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Nested LOOPS Nested loops consist of an outer loop with one or more inner loops Nested LOOPS Nested loops consist of an outer loop with one or more inner loops

Nested LOOPS Nested loops consist of an outer loop with one or more inner loops - PowerPoint Presentation

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Nested LOOPS Nested loops consist of an outer loop with one or more inner loops - PPT Presentation

Each time the outer loop is repeated the inner loop starts from the beginning 1 WHAT ARE NESTED LOOPS Dr Soha S Zaghloul 2 Analysis How to calculate the total scores of a single student ID: 632248

student score sum printf score student printf sum scanf enter student

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Slide1

Nested LOOPSSlide2

Nested loops consist of an outer loop with one or more inner loops

Each time the outer loop is repeated, the inner loop starts from the beginning.

1. WHAT ARE NESTED LOOPS

Dr. Soha S. Zaghloul

2

Slide3

Analysis:

How to calculate the total scores of a single student?

Repeat the same steps for 100 students.

2

. Example (1)

Dr. Soha S. Zaghloul

3

Write a complete program that calculates the total scores of each of 100 students in a course. The program should read first the student’s ID.Slide4

2

. Example (1) –

cnt’d

Dr. Soha S. Zaghloul

4

Calculation of the total score of a student:

#include <

stdio.h

>

#define SENTINEL -999

i

nt

main (void)

{

double score;

// student’s score in an exam

double sum;

// accumulator to the scores of a single student

char ID[15];

//student’s ID

sum = 0.0;

// initialize the accumulator

score = 0.0;

// initialize the loop control variable

printf

(“Enter Student ID> “);

scanf

(“%s”, ID);

while (score != SENTINEL)

{

printf

(“Enter student’s score> “);

scanf

(“%f”, &score);

if (score != -999)

sum += score;

}

// end while

}

// end main

Slide5

2

. Example (1) –

cnt’d

Dr. Soha S. Zaghloul

5

Repeat the program for 100 students

#include <

stdio.h

>

#define SENTINEL -999

i

nt

main (void)

{

double score;

// student’s score in an exam

double sum;

// accumulator to the scores of a single student

char ID[15];

// student ID

int

i

;

// loop control variable

for (

i

= 1;

i

<= 100;

i

++)

{

sum = 0.0;

// initialize the accumulator

score = 0.0;

// initialize the loop control variable

printf

(“Enter Student ID> “);

scanf

(“%s”, ID);

while (score != SENTINEL)

{

printf

(“Enter student’s score> “);

scanf

(“%f”, &score);

if (score != -999)

sum += score;

}

// end while

}

// end for

}

// end main

Slide6

Dr. Soha S. Zaghloul

6

3. Example (1) – check your parenthesis

#include <

stdio.h

>#define SENTINEL -999

i

nt

main (void)

{ double score; // student’s score in an exam double sum; // accumulator to the scores of a single student char ID[15]; // student ID int i; // loop control variable for (i= 1; i <= 100; i

++)

{

sum = 0.0;

// initialize the accumulator

score = 0.0;

// initialize the loop control variable printf (“Enter Student ID> “); scanf (“%s”, ID); while (score != SENTINEL) { printf (“Enter student’s score> “); scanf (“%f”, &score); if (score != -999) sum += score; } // end while } // end for} // end main

p

rintf

(“Student’s total score= %f”, sum);

?Slide7

4

. Correct nesting layout

Dr. Soha S. Zaghloul

7

Figure 1

Figure 2

The brace opened first closes last: CORRECT

Figure 3

Figure 4

Intersecting braces: WRONGSlide8

Analysis:

Calculate the total scores of a single student in a single course?

Repeat the same steps for 5 coursesRepeat the whole program for 100 students.

5. Example (2)

Dr. Soha S. Zaghloul

8

Write a complete program that calculates the total scores of each of 100 students in

each of five courses

. Slide9

5. Example (2) –

cnt’d

Dr. Soha S. Zaghloul

9

Calculation of the total score of a student in one course

#include <

stdio.h

>

#define SENTINEL -999

i

nt

main (void)

{

double score;

// student’s score in an exam

double sum; // accumulator to the scores of a single student char ID[12]; //student’s ID char code[7]; // course code sum = 0.0; // initialize the accumulator score = 0.0; // initialize the loop control variable printf (“Enter Student ID> “); scanf (“%s”, ID); printf (“Enter Course Code> “); scanf (“%s”, code); while (score != SENTINEL)

{ printf

(“Enter student’s score> “);

scanf (“%f”, &score); if (score != -999)

sum += score; } // end while

printf (“Total score in course %s = %f”, code, score);

} // end main

Slide10

5. Example (2) –

cnt’d

Dr. Soha S. Zaghloul

10

Calculation of the total score of a student in

five courses

#include <

stdio.h

>

#define SENTINEL -999

i

nt

main (void)

{

double score, sum;

int course; // course counter char ID[12], code[7]; printf (“Enter Student ID> “); scanf (“%s”, ID); sum = 0.0; // initialize the accumulator for (course = 1; course <= 5; course++) { score = 0.0;

// initialize the loop control variable

printf (“Enter Course Code> “); scanf (“%s”, code);

while (score != SENTINEL) {

printf (“Enter student’s score> “);

scanf (“%f”, &score);

if (score != -999) sum += score;

} // end while printf

(“Total score for student %s in course %s = %f \n”, ID, code, score); } // end for (course=…

} // end main

Slide11

5. Example (2) –

cnt’d

Dr. Soha S. Zaghloul

11

Repeat the program for 100 students

#include <

stdio.h

>

#define SENTINEL -999

i

nt

main (void)

{

double score, sum;

int course; // course counter int student; // student counter char ID[12], code[7]; for (student = 1; student <= 100; student++) { printf (“Enter Student ID> “); scanf (“%s”, ID); sum = 0.0; for (course = 1; course <= 5; course++)

{ score

= 0.0; printf (“Enter Course Code> “);

scanf (“%s”, code); while (score != SENTINEL)

{ printf

(“Enter student’s score> “);

scanf (“%f”, &score); if (score != -999)

sum += score; }

// end while printf (“Total score for student %s in course %s = %f \n”, ID, code, score);

} // end for (course=…

}

// end for(student…} // end main Slide12

Analysis:

How to calculate the GPA?

1. The maximum score total of each course is 100  The maximum score for 4 courses is 400.

Calculate it out of 5 as follows:

Example: the student got 320 out of 400 in all courses.

maximum: 400 5 actual score: 320 GPAGPA = (320 * 5) / 400 = 4.0 out of 56. Example (3)

Dr. Soha S. Zaghloul

12

Update the program written in Example (2) so that to calculate the grade average point (GPA) of each student. The total of each course is calculated out of 100.Slide13

6

. Example (3) –

cnt’d

Dr. Soha S. Zaghloul

13

#include <stdio.h

>

#define SENTINEL -999

int

main (void){ double score, sum; int course, student; // counter double GPA; //Grade Point Average char ID[12], code[7]; for (student = 1; student <= 100; student++) { printf (“Enter Student ID> “); scanf (“%s”, ID); sum = 0.0;

for (course = 1; course <= 5; course++)

{

score

= 0.0;

printf

(“Enter Course Code> “); scanf (“%s”, code); while (score != SENTINEL) { printf (“Enter student’s score> “); scanf (“%f”, &score); if (score != -999) sum += score; } // end while printf (“Total score for student %s in course %s = %f \n”, ID, code, score); } // end for (course=… GPA = (sum * 5) / 500; // number of courses = 5 printf (“GPA of student %s = %f”, ID, GPA);

} // end for(student…

} // end main Slide14

7. self-check exercise (1)

Dr. Soha S. Zaghloul

14

Update the program written in Example (3) so that to do the following:

The user ends the courses entry using a sentinel

The user ends the data entry of students using a sentinel

Calculate the GPA of each student accordingly

Calculate the average of GPAs for all studentsSlide15

8

. self-check exercise (2)

Dr. Soha S. Zaghloul

15

Show the output displayed by the following nested loops:

for (

i

= 0;

i

< 2; ++i) { printf (“outer %4d\n”, i); for (j = 0; j < 3; ++j) { printf (“~~~~~inner%3d%3d\n”, i, j);

}

for (k = 2; k > 0; --k)

printf

(“~~~~~inner%3d%3d\n”,

i

, k);

}Slide16

9. self-check exercise (3)

Dr. Soha S. Zaghloul

16

Write a program that displays the multiplication table for numbers 0 to 9.Slide17

10. self-check exercise (4)

Dr. Soha S. Zaghloul

17

Design an interactive input loop that scans pairs of integers until it reaches a pair in which the first integer evenly divides the second.