change Energy

Energy must be transferred to a system to cause a substance to melt (or boil).

The energy of the system therefore increases as the system undergoes a solid-to-liquid (or liquid-to-gas) phase transition. Likewise, a system releases energy when it freezes (or condenses).

The energy of the system decreases as the system undergoes a liquid-to-solid (or gas-to-liquid) phase transition.

The temperature of a pure substance remains constant during a phase change.

Slide30

Phase Change Energy

Molar Heat of Vaporization:

the amount of energy needed to vaporize one mole of a pure substance

The energy released in condensation has an equal magnitude Molar Heat of Fusion: the amount of energy absorbed when one mole of a pure solid melts or changes from the solid to liquid state The energy released when the liquid solidifies has an equal magnitude

Slide31

Phase Change Energy The heat of vaporization is always greater than the corresponding heat of fusion

It takes much more energy to break IMFS to become a gas than those to become liquid

 

Slide32

Heat Capacity vs. Specific HeatThe transfer of a given amount of thermal energy will not produce the same temperature change in equal masses of matter with differing heat capacities.

Molar Heat Capacity:

the amount of energy needed to heat

1 mol of substance by 1∘C (units = J/oC  mol) Specific Heat Capacity: the amount of energy needed to heat 1 g of substance by 1∘C (units = J/oC  g)

Slide33

Calorimetry

Calorimetry is an experimental technique that is used to determine the heat exchange/transferred into a chemical system.

Experimental Set-Up:

A chemical system is put in thermal contact with a heat bath.

The heat bath is a substance, such as water, heat capacity has been well established by previous experiments. A process is initiated in the chemical system, and the change in temperature of the heat bath is determined

Slide34

Coffee Cup Calorimetry

Slide35

Calorimetry Because the heat capacity of the heat bath is known, the observed change in temperature can be used to determine the amount of energy exchanged between the system and the heat bath.

The energy exchanged between the system and the heat bath is equal in magnitude to the change in energy of the system.

Slide36

Calorimetry If the heat bath decreases in temperature, and therefore energy, the energy of the system increased by this amount.

Calorimetry may be used to determine heat capacities, enthalpies of vaporization, enthalpies of fusion, and enthalpies of reactions

 

Slide37

Other Types of Calorimetry

In this course, we will only perform constant pressure calorimetry.

Bomb calorimetry is a different type of calorimetry that is performed under constant volume.

Slide38

Bond Energies

Slide39

Breaking vs. Making Bonds Breaking bonds requires energy (endothermic), and making bonds releases energy (exothermic)

Slide40

Bond Energy Bond making and bond breaking are opposing processes that have the same magnitude of energy associated with them.

Convention is important!

Bond energy

is defined as the energy required to break a bond.

Slide41

Heat of Reaction and Standard Enthalpy of Formation

Slide42

Enthalpy vs. Internal Energy

For the purposes of thermodynamic analysis in AP Chemistry,

enthalpy

and

internal energy are not distinguished.

Slide43

Energy Changes During Reactions

During a chemical reaction, bonds are broken and/or formed to change the potential energy of the

reaction system

The net energy change during a reaction is the sum of the energy required to break the bonds in the reactant molecules and the energy released in forming the bonds of the product molecules.

The net change is positive for endothermic and negative for exothermic

Slide44

Bond Energies The average energy required to break all of the bonds in the reactant molecules can be estimated by adding up the average bond energies for all the bonds in the reactant molecules.

Likewise, the energy released in forming bonds is estimated for the product molecules.

If the energy required is greater than the energy release, then the reaction is endothermic and vice versa

Slide45

Heat of Reaction (

)

 

For any given reaction, the enthalpy of the reaction can be calculated using:

 

 

Slide46

Example

Calculate the heat of reaction for the following:

CH

4

(g) + 4Cl2(g)  CCl4(g) + 4HCl(g)

Type of BondBond Energy (kJ/mol)

C-H

413

Cl-Cl

243

C-Cl

339

H-Cl

432

 

 

 

 

Slide47

Standard Enthalpy of Formation (

)

 

The

Standard Enthalpy of Formation

is the change in enthalpy that accompanies the formation of one mole of a compound from its elements with all substances in their standard states.

The degree symbol on a thermodynamic function indicated that the process is carried out under standard conditions

Units: always given per mole of product with the product in the standard state (kJ/mol)

Slide48

Conventions for Standard State Compounds

Gaseous substance is at a pressure of exactly 1 atm

Pure liquid or solid

In solution, concentration is exactly 1 M

Elements Form in which element exists at 1 atm and 25oC Could be solid, liquid, or gas depending on element

Slide49

Finding

 

Over several years, scientists have run formation reactions over and over again to determine the

for specific compounds.

These values are now consolidated in reference tables for us to look up.

for an element in its standard state is zero!

 

Slide50

Calculating

 

The enthalpy change for a given reaction can be calculated by subtracting the enthalpies of formation of the reactants from the enthalpies of formation of the products.

 

The magnitude of

H is directly proportional to the quantities of reactant and products in a reaction. If the coefficients in a balanced reaction are multiplied by an integer, the value of

H is multiplied by the same integer.

Slide51

Example

Calculate

for the following:

2NO(g) + O

2(g)  2NO

2(g)

 

Compound

(kJ/mol)

NO(g)

90.25

O

2

(g)

0

NO

2

(g)

33.18

Compound

NO(g)

90.25

O

2

(g)

0

NO

2

(g)

33.18

 

 

 

 

Slide52

Hess’s Law

Slide53

Hess’s Law Going from a particular set of reactants to a particular set of products, the change in enthalpy is the same whether the reaction takes place in one step or a series of steps

Overall heat of reaction is the sum of enthalpy for each step

 

Slide54

Hess’s Law

Slide55

Rules with Hess’s Law If a reaction is reversed, the sign of

H is also reversed

The magnitude of

H is directly proportional to the quantities of reactant and products in a reaction. If the coefficients in a balanced reaction are multiplied by an integer, the value of H is multiplied by the same integer.

Slide56

Hess’s Law Rules Practice

Original

Reaction

Original

Δ

HNew Reaction

New

Δ

H

-393.5 kJ

+1185 kJ

+91.8 kJ

-1299.5 kJ

Original

Reaction

Original

Δ

H

New

Reaction

New

Δ

H

-393.5 kJ

+1185 kJ

+91.8 kJ

-1299.5 kJ

+393.5 kJ

+2370 kJ

+45.9 kJ

+2599 kJ

Slide57

Example

Given that:

C(s, graphite) + O

2

 CO2 Ho = -393.5 kJ/molCO2  C(s, diamond) + O2 Ho

= +395.4 kJ/molCalculate the standard enthalpy of reaction for the following:C(s, graphite)

 C(s, diamond)

C(s, graphite) + O

2

 CO

2

H

o

= -393.5 kJ

CO

2

 C(s, diamond) + O

2

H

o

= +395.4 kJ

+ ______________________________________________________

C(s, graphite)

 C(s, diamond)

H

o

rxn

= +1.9 kJ

Slide58

+ _____________________________________________

C(s) + O

2

(g)

 CO2(g) Ho = -393.5 kJ/mol2S(s) + 2O2(g)  2SO2(g) Ho = 2(-296.8 kJ/mol) CS

2(l)

C(s) + 2S(s)

H

o

= -1(+87.9 kJ/mol)

Example

Given that:

C(s) + O

2

(g)

 CO

2

(g)

H

o

= -393.5 kJ/mol

S(s) + O

2

(g)

 SO

2

(g)

H

o

= -296.8 kJ/mol

C(s) + 2S(s)

 CS

2

(l)

H

o

= +87.9 kJ/mol

Calculate the standard enthalpy of reaction for the following:

CS

2

(l) + 3O

2

(g)

 CO

2

(g) + 2SO

2

(g)

CS

2

(l) + 3O

2

(g)

 CO

2

(g) + 2SO

2

(g)

H

o

rxn

= -1075 kJ

Slide59

Laws of Thermodynamics

Slide60

What is thermodynamics?Thermodynamics is the study of energy and its interconversions.

There are three (really four) laws of thermodynamics.

Slide61

1st Law of Thermodynamics

Energy of the universe is constant.

The internal energy of a system is the sum of the kinetic and potential energies of all particles of a substance

The change in energy is the sum of work (w) and heat (q)

 

*Law

of Conservation of Energy

Slide62

2nd Law of Thermodynamics

Entropy of the universe is always increasing.

Entropy is a essentially measure of disorder

In any spontaneous process, there is always an increase in the entropy of the universe.

 

Slide63

3rd Law of Thermodynamics

The entropy of a perfect crystal at 0K is zero.

Entropy increases with temperature

There is also technically a

0th Law that came after the first three that states that if two systems are in thermal equilibrium with a third system, they are in thermal equilibrium with each other. The transitive property

Slide64

0th Law of Thermodynamics

Two systems in thermal contact will eventually reach thermal equilibrium.

Energy will be transferred as heat between systems until they reach the same temperature

Slide65

The Laws of Thermodynamics

0

th

Law: This is the game.

1st Law: You can’t win. You can’t get more energy out of the system than you put in.2nd Law: You can’t break even. Any transfer of energy will result in some waste as entropy to the universe.3rd Law: You can’t get out of the game. You cannot achieve absolute zero.

Slide66

Spontaneous processes and entropy

Slide67

Entropy (S) Chemical or physical processes are driven by a decrease in enthalpy or an increase in entropy (or both)

Entropy

(S) is a measure of the dispersal of matter and energy (measure of molecular randomness or disorder)

It is a thermodynamic function that describes the number of arrangements (positions and/or energy levels) that are available to a system existing at a given state

Slide68

Entropy Nature spontaneously proceeds toward the states that have the highest probabilities of existing (higher entropy)

Example:

There is only one way to perfectly stack a deck of cards but infinite ways to spread those cards across the universe.

Slide69

Entropy In upper level chemistry, entropy can be understood in formal statistical terms; however, AP Chemistry focuses on describing entropy in qualitative terms

The emphasis of the AP curriculum is to be able to make predictions about the direction of ∆S

o

So is calculated relative to 0KSoreaction

= 

n

p

S

o

products

-

n

r

S

o

reactants

Slide70

Positional Entropy In a chemical reaction, the change in

positional entropy

is dominated by the relative numbers of gaseous reactants and products.

Each configuration that gives a particular arrangement is called a

microstate

Slide71

Entropy in Phase ChangesEntropy increases when matter is dispersed.

During phase changes from solid

 liquid  gas, dispersal of matter occurs in the sense that individual particles become more free to move and generally occupy a larger volume

Due to positional probability

Slide72

Entropy in Chemical Reactions Entropy can also increase in the context of individual particles in a chemical reaction

Entropy increases when the number of individual particles increases.

Entropy favors the side of the reaction with a larger number of species.

NaHCO

3  NaO + H2O + CO2

Slide73

Entropy of Gases

For a gas, entropy increases when there is an increase in volume (at constant temperature)

More possible positions for gas to occupy

Recall the Maxwell Boltzmann distribution in which the kinetic energy of particles of a gas broadens as the temperature increases

This is an increase in the dispersal of energyAs temperature increases, the entropy increases

Slide74

Entropy and Enthalpy

Slide75

Entropy of the SurroundingsConsider an endothermic process (like vaporization), where ∆

S

sys

is increasing as energy flows from the surroundings into the system. Therefore ∆

Ssurr must be negative. Whether the process is spontaneous depends on temperature and the entropy changes in the surroundings, which are primarily determined by heat flow. The magnitude of ∆Ssurr depends on temperature.

Slide76

∆Ssurr

The impact of the transfer of energy as heat to or from the surroundings will be greater at lower temperatures.

At constant pressure, heat flow is equal to ∆H

The negative accounts for the inverse relationship between endo/

exothermicity and entropySsurr

= 

quantity of heat (J)/T (K)

S

surr

= -

H/T

Slide77

Free Energy

Slide78

Gibbs Free Energy (G)

Free energy

is a thermodynamic function that measures spontaneity including the dependence on temperature (derived from the 2

nd law)Units: J/mol A process (at constant T and P) is spontaneous in the direction in which the free energy decreases. (-∆G = spontaneous)G = 

H - T

S

-

G =

S

surr

Slide79

Sign of Go

Some

process involve

both

a decrease in the internal energy of the components (Ho < 0) and an increase in the entropy of those components (So > 0). These processes are necessarily “thermodynamically favored” since Go < 0.When

Go > 0, the process is not thermodynamically favorable. When

G

o

< 0, the process

is

thermodynamically favorable.

G =

H - T

S

Slide80

Thermodynamic Favorability

Historically, the term “spontaneous” has been used to describe processes for which

G

o < 0.The phrase “thermodynamically favored” is used to avoid misunderstanding and confusion because of the common connotation for the term “spontaneous” meaning “immediately” or “without cause” Being thermodynamically favored does not mean that the reaction will proceed at a measurable rate.

Slide81

Spontaneity from H and S

You can determine the spontaneity of a reaction from the signs of

H

and

S by finding the sign of G.G = H - T

S

Sign

H

Sign

S

Always Spontaneous

-

+

Never Spontaneous

+

-

Sometimes Spontaneous

-

-

+

+

Qualitative

Quantitative

Slide82

When H and S have the same sign…

When

H

and

S have the same sign, we must calculate G to determine its sign. However, we are able to estimate the conditions G will be negative.G =

H - T

S

Temperature

Sign

H

Sign

S

Low

-

-

High

+

+

G is negative when

Slide83

Equilibrium

A system is at equilibrium only when:

G =

0

Slide84

Calculating Gibb’s Free Energy When a process is not drive by both entropy and enthalpy changes, then the Gibbs Free Energy change can be used to determine thermodynamic favorability

Standard free energy change

(∆G

o) is the change in free energy that will occur if the reactants in their standard states are converted to the products in their standard states.Go =

H

o

-

T

S

o

Slide85

Standard Free Energy of Formation

The

standard free energy of formation

(

) is the change in free energy that accompanies the formation of 1 mole of a substance from its constituent elements with all reactants and products in their standard states

for an element in its standard states is zero.

We find

in reference tables

 

G

o

=

n

p

G

o

f

(products)

-

n

r

G

o

f

(reactants)

*We can also use Hess’s Law

Slide86

∆G in Ideal Gases When dealing with ideal gases, pressure must be considered as it effects entropy

Entropy is highest at large volumes and low pressures

G =

Goreaction + RTln

(P)

Slide87

Nonspontaneous processes

Slide88

Nonspontaneous Reactions Not all reactions we want to occur are spontaneous

We can force reactions to occur by using external sources of energy to drive changes even if ∆G is positive

Electricity

Light

Coupling

Slide89

Electricity Electricity may be used to cause a process to occur that is not thermodynamically favored.

Examples:

Charging

a battery

Electrolysis

Slide90

Light Light may also be a source of energy for driving a process that in isolation is not thermodynamically favored.

Examples:

The photoionization of an atom, because although the separation of a negatively charge electron from the remaining positively charged ion is highly endothermic, ionization is observed to occur in conjunction with the absorption of a photon.

Slide91

Light Light may also be a source of energy for driving a process that in isolation is not thermodynamically favored.

Examples:

The overall conversion of carbon dioxide to glucose through photosynthesis, for which 6CO

2(g)+6H2O(l)  C6H12O6(aq)+6O2(g) has Go = +2880 kJ/molrxn

yet is observed to occur through a multistep process that is initiated by the absorption of several photons in the range of 400-700 nm.

Slide92

Coupling A thermodynamically unfavorable reaction may be favorable by coupling it to a favorable reaction, such as the conversion of ATP to ADP in biological systems.

In this context, coupling means the process involves a series of reactions with common intermediates, such that the reactions add up to produce an overall reaction with a negative

G

o.

Slide93

Kinetic vs. Thermodynamic Control

Slide94

Spontaneous Reactions that don’t “Occur”

Many processes that are thermodynamically favored do not occur to any measurable extent, or they occur at extremely slow rates.

Sometimes, a thermodynamically favored process may not occur due to kinetic constraints

Kinetic control

Thermodynamic control

Slide95

Kinetic Control

Processes that are thermodynamically favored, but do not proceed at a measurable rate, are said to be under “

kinetic control

.”

The fact that a process does not proceed at a noticeable rate does not mean that the chemical system is at equilibrium. High activation energy is a common reason for a process to be under kinetic control. Kinetic control is frequently seen at low temperatures, where meeting activation energy is problematic.

Slide96

Thermodynamic Control Thermodynamic control

depends on the relative stability of the products/reactants in a reversible reaction.

At high temperatures, where activation energy will be met regardless of direction, the reaction favors the production of the more stable product.

Slide97

Kinetic vs. Thermodynamic Control