Now set up an equation and solve for x 3 x 3 C O L A 5x 13 3x 3 5x 13 16 2x 8 x Find the measure of angle 1 10x 8 1 2 3x 6 10x 8 3x 6 180 ID: 225310
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Slide1
OA bisects <COL. <COA = 3x + 3, <AOL = 5x – 13 Draw a picture to represent this situation.
Now set up an equation and solve for x.
3
x + 3
C
O
L
A
5x – 13
3x + 3 = 5x – 13
16 = 2x
8 = xSlide2
Find the measure of angle 1.
10x – 8
1
2
3x + 6
10x – 8 + 3x + 6 = 180
13x – 2 = 180
13x = 182
x = 14
<1 = 10(14) – 2
= 138˚Slide3
UZ bisects <QUI. <QUZ = 8x + 6
<ZUI = 14y<QUI = 20x – 4yDraw a picture to represent this situation.
Now set up a
system
of equations and solve for x and y.
8x + 6
Q
U
I
Z
14y
20x – 4y
8x + 6 = 14y
8x – 14y = -6
8x + 6 + 14y = 20x – 4y
-12x + 18y = -6
2(8x + 6) = 20x – 4y
16x + 12 = 20x – 4y
-4x + 4y = -12
2(14y) = 20x – 4y
28y = 20x – 4y
-20x + 32y = 0
x = 8
y = 5Slide4
Three times an angle is 16 more than the angle’s supplement. Find the measure of the angle’s complement.
3x = 16 + 180 – x
4x = 196
x = 49
Complement = 90 – 49 = 41˚ Slide5
A is the midpoint of segment CT.CA = 4x + 3
AT = 2x + 53 Draw a picture to represent this situation.
Now set up an equation and solve for x.
4x
+ 3
C
T
A
2x + 53
4x + 3 = 2x + 53
2x = 50
x = 25