Objective To solve multistep probability tasks with the concept of geometric distributions CHS Statistics A Geometric probability model tells us the probability for a random variable that counts the number of ID: 295376
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Slide1
4.5: Geometric Distributions
Objective: To solve multistep probability tasks with the concept of geometric distributions
CHS StatisticsSlide2
A Geometric probability model
tells us the probability for a random variable that counts the number of trials until the first success.
Geometric DistributionsSlide3
Requirements of geometric distributions:
Each observation is in one of two categories: success or failure.
The probability is the same for each observation.
Observations are independent. (Knowing the result of one observation tells you nothing about the other observations.)
The variable of interest is the number of trials required to obtain the first success
. [The only difference from a binomial distribution]
Geometric DistributionsSlide4
Does this represent a geometric distribution? What is your evidence?
A new sales gimmick is to sell bags of candy that have 30% of M&M’s covered with speckles. These “groovy” candies are mixed randomly with the normal candies as they are put into the bags for distribution and sale. You buy a bag and remove candies one at a time looking for the speckles.
ExampleSlide5
A new sales gimmick is to sell bags of candy that have 30% of M&M’s covered with speckles. These “groovy” candies are mixed randomly with the normal candies as they are put into the bags for distribution and sale. You buy a bag and remove candies one at a time looking for the speckles.
What’s the probability that the first speckled one we see is the fourth candy we get? Note that the skills to answer this question come from the very first day of the probability unit.
Geometric ModelSlide6
What’s the probability that the first speckled one is the tenth one? Write a general formula.
What’s the probability that the first speckled candy is one of the first three we look at?How many do we expect to have to check, on average, to find a speckled one?
Geometric Model (cont.)Slide7
p
= probability of successq = 1 – p = probability of
failure
X
= number of trials until the first success
occursP(X = x) = qx-1p
Geometric Model (cont.)Slide8
People with O-negative blood are “universal donors.” Only about 6% of people have O-negative blood
.If donors line up at random for a blood drive, how many do you expect to examine before you find someone who has O-negative blood?
What’s the probability that the first O-negative donor found is one of the four people in line?
ExampleSlide9
2nd
DISTR geometpdf( Note the
pdf
for Probability Density Function
Used to find any
individual outcomeFormat: geometpdf(p,x)
2
nd
DISTR
geometcdf
(
Note the
cdf
for Cumulative Density Function
Used to find the first success
on or before the xth trialFormat: geometcdf(
p,x)Try the last example using the calculator!
Much easier
…
Geometric Probabilities Using CalculatorSlide10
Example
: Let x represent the number of students who must be stopped before finding one with jumper cables. Suppose 40% of students who drive to school carry cables. Find the probability that the 3rd
person you stop has them.
You need to stop no more than 3 people.
ExampleSlide11
Assignment