httpwwwcompnusedusgcs1010 Week 5 Repetition Statements Objectives Understand the program control structure called loops Compare the different types of repetition structure CS1010 AY20123 Semester 1 ID: 757954
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Slide1
CS1010: Programming Methodology http://www.comp.nus.edu.sg/~cs1010/Slide2
Week 5: Repetition Statements
Objectives:
Understand the program control structure called loops
Compare the different types of repetition structure
CS1010 (AY2012/3 Semester 1)
Week5 - 2
References:
Chapter 4
Lessons
4.7 –
4.11Slide3
Week 5: Outline (1/2)
Week 4 Exercise #3: NRIC Check Code
Loops!
The
while
Loop
3.1 Demo
3.2 Loop condition
3.3 TracingThe do-while LoopThe for Loop5.1 Odd IntegersExercise #1: Sum of Multiples of 3Exercise #2: Asterisks
CS1010 (AY2012/3 Semester 1)
Week5 -
3Slide4
Week 5: Outline (2/2)
Common Errors
Some Notes of Caution
Exercise #3: Tracing Nested Loops
Using
break
in Loop
Using
continue in LoopExercise #4: Prime Number (take-home)CS1010 (AY2012/3 Semester 1)Week5 - 4Slide5
1. Week 4 Exercise #2: Taxi Fare (1/3)
The taxi fare structure in Singapore must be one of the most complex in the world! See
http://www.taxisingapore.com/taxi-fare/
Write a program
Week4_TaxiFare.c that reads the following input data (all are of int type) from the user, and computes the taxi fare:
dayType: 0 represents weekends and public holidays (PH for short); 1 represents weekdays and non-PH
boardHour
,
boardMin: the hour and minute the passengers board the taxi (eg: 14 27 if the passengers board the taxi at 2:27 PM)distance: the distance of the journey, in metresYour program should have a function float computeFare(int dayType,
int
boardTime
,
int
distance)
The parameter
boardTime
is converted from the input data boardHour and boardMin. It is the number of minutes since 0:00hr.Eg: If boardHour and boardMin are 14 and 27 respectively, then boardTime is 867.
Week4 - 5
CS1010 (
AY2012/3
Semester 1)Slide6
1. Week 4 Exercise
#2: Taxi Fare (2/3)
To implement the actual taxi fare could be a PE question
. In this exercise, we use a (grossly) simplified fare structure:
Basic Fare:
Surcharge
(applicable at the time of boarding):
Week4 -
6CS1010 (AY2012/3 Semester 1)Flag-down (inclusive of 1st km or less)$3.40Every 400m thereafter or less up to 10.2km
$0.22
Every 350m thereafter or less after 10.2km
$0.22
dayType
Midnight charge (12am – 5:59am)
Peak hour charge (6am – 9:29am)
Peak
hour charge (6pm – 11:59pm)0: Weekends & PH50% of metered fareNone25% of metered fare1: Weekdays and non-PH
50% of metered fare25% of metered fare25% of metered fareSlide7
1. Week 4 Exercise #2: Taxi Fare (3/3)
You are given an incomplete program
Week4_TaxiFarePartial.c
. Complete the program. This exercise is mounted on
CodeCrunch.Sample runs below for your checking
Week4 -
7
CS1010 (
AY2012/3 Semester 1)Day type: 0Boarding hour and minute: 14 27Distance: 10950
Total taxi fare is
$9.12
First 1km: $3.40
Next 9.2km: 23
$0.22 = $5.06
Next 750m: 3
$0.22 = $0.66Basic fare = $9.12No surchargeTotal fare = $9.12Day type: 1
Boarding hour and minute: 9 20
Distance:
6123
Total taxi fare is
$7.83
First 1km: $3.40
Next 5123m: 13
$0.22 = $2.86
Basic fare = $6.26
Surcharge = 25% $6.26 = $1.57
Total fare = $7.83
Day type:
1
Boarding hour and minute:
5 59
Distance: 9000Total taxi fare is $11.70
First 1km: $3.40
Next 8km: 20
$0.22 = $4.40
Basic fare = $7.80
Surcharge = 50% $7.80 = $3.90
Total fare = $11.70Slide8
1. Week 4 Exercise #2: Taxi Fare
Week4 -
8
CS1010 (
AY2012/3 Semester 1)
float
computeFare
(
int daytype, int bTime, int
dist
)
{
basicFare
=
calcBasicFare(dist) ; return includeSurcharge
(basicFare,
daytype
,
bTime
) ;
}
float
calcBasicFare
(
int
dist
){
// Pre-
cond
: 0 <= dist ; if (dist
<= 1000)
return 3.40;
else
if
(
dist
<= 10200
&&
dist
> 1000
)
return (3.40
+
ceil((
dist
- 1000) /
400.0) * INCREMENT);
else
if
(
dist
> 10200)
return (3.40
+
9200 / 400.0 * INCREMENT +
(ceil((
dist
-
10200)
/
350.0))
*
INCREMENT);
}Slide9
1. Week 4 Exercise #2: Taxi Fare
Week4 -
9
CS1010 (
AY2012/3 Semester 1)
float
computeFare
(
int daytype, int bTime, int
dist
)
{
basicFare
=
calcBasicFare(dist) ; return includeSurcharge
(basicFare,
daytype
,
bTime
) ;
}
float
includeSurcharge
(float fare,
int
dType
,
int
bTime
){ // Pre-cond: dType
= 0 or 1, 0 <=
bTime
<= 2359 ;
if (
bTime
< 360
&& (
dType
== 0 ||
dType
== 1
)
)
return fare * 1.50;
else
if
(
dType
== 1 && (
bTime
< 600
&&
dtime
>=360
))
return fare * 1.25;
else if (
b
Time
>= 1080)
return fare * 1.25;
else return fare ;
}Slide10
1. Week 4 Ex3: NRIC Check Code (1/3)
Algorithm for NRIC check code
NRIC consists of 7 digits.
Eg: 8730215
Step 1: Multiply the digits with corresponding weights
2,7,6
,
5
,4,3,2 and add them up.Eg: 82 + 77 + 36 +
0
5
+
2
4
+
13 + 52 = 16+49+18+0+8+3+10 = 104Step 2: Divide step 1 result by 11 to obtain the remainder.Eg: 104 % 11 = 5
Week5 - 10
Week5 -
10
CS1010 (AY2012/3 Semester 1)Slide11
1. Week 4 Ex3: NRIC Check Code (2/3)
Algorithm for NRIC check code (cont…)
Step 3: Subtract step 2 result from 11
Eg: 11 – 5 = 6
Step 4: Match step 3 result in this table for the check code
Eg: The check code corresponding to 6 is ‘F’.
Therefore, the check code for
8730215
is ‘F’.Sample run:1
2
3
4
5
6
7
8
9
10
11
A
B
C
D
E
F
G
H
I
Z
J
Week5 -
11
Week5 -
11
Enter 7-digit NRIC number:
8730215
Check code is
F
CS1010 (AY2012/3 Semester 1)Slide12
1. Week 4 Ex3: NRIC Check Code (3/3)
Write a program
Week4_NRIC.c
to generate the check code given a 7-digit NRIC number.Your program should include a function char
generateCode(
int) that takes in a single integer (the NRIC number) and returns a character (which is the check code).
You need to use the
char
type. (Explore this on your own.)A character constant is enclosed in single quotes (eg: 'A', 'Z').The format specifier for char type is %c (to be used in a printf() statement).Do not use techniques that are not covered in class, such as array. Your program may be long now. You can write an improved version later.This is your take-home exercise.This exercise is mounted on CodeCrunch.
Week5 -
12
Week5 -
12
CS1010 (AY2012/3 Semester 1)Slide13
1. Week 4 Ex3: NRIC Check code
Step 1
: Multiply the digits with corresponding weights
2,
7,6,
5,4,3
,
2
and add them up.Eg: 82 + 77 + 36 + 05 +
2
4
+
1
3
+
52 = 16+49+18+0+8+3+10 = 104 // Extract the digits digit7 = num%10; num
/= 10; digit6 = num%10;
num
/= 10;
digit5 = num%10;
num
/= 10;
digit4 = num%10;
num
/= 10;
digit3 = num%10;
num
/= 10;
digit2 = num%10;
num
/= 10;
digit1 = num%10;
step1 = digit1*2 + digit2*7 + digit3*6 + digit4*5 + digit5*4 + digit6*3 + digit7*2
;
Week5 -
13
Week5 -
13Slide14
1. Week 4 Ex3: NRIC Check code
Step
2: Divide step 1 result by 11 to obtain the remainder.
Eg
: 104 % 11 = 5
step2 = step1 % 11;
Step 3: Subtract step 2 result from 11
Eg
: 11 – 5 = 6step3 = 11 - step2;Week5 - 14Week5 - 14CS1010 (AY2012/3 Semester 1)Slide15
1. Week 4 Ex3: NRIC Check Code
Step
4: Match step 3 result in this table for the check code
switch
(step3) {
case 1: code = 'A'; break;
case 2: code = 'B'; break;
case 3: code = 'C'; break;
case 4: code = 'D'; break; case 5: code = 'E'; break; case 6: code = 'F'; break; case 7: code = 'G'; break; case 8: code = 'H'; break;
case 9: code = 'I'; break;
case 10: code = 'Z'; break;
case 11: code = 'J';
} // end
switch
1
2
3
4
5
6
7
8
9
10
11
A
B
C
D
E
F
G
H
I
Z
J
Week5 -
15
Week5 -
15
CS1010 (AY2012/3 Semester 1)Slide16
Recall: Control Structures
Week5 -
16
Week5 - 16
Sequence
Selection
Repetition
if-else, switch
CS1010 (AY2012/3 Semester 1)Slide17
2. LOOPS! (1/2)
Week5 -
17
Week5 - 17
“A program without a loop and a structure variable isn’t worth writing.”
Alan
J.Perlis
Yale University
The first recipient of ACM Turing AwardA loop is a statement
whose job is to
repeatedly
execute some other statement(s).
CS1010 (AY2012/3 Semester 1)Slide18
2. LOOPS! (2/2)
Week5 -
18
cond
?
Some
statement(s)
true
false
loop body
Loop condition
Week5 -
18
Each round of the loop is called an
iteration
.
CS1010 (AY2012/3 Semester 1)Slide19
2. Loop: Demo (1/3)
Keep prompting the user to input a non-negative integer, and output that integer.
Halt the loop when the input is negative.
Enter a number:
12
You entered: 12
Enter a number:
0
You entered: 0Enter a number: 26You entered: 26Enter a number: 5You entered: 5Enter a number: -1Week5 - 19Week5 - 19
Key observations:
You keep repeating a task while certain condition is met, or alternatively, you repeat until the condition is not met.
You do not know beforehand
how many iterations there will be.
CS1010 (AY2012/3 Semester 1)Slide20
2. Loop: Demo (2/3)
int
main(void) {
int
num;
printf
("Enter a number: "); scanf("%d", &num); if (num < 0) return 0; printf("You entered: %d\n", num); printf("Enter a number: ");
scanf("%d", &num
);
if
(num < 0) return
0;
printf("You entered: %d\n", num); printf("Enter a number: ");
scanf("%d", &num);
....
}
Week5 -
20
Week5 -
20
Loop condition
Enter a number:
12
You entered: 12
Enter a number:
0
You entered: 0
Enter a number:
26
You entered: 26
Enter a number:
5
You entered: 5
Enter a number:
-1
Loop body
CS1010 (AY2012/3 Semester 1)Slide21
2. Loop: Demo (3/3)
Week5 -
21
num
>= 0?
printf
…
printf
… scanf …truefalse
Week5 -
21
CS1010 (AY2012/3 Semester 1)
int
main(
void
) {
int
num;
printf
(
"Enter a number: "
);
scanf
(
"
%d
"
, &num);
while (num >= 0) {
printf
(
"You entered:
%d\n
"
, num);
printf
(
"Enter a number: "
);
scanf(
"
%d
"
, &num);
}
return 0;}Week5_Read_print.cSlide22
3. The while
Loop
CS1010 (AY2012/3 Semester 1)
Week5 - 22
while (
condition
)
{ // loop body}cond?
Loop body
true
false
If condition is
true
, execute
loop body; otherwise, terminate loop.Slide23
3.1 The while
Loop: Demo (1/3)
Enter a number:
12Enter a number:
0Enter a number:
26
Enter
a number: 5Enter a number: -1The maximum number is 26Week5 - 23Week5 - 23CS1010 (AY2012/3 Semester 1)
Keep prompting the user to input a non-negative integer, and output that integer.
Halt the loop when the input is negative,
and output the maximum integer input so far.
Slide24
3.1 The while
Loop: Demo (2/3)
Week5 - 24
maxi = 0;
num
input;
while (num >= 0) { if (maxi < num) maxi = num; num
input;
}
print maxi;
maxi = 0;
num
input; if (
num < 0) {
print maxi; stop;
}
if (maxi < num)
maxi = num ;
num
input;
if (
num
< 0) {
print maxi; stop;
}
if (maxi < num)
maxi = num;
num input;...Week5 - 24
CS1010 (AY2012/3 Semester 1)Slide25
3.1 The while
Loop: Demo (3/3)
Week5 - 25
Week5 -
25
CS1010 (AY2012/3 Semester 1)
int
main(void) { int num, maxi =
0
;
printf
(
"Enter a number: "
);
scanf("%d"
, &num);
while
(num >= 0) {
if
(maxi < num) {
maxi = num;
}
printf
(
"Enter a number: "
);
scanf(
"
%d
", &num); } prinf("The maximum number is
%d\n
"
, maxi);
return
0
;
}
Week5_Find_max.cSlide26
3.2 while
Loop
Condition (1/2)
When the loop condition is always false
, the loop body is not executed.
Week5 -
26
Output:
?
Week5 -
26
CS1010 (AY2012/3 Semester 1)
a = 2;
b = 7;
while (a == b) {
print a;
a = a + 2;
}Slide27
3.2 while
Loop
Condition (2/2)Week5 -
27
Output:
?
Week5 -
27
CS1010 (AY2012/3 Semester 1)
a = 2;
b = 7;
while (a != b) {
print a;
a = a + 2;
}
Slide28
3.3 Tracing while
Loop (1/4)
Trace the following codes manually and write out their outputs (assume all variables are of type
int)
Week5 -
28
CS1010 (AY2012/3 Semester 1)
a =
1
;
while
(a*a <
100
) {
printf("%d ", a); a *=
2;}
printf
(
"
\n
"
);
(a)
b =
0
; c =
9
;
while
(b < c) {
printf("b=%d,
c=
%d\n
"
, b, c);
b++; c--;
}
printf
(
"outside: b=
%d
,
c=
%d\n
"
, b, c);
(b)
Slide29
3.3 Tracing while
Loop (2/4)
Example: Given a positive integer
n, print out its digits from least significant to most significant.
Sample run:
Week5 -
29
Enter a positive integer: 289433
49
8
2
CS1010 (AY2012/3 Semester 1)Slide30
3.3 Tracing while
Loop (3/4)
Example: Given a positive integer
n, print out its digits from least significant to most significant.
Week5 -
30
CS1010 (AY2012/3 Semester 1)
//
Precond
: n > 0
void
print_digits
(
int
n) { int digit;
while
(n >
0
) {
digit = n%
10
;
printf
(
"
%d\n
"
, digit);
n /=
10; }}Week5_Print_digits.cSlide31
//
Precond
: n > 0
void
print_digits
(
int
n) { int digit; while (n >
0
) {
digit = n%
10
;
printf
("%d\n", digit); n /=
10;
}
}
Week5_Print_digits.c
3.3 Tracing
while
Loop (4/4)
Week5 -
31
n initially
28943
n @ point
29843
digit @ point
***
What are the values of
n
and
digit
after exiting the loop?
CS1010 (AY2012/3 Semester 1)Slide32
4. The do-while
Loop (1/2)
Week5 - 32
do
{ // loop body} while (
condition
);
Execute loop body at least once.cond?
Loop
body
true
false
CS1010 (AY2012/3 Semester 1)Slide33
4. The do-while
Loop (2/2)
Example: Count the number of digits in an integer.
Week5 -
33
do
{
// loop body} while ( condition );CS1010 (AY2012/3 Semester 1)
//
Precond
: n > 0
int
count_digits
(
int n) {
int
counter =
0
;
do
{
counter++;
n /=
10
;
}
while
(n >
0
);
return counter;
}
Week5_Count_digits.cSlide34
5. The for
Loop (1/2)
Week5 -
34
for (
initialization; condition; update
)
{
// loop body}Initialization: initialize the loop variable
Condition:
repeat loop while the condition
on
loop variable
is
true
Update: change value of loop variable
CS1010 (AY2012/3 Semester 1)Slide35
5. The for
Loop (2/2)
Example: Print numbers 1 to 10
Week5 -
35
int
n;
for (n=1; n<=10; n
++) {
printf
("%3d", n);
}
Steps:
n=1;
if
(n<=10)
{ printf(…);
n++;
Go to step 2
}
Exit the loop
CS1010 (AY2012/3 Semester 1)Slide36
5.1 The for
Loop: Odd Integers (1/2)
Week5 -
36
CS1010 (AY2012/3 Semester 1)
#include
<
stdio.h
>void print_odd_integers(int);
int
main(
void
) {
int
num; printf("Enter a positive integer: "
);
scanf
(
"
%d
"
, &num);
print_odd_integers
(num);
return
0
;
}// Precond: n > 0
void
print_odd_integers
(
int
n
) {
int
i
;
for
(
i
=
1
; i<=n; i+=2) printf("%d ", i); printf("\n");}Week5_OddIntegers_v1.cSlide37
5.1 The for
Loop: Odd Integers (2/2)
Week5 -
37
CS1010 (AY2012/3 Semester 1)
//
Precond
: n > 0
void print_odd_integers(int n) {
int
i
;
for
(i=1; i<=n; i
++)
if
(i%
2
!=
0
)
printf
(
"
%d
"
,
i
);
printf("\n");}
Week5_OddIntegers_v2.c
//
Precond
: n > 0
void
print_odd_integers
(
int
n
) {
for
( ; n >
0
; n--)
if
(n%2 != 0) printf("%d ", n); printf("\n");}Week5_OddIntegers_v3.cValues printed from largest to smallest.Empty statementSlide38
6. Exercise #1: Sum of Multiples of 3 (1/2)
Modify the program
Week5_OddIntegers_v1.c
to read a positive integer n and then compute the sum of all integers which are multiples of 3 between 1 and n using a ‘for’ loop. Write a function called
sum_multiples_of_3(int
).This problem can be solved with a formula, but we will use the ‘while’ loop just for exercise.
Call this program
Week5_SumMultiples3.c
Sample run:Week5 - 38
Enter a positive integer:
50
Sum = 408
CS1010 (AY2012/3 Semester 1)Slide39
6. Exercise #1: Sum of Multiples of 3 (2/2)
How about using a while loop instead?
Pseudo-code using a while loop:
Week5 -
39
CS1010 (AY2012/3 Semester 1)
precondition: n
> 0
sum
0
i
n
while
i
> 0
if
i
is multiple of 3 then
sum
sum +
i
i
i
- 1
return sumSlide40
7. Exercise #2: Asterisks (1/2)
Write a program
Week5_Asterisks.c
to read an integer n and print a certain number of asterisks on a single line. Write a function
print_asterisks(int
).If
n
is non-positive, then no asterisk should be printed.
Sample runs:Week5 - 40
Enter n: 3
*****
Done!
Enter n:
6
***********
Done!
Enter n: 10
*******************Done!
Enter n:
-2
Done!
Think!
What is the relationship between
n
and the number of *?
CS1010 (AY2012/3 Semester 1)Slide41
7. Exercise #2: Asterisks (2/2)
Write a program
Week5_Asterisks.c
to read an integer n and print a certain number of asterisks on a single line. Write a function
print_asterisks(int
).
Week5 -
41
CS1010 (AY2012/3 Semester 1)Pseudo-code:read input n ;
if n is non-positive
print “done” and end program ;
m
compute the number of asterisks given n
print_asterisks
(m)
end program;Slide42
8. Common Errors (1/2)
What are the outputs for the following programs?
(Do not code and run them. Trace the programs manually.)
Week5 -
42
CS1010 (AY2012/3 Semester 1)
int
i
;
for
(
i
=
0; i
<
10
;
i
++);
printf
(
"
%d\n
"
,
i
);
Week5_CommonErrors1.c
int
i
=
0
;
while
(
i
<
10
);
{
printf
(
"
%d\n
", i); i++; }Week5_CommonErrors2.cSlide43
8. Common Errors (2/2)
Off-by-one error; make sure the loop repeats exactly the correct number of iterations.
Make sure the loop body contains a statement that will eventually cause the loop to terminate.
Using ‘=’ where it should be ‘==’
Putting ‘;’ where it should not be (just like for the ‘if’ statement)
Week5 -
43
CS1010 (AY2012/3 Semester 1)
int
z =
3
;
while
(z = 1) {
printf
(
"z =
%d\n
"
, z);
z = 99;
}
Week5_CommonErrors3.cSlide44
9. Some Notes of Caution (1/2)
Involving real numbers
Trace the program manually without running it.
Week5 -
44
CS1010 (AY2012/3 Semester 1)
double
one_seventh
=
1.0
/
7.0
;
double
f =
0.0;
while
(f !=
1.0
) {
printf
(
"
%f\n
"
, f);
f +=
one_seventh
;
}
Week5_Caution1.cSlide45
9. Some Notes of Caution (2/2)
Involving ‘wrap-around’
Trace the program manually without running it.
Week5 -
45
CS1010 (AY2012/3 Semester 1)
int
a =
2147483646
;
int
i
;
for
(
i
=
1
;
i
<=
5
;
i
++) {
printf
(
"
%d\n
", a); a++;}Week5_Caution2.cSlide46
10. Exercise #3: Tracing Nested Loops
You are given
Week5_NestedLoop1.c
, Week5_NestedLoop2.c and
Week5_NestedLoop3.c
Hand trace the programs and write out the outputs without running the programs
Verify your answers by running the programs
Week5 -
46CS1010 (AY2012/3 Semester 1)Slide47
11. Using break
in Loop (1/2)
You have seen ‘break’ in switch statement
‘break’ can also be used in a loop
Test out
Week5_BreakInLoop.c
Week5 -
47
CS1010 (AY2012/3 Semester 1)Slide48
11. Using break
in Loop (2/2)
Use ‘break’
sparingly
, because it violates the one-entry-one-exit control flow.
A loop with ‘break’ can be rewritten into one without ‘break’.
Week5 -
48
CS1010 (AY2012/3 Semester 1)// with break
int
n,
i
=
1
, sum =
0;while (i
<= 5
) {
scanf
(
"
%d
"
, &n);
if
(n <
0
)
break
; sum += n; i++;}
// without break
int
n,
i
=
1
, sum =
0
;
int
isValid
=
1
;
while
((
i <= 5) && isValid){ scanf("%d", &n); if (n < 0) isValid = 0; else { sum += n; i++; }}Slide49
12. Using continue
in Loop
Test out
Week5_ContinueInLoop.c
‘continue’ is used even less often than ‘break’
Week5 -
49
CS1010 (AY2012/3 Semester 1)Slide50
13. Exercise #4: Prime Number (1/2)
Primality
test
is a classic programming problem
Given a positive integer, determine whether it is a prime
A prime number has two distinct factors (divisors): 1 and itself. Examples: 2, 3, 5, 7, 11, ... (Note: 1 is not a prime!)
Write a program
Week5_PrimeTest.c
. You should include a function is_prime(int). (What does it return?)Sample runs:
Week5 - 50
Enter a positive integer:
131
131 is a prime.
Enter a positive integer:
713
713 is not a prime.
CS1010 (AY2012/3 Semester 1)Slide51
13. Exercise #4: Prime Number (2/2)
This is your
take-home exercise
.This exercise is mounted on
CodeCrunch.
We will discuss this in the next lecture.
Week5 -
51
CS1010 (AY2012/3 Semester 1)Slide52
Summary for Today (1/2)
Week5 -
52
Repetition statements (loops)
for
,
while
,
do-whileNested loopsbreak and continueCS1010 (AY2012/3 Semester 1)Slide53
Summary for Today (2/2)
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53
You have learned the 3 control structures:
Sequence, Selection, Repetition
With these, you are able to solve just any
computing problem!
However, writing good programs is
more than just learning the syntax:Logic should be clearVariables should be descriptiveAlgorithm should be efficientCS1010 (AY2012/3 Semester 1)Slide54
Announcements/Things-to-do
Revise Chapter 4 (Lessons 4.7 – 4.11)
Deadline for Lab #2
Deadline: 15
th
September 2012, Saturday, 12noon
Practical
Exam 1 (PE1
)22nd September 2012, SaturdaySee web page for details:http://www.comp.nus.edu.sg/~cs1010/3_ca/pe.html To prepare for next week’s lecture:Read Chapter 5 Functions
Bring along your
Week5_PrimeTest.c
program
Week5 -
54
CS1010 (AY2012/3 Semester 1)Slide55
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