Atomic Mass Number Where did that decimal come from Calculating Average Atomic Mass I CAN calculate the Average Atomic Mass Number of an element from its isotope data The Case for a Decimal ID: 934852
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Slide1
Calculating the Average Atomic Mass Number
Where did that decimal come from?
Slide2Calculating Average Atomic Mass
I CAN
calculate the Average Atomic Mass Number of an element from its isotope data
.
Slide3The Case for a Decimal We learned earlier that
ATOMIC MASS NUMBER
is the
COMBINED NUMBER
of
P
+
and
N
o
in an atom.
Yet, the AMN given on the Periodic Table generally has a
DECIMAL
in it.
Slide4We discussed earlier that the AMN on the PT represents a
WEIGHTED AVERAGE
of all the
ISOTOPES
(atoms from the same element with varying numbers of N
o
) of an element.
Most elements have
2 OR MORE
isotopes.
Each different isotope always occurs in the
SAME RELATIVE AMOUNT
regardless of where the sample of the element is taken from.
Slide5For example: Lead has 4 isotopes:1.40 % of all lead atoms are
Pb -204
24.10%
of all lead atoms are
Pb-206
22.10%
of all lead atoms are
Pb-207
52.40%
of all lead atoms are
Pb-208
The
UNIT
for Atomic Mass is the
ATOMIC MASS UNIT
, abbreviated “
amu
” or simply “
u
”.
How would you determine the AVERAGE ATOMIC MASS NUMBER of lead?
Slide6First of all, why can’t we simply add all the AMNs of the four isotopes up and find the average by dividing by 4?
We can’t do this because there is
NOT AN EQUAL PERCENTAGE
of each isotope. It they were all
25%
each we could.
Since there is not an equal percentage of each, they do not contribute equally to the overall average.
Since we can’t do a simple average, we will have to calculate a
WEIGHTED AVERAGE
.
Slide7Calculating a Weighted AverageTo find a weighted average,
EACH VALUE
is
MULTIPLED
by its
PERCENTAGE
and the results are
ADDED
together.
For Average Atomic Mass, the equation looks like this:
Average AMN = Σ (Atomic Mass x
P
ercentage)
Σ =
sigma
=
“find the sum of”
Slide8Practice Problem
L
ead has 4 isotopes: 1.40 % of all lead atoms are Pb -204,
24.10% of all lead atoms are Pb-206, 22.10% of all lead atoms
are Pb-207, and 52.40% of all lead atoms are Pb-208. What is
the average AMN for lead?
STEPS
1. Multiple
EACH
mass by its percentage, making sure to
move the decimal in the percentage
TWO PLACES
to the
LEFT
before multiplying.
2. Add the results and
ROUND
to
SF
.
Pb-204 204 u x 0.0140 = 2.856 u
Pb-206 206 u x 0.2410 = 49.646 u
Pb-207 207 u x 0.2210 = 45.747 u
Pb-208 208 u x 0.5240 = 108.992 u
_________
≈ 207.241 u
Slide10MORE PRACTICEUranium has three common isotopes. If the abundance of
U-234
is 0.01%, the abundance of
U-235
is 0.71%, and the abundance of
U-238
is 99.28%, what is the average atomic mass of uranium?
Slide11U-234 U-234 u x 0.0001 = 0.0234 u
U
-235
U-235 u x 0.0071 = 1.6685 u
U
-238
U-238 u x 0.9928 =
236.2864 u
237.978
3
u
(There are only
3 SF
in 0.0234) ≈
237.978 u