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Nuclear Physics Part III Nuclear Physics Part III

Nuclear Physics Part III - PowerPoint Presentation

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Uploaded On 2022-06-07

Nuclear Physics Part III - PPT Presentation

1 Aside on the neutrinos Alpha decay and Tunneling Nuclear Reaction Kinematics Nuclear Spin Radioactive Decay Xray spectrum for Ru 106 Why is this isotope in the news not Cs 137 ID: 914118

mass nuclear decay mev nuclear mass mev decay alpha particle question energy rest tunneling ans protons spin total number

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Slide1

Nuclear Physics Part III

1

Aside on the neutrinos

Alpha decay and TunnelingNuclear Reaction KinematicsNuclear SpinRadioactive Decay

X-ray spectrum for Ru106 -Why is this isotope in the news ? (not Cs137)

Ans: a plume of Ru106 has been detected all over Europe. Most likely from a Russian medical isotope facility. Dose is small.

Slide2

Probability of ruthenium emission point using all measurements in Europe and weather info.

Technical analysis by French Nuclear Institute IRSN. [Ru

- signals reported by 43 nations.]

Question: What are medical isotopes used for ?Ans: Diagnosis and treatmentSee discussion on p.1461 of the text e.g. Technetium-99

Slide3

An Aside: mass of the neutrino?

N

ote

the values of the masses: mp =1.007276 u, mn = 1.008665 u the proton is a stable particle. [Q: What is u ?]

3

Does the neutrino have mass?

SuperKamiokande

Water Tank in Gifu-ken (2015 Nobel Prize for

Kajita

)

There are mass differences between different types of nu’s

Slide4

Review: Alpha decay

An

alpha particle α

is a 4He nucleus (2 protons and 2 neutrons) The α decay of the 226Ra (radium) nuclide to Radon.N.B. alpha decay requires quantum mechanical tunneling (original nucleus is bound and inside a potential well)

4

Slide5

QM Tunneling and alpha decay

http://hyperphysics.phy-astr.gsu.edu/hbase/Nuclear/alpdet.html#c1

Let’s work out a numerical example and remember how to calculate tunneling probabilities

5

Slide6

QM Tunneling and alpha decay (I)

In a simple model for a radioactive nucleus, an alpha particle (m=6.64 x 10-27kg) is trapped by a square barrier that has width 2.0 fm and height 30 MeV.

What is the tunneling probability if the kinetic energy of the alpha particle is 1.0 MeV below the top of the barrier ? [Also try 10 MeV below U

0]E1 MeV

6

Slide7

Example of QM Tunneling and alpha decay (II)

An alpha particle (m=6.64 x 10-27kg) is trapped by a square barrier that has width 2.0 fm and height 30 MeV.

What is the tunneling probability if the kinetic energy of the alpha particle is 1.0 MeV below

the top of the barrier ?

Here G= 0.5 and the tunneling probability

T= 0.09 or 9%Remember to convert to MKS units for

kappa

7

1

eV

=1.6 x 10

-19

J

Slide8

Example of QM Tunneling and alpha decay (III)

An alpha particle (m=6.64 x 10-27kg) is trapped by a square barrier that has width 2.0 fm and height 30 MeV.

What is the tunneling probability if the kinetic energy of the alpha particle is 1.0 MeV below

the top of the barrier ?The tunneling probability T= 0.09 or 9% for an alpha 1.0 MeV below the top of the well T=0.014 or 1.4% for a particle 10 MeV below the barrier (energy 20 MeV)

8

Slide9

The key to understanding energetics of nuclear reactions.

Question: This equation is based on E=mc

2

. Do you see why ?Question: What is Q if Q is positive ?Ans: Energy release Question: What is Q if Q is negative ?Ans: Energy that must supplied to make the reaction proceed.

Slide10

Example:

The difference between the LHS and RHS is -0.00128u

If Q is negative, what is the energy release ?

Ans: Must supply 1.192 MeV to A+B in center of mass for the reaction to proceed.

What is u (and why are the values not exact integers ?

Slide11

The atomic mass unit is defined so that C12 has exactly 12 u

Question: Why is MAZ not exactly equal to the sum of (Z x M

p) + (N x Mn

) ? Ans: There is nuclear binding energy !

Slide12

Some consequences of this curve of binding energy

Slide13

165 MeV

7 MeV

6 MeV

7 MeV6 MeV9 MeV200 MeV~ kinetic energy of fission products~ gamma rays~ kinetic energy of the neutrons

~ energy from fission products~ gamma rays from fission products

~ anti-neutrinos

from fission products

energetics

Each U-235 fission releases 30 million times more energy than a molecule of TNT;

3 million times per mass than coal

Energetics

But need one neutron to interact with the U-235 each time

Slide14

Nuclear Power is based on a chain reaction involving fission

Based on fission induced by neutrons

Nucleus is like a droplet of nuclear matter with surface tension from strong interaction and EM Coulomb repulsion from protons in competition

N.B. This does not work for U-238

Difference in rest mass here

Slide15

Nuclear stability and radioactivity

The right figure is a

Segr

è chart showing N versus Z for stable nuclides.In α decay, Z decreases by 2 and A decreases by 4, (why ?) moving the nuclei closer to the line of stability.

15

Slide16

Why do stable nuclei with many nucleons (those with a large value of

A

) have more neutrons than protons?

Nuclear Stability Clicker Question A. An individual nucleon interacts via the nuclear force with only a few of its neighboring nucleons.B. The electric force between protons acts over long distances.C. The nuclear force favors pairing of both neutrons and protons.D. both A. and B.E. all of A., B., and C.

16

Slide17

Why do stable nuclei with many nucleons (those with a large value of

A

) have more neutrons than protons?

Nuclear Stability Clicker Question A. An individual nucleon interacts via the nuclear force with only a few of its neighboring nucleons.B. The electric force between protons acts over long distances.C. The nuclear force favors pairing of both neutrons and protons.D. both A. and B.E. all of A., B., and C.

17

The Coulomb (EM ) interaction is infinite range while the strong force is short-range

Slide18

Nuclear spin

Like electrons, protons and neutrons are spin ½ particles. Spin and total angular momentum are quantized

Question: What is S for a single nucleon ?

Question: What is SZ for a single nucleon ?

18

Slide19

Nuclear spin

The total angular momentum is the sum of the spin and orbital angular momentum of all nucleons.

19

Slide20

Nuclear magnetic moments and a mystery

There is also a nuclear magneton.

Question: How does this compare to the Bohr

magneton ?Ans: It is 1836 times smaller than μB because of the ratio of the electron and proton mass (x 1836 heavier).Question: Shouldn’t the proton z component be +- μn ? And shouldn’t the neutron be zero ? What is going on ?

Ans: quarks

20

Slide21

Importance of nuclear spin

21

Slide22

Important applications of nuclear spin

What is this called ?

Ans

: Nuclear Magnetic Resonance (NMR)

22

Slide23

Importance of nuclear spin

23

Slide24

Radioactive decay: Activities and half-lives

The

half-life is the time for the number of radioactive nuclei to decrease to one-half of their original number

. The number of remaining nuclei decreases exponentially with decay constant λ (see Figure on the right).Activity is measured in either Curies (US) or Becquerel (Europe or Japan) 1 Ci= 3.7 x 1010Bq =3.7 x 1010decays/sec

24

Slide25

Radioactive decay law

Here N(t) is the number of radioactive nuclei present. The quantity

λ

is the “decay constant” and determines the probability per unit time that a nuclei will decay.Question: How do we integrate this ?Question: What is the solution ?

25

Slide26

Radioactive decay law

What is the half-life ? This corresponds to N(t)/N0=1/2

26

N.B. Half-life is different from the lifetime !!

Slide27

Q38.1

Yes, it can occur because it balances both charge number and mass number.

Yes, it

it can occur because the total rest mass of the product is greater than the rest mass of the original particle.No, it it cannot occur because the total rest mass of the product is greater than the rest mass of the original particle.No, it it cannot occur because the total rest mass of the product is smaller than the rest mass of the original particle.

27

Hint:

m_p

=1.007276 u,

m_n

= 1.008665 u

Slide28

Q38.1

Yes, it can occur because it balances both charge number and mass number.

Yes, it

it can occur because the total rest mass of the product is greater than the rest mass of the original particle.No, it it cannot occur because the total rest mass of the product is greater than the rest mass of the original particle.No, it it cannot occur because the total rest mass of the product is smaller than the rest mass of the original particle.

28

Hint:

m_p

=1.007276 u,

m_n

= 1.008665 u