1 objectives Fundamental concepts on basic character of amines Applications of these concepts in comparing the relative basic strengths of NH 3 various alkyl amines C 6 H 5 NH 2 and other substituted aromatic amines ID: 1034124
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1. CHEMISTRY LESSON:BASIC CHARACTER OF AMINES1
2. objectives:Fundamental concepts on basic character of amines.Applications of these concepts in comparing the relative basic strengths of NH3, various alkyl amines, C6H5NH2 and other substituted aromatic amines.2
3. Amines are derivatives of ammonia: NH3 R – NH2Various types of amines are primary (10), secondary (20) and tertiary (30): RNH2 R2NH R3N (10) (20) (30)The basic nature of an amine is due to the presence of a lone pair on N, and its ability to donate it; and depends on the stability of the conjugate acid.FUNDAMENTAL CONCEPTS ON BASIC CHARACTER OF AMINES-H+R3
4. Steric hindrance plays an important role in deciding basic strength.Electron releasing groups increase the basic strength , whereas electron withdrawing group decrease the basic strength of amines.A higher value of pKb implies lower basic strength.4
5. APPLICATION : COMPARISON OF NH3 AND RNH2As the alkyl group has +I – effect, it increases the electron density on N.Substituted ammonium ion is more stable due to charge dispersal by the alkyl group. So, RNH2 is more basic than NH3.5
6. APPLICATION : COMPARISON OF RNH2, R2NH AND R3N IN GASEOUS STATEAs the alkyl groups have +I – effect, it increases the electron density on N.As these are in the gaseous phase, so only the +I – effect is considered.So, the order of basic nature is: 30 > 20 > 10 > NH3.6
7. APPLICATION : COMPARISON OF RNH2, R2NH AND R3N IN AQUEOUS STATEIn aqueous solutions, in addition to +I – effect, the solvation effect and steric hindrance are also at work.As 30 amines are least solvated, so their conjugate acids are least stable. So, we expect an order as : 10 > 20 > 30.But, due to the combination of +I – and solvation effects, secondary amines become most basic.So, the order of basic nature in methyl substituted amines is: 20 > 10 > 30 > NH3.7
8. But, this order applies to methyl substituted amines only.If R– is ethyl (C2H5–) group, then due to steric hindrance, solvation effect decreases in all the three types of amines. Hence, +I – effect of tertiary amines tends to dominate over the solvation effect of primary amines. Similarly, in propyl substituted amines, though electron density is increased due to +I – effect, still, due to steric hindrance, ability to donate the electron pair is decreased and hence the order is changed again.Hence, the order of basic nature in ethyl substituted amines is: 20 > 30 > 10 > NH3.The order of basic nature in propyl substituted amines is: 10 > NH3 > 20 > 30.Similarly, the order of basic nature in butyl substituted amines is: NH3 > 10 > 20 > 30.8
9. APPLICATION : COMPARISON OF AROMATIC AMINES WITH ALIPHATIC AMINESIt is because the lone pair on nitrogen in aniline is in conjugation with the benzene ring.Also, anilinium ion (conjugate acid) is less stable than aniline as it has lesser number of resonating structures. pKb of aniline is very high, as compared to that of alkyl amines; i.e., aniline is much less basic than alkyl amines.9
10. Presence of electron withdrawing group in the benzene ring decreases the basic strength and the presence of electron releasing groups increases the basic strength. NH3 NO2 NH3 CH3is less basic than Electron withdrawing groupElectron releasing group10
11. THE ORTHO EFFECT IN AROMATIC AMINES It has been observed that any group; whether electron withdrawing, or electron releasing, at the ortho position in aniline always decreases its basic strength. This is known as the ORTHO EFFECT.The reason for the occurence of the ortho effect is steric hindrance. 11
12. QUESTIONS FOR PRACTICE(CLASSROOM EXERCISE)Predict the increasing order of basic strength in each of the following cases: NH CH3 – C – NH2 (I) CH3 – CH2 – NH2 (II) CH3 OCH3 – CH – NH2 (III) CH3 – C – NH2 (IV) Answer: IV < II < III < I12
13. 13 NH2 NH2CH3 NH2CH3 NH2CH3(I) (II) (III) (IV)Answer: II < I < III < IV NH2 NH2NO2 NH2NO2 NH2NO2(I) (II) (III) (IV)Answer: II < IV < III < I
14. THANK YOU14