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Lecture Five  Characteristic roots  &  characteristic vectors of a matrix Lecture Five  Characteristic roots  &  characteristic vectors of a matrix

Lecture Five Characteristic roots & characteristic vectors of a matrix - PowerPoint Presentation

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Uploaded On 2023-10-29

Lecture Five Characteristic roots & characteristic vectors of a matrix - PPT Presentation

The characteristic roots of the pp matrix A are the solutions of the following determinant equation Laplace expansion is used to write the characteristic polynomial as Since ID: 1026557

matrix characteristic positive roots characteristic matrix roots positive vectors definite root symmetric orthogonal form sum semi minimum diagonal vector

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1. Lecture Five Characteristic roots & characteristic vectors of a matrix

2. The characteristic roots of the (p×p) matrix A are the solutions of the following determinant equation: Laplace expansion is used to write the characteristic polynomial as:Since (Si) is the sum of all (i×i) principal minor determinant, then:

3. Associated with every characteristic root(latent , eigen, proper) : λi of the squre matrix A is a characteristic vector xi whose elements satisfy the homogeneous system of equations:

4. Properties of Characteristic Roots and Characteristic Vectors The characteristic roots of a positive definite symmetric matrix A are all positive(λi > 0), i.e.; there are p non-zero characteristic roots.The characteristic roots of a positive semi-definite symmetric matrix A are (λi ≥ 0), i.e.; p non-zero characteristic roots and (n-p) zero.For any positive definite symmetric matrix A, the characteristic roots of (A-1) are the reciprocal of characteristic roots of (A).If we have the matrix (Ak) , (k is a positive integer) then, it has the same characteristic vectors of (A) , i.e.;is the characteristic root of (Ak) , where is (λi) is the (ith) characteristic root of (A).

5. For every real symmetric matrix (A), there exists an orthogonal matrix (P) such that: D = P'AP where: D is the diagonal matrix of the characteristic roots of (A). The normalized characteristic vectors of (A) can be taken as the columns of (P) , such that: P'P=I.Any real quadratic form (Q.F.) can be reduced to a weighted sum of squares by computing the characteristic roots and vectors of its matrix, such that: x'Ax = y'P'APy by using the orthogonal transformation : x=Py where is: x'Ax = y'Dy = λ1y12 + λ2y22 + …+ λryr2

6. Where is: λi are the characteristic roots of the coefficient matrix. r is the rank of the form.The characteristic roots of an idempotent matrix (AA = A) are either zeros (0) or (1) ones and a quadratic form with such a matrix can be reduced to a sum of ( r ) squared terms. If (C) be the matrix whose columns are the (n) independent characteristic vectors of (A) then: B = C-1AC be the diagonal matrix with characteristic roots of (A). i.e.C: non-singular (full rank)

7. If λi ≠ λj for a symmetric matrix (A) , their corresponding vectors xi & xj are orthogonal.If (A) is orthogonal matrix , then all of its characteristic roots have absolute value of (1) i.e. (±1).If λi > 0 , then x'Ax is positive definite and if λi ≥ 0 , then x'Ax is positive semi definite.The characteristic roots of (AB) are identical to the characteristic roots of (BA), i.e., r(AB) = r(BA) , as well as: tr(AB) = tr(BA). Furthermore; tr(ABC) = tr(BCA) Note: If the Q.F. is to be maximum then λ must be the greater characteristic root of A and x is associated vector. Similarly , if the Q.F. is to be minimum then λ must be the minimum characteristic root of A.