MATH 2311 Section 7.4 - PowerPoint Presentation

MATH 2311 Section 7.4

Confidence Interval for a Population Mean

So, what is t* ?

How do we find critical values for a t -distribution? Look at the online text book, under appendices. Degrees of freedom are on the left and the top end (1-confidence level/2) are given at the top.

Assumptions:

Changes is the Confidence Interval: The following will cause an increase in the width of the confidence interval: An increase in the Margin of Error An increase in the Standard Deviation ( σ or s). An increase in the Confidence Level. A decrease in the Sample Size. Note: Changes in the sample mean ( ) will affect the center of the interval but will have no effect on the interval width.  

Examples: [0.992, 0.998] We are 90% confident that mean weight of Snicker’s 1-oz candies is between 0.992 oz and 0.998 oz

Popper 26 You select a sample of 50 people with a mean height of 72 inches from a population that has a standard deviation of 3 inches. 1. What would the margin of error be for a 95% confidence interval? 0.698 b. 0.832 c. 16.748 d. 1.644 2. What is the width of confidence interval? 1.396 b. 0.349 c. 1.66 d. 0.415 3. What is the confidence interval? a. [71.17, 72.83] b. [69.43, 75.11] c. [72.41, 75.21] d. [47.31, 53.65]

Popper 26 Continued: 4. Give an interpretation of this interval: A randomly selected person from the population has a 95% chance being within the interval. There is a 95% chance that the population mean will fall within the interval. If numerous similar samples are selected, 95% of them will contain the population mean. All of these choices 2 of the choices a, b or c. What will cause the width of the confidence interval to increase? decrease n b. decrease confidence level c. decrease standard deviation d. increase the mean

Examples:

t-score table:

t-score table: Since n = 16, we are going to use the value for n – 1 = 15 degrees of freedom. Since we want a confidence level of 90%, we will use an “Upper Tail Probability” of (1 – 0.90)/2 = 0.05. This is to account for only using one tail end of our graph, rather than 2. Our t* value will be 1.7531.

Using Rstudio and TI to calculate t* In Rstudio:qt(1.##/2,df) so for a 90% confidence interval with a sample size of 16: qt (1.90/2,15) In TI 84 (this command does not appear in TI 83) Under the DIST menu, select InvT area: 1.90/2 df : 15

Confidence Interval Calculation: [456.17, 543.83] We are 90% confident that the mean SAT score of all seniors is between 456.17 and 543.83.

Look at the following example: The effect of exercise on the amount of lactic acid in the blood was examined in an article for an exercise and sport magazine. Eight males were selected at random from those attending a week-long training camp. Blood lactate levels were measured before and after playing three games of racquetball, as shown in the accompanying table. Use this data to estimate the mean increase in blood lactate level using a 95% confidence interval.

[6.703, 20.547] We are 95% confident that the mean increase of lactate levels is between 6.703 and 20.547.

Interpretation of the Confidence Interval:

Example: A 95% confidence interval for the mean of a population is to be constructed and must be accurate to within 0.3 unit. A preliminary sample standard deviation is 2.9. Find the smallest sample size n that provides the desired accuracy.

When to use z* or t*? Use z* if: the question involved proportionsyou are given standard deviation of the population (σ). you are asked to find sample size. Use t* if: you are not provided with standard deviation of population. (you may be given standard deviation of your sample or given data to calculate standard deviation.)

Is it a z* or a t*? You wish to determine the confidence interval for the mean water salinity in a certain town. Preliminary studies have shown that water salinity is normally distributed with a standard deviation of 0.03. You select a sample of 25 households, and determine that the mean water salinity is 18 parts per thousand, with a standard deviation of 0.04. Construct the 90% confidence interval for the mean of water salinity.

Is it z* or t*? In a sample of 50 examinees, you have determined the mean score to be 87 with a standard deviation of 2. Determine the 95% confidence interval for the mean score of the population.

Is it t* or z*? You are designing a study to determine the interaction between sugar intake and insomnia. To do this, you wish to construct a sample of subjects that will have large amounts of sugar prior to bed and measure the duration of their sleep. Preliminary studies show that this will have a standard deviation of 0.5 hours. What size interval must be used to have a margin of error of no more than 1 hour?

Popper 27: A group of 10 students are comparing exam scores for a test they recently took. Based on these results, you want to find out, with 90% confidence, what range of grades you can expect to receive. Exam Scores: 70, 75, 80, 87, 90, 90, 93, 94, 96, 100 1. What is the sample mean? a. 90 b. 87.5 c. 80 d. 91.6 2. What is the sample standard deviation? a. 9.62 b. 92.5 c. 5.65 d. 13.83 3. What is the t* value that can be used here? a. 1.3722 b. 1.3968 c. 1.8331 d. 1.6449 4. What is the margin of error? a. 5.58 b. 5.00 c. 4.03 d. 6.12 5. What is the confidence interval? a. [70,100] b. [87.5, 100] c. [85.67, 89.33] d. [81.92, 93.08]