Riemann Sums The sums you studied in the last section are called Riemann Sums When studying area under a curve we consider only intervals over which the function has positive values because area must be positive ID: 689862
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Slide1
Definite Integrals
Finney Chapter 6.2Slide2
Riemann Sums
The sums you studied in the last section are called
Riemann Sums
When studying area under a curve, we consider only intervals over which the function has positive values because area must be positiveRiemann Sums are more general and we may use any interval over which a function is continuousIntervals over which a function has negative values give the negative value of the area under the curve for that intervalWhat follows is a description of how a Riemann sum is created
2Slide3
Riemann Sums
Creating a Riemann Sum is similar to what you practiced in the previous section
For a function
over a continuous interval
, we divide the interval into
subintervals by choosing points between and , such thatWe can think of this as a set, that is called a partition of
3Slide4
Riemann Sums
The
subintervals are indexed by the right endpoint; that is, the first subinterval is
, the second subinterval is
, and the
th
subinterval is In a Riemann Sum, each subinterval can have any widthHence, the first subinterval has width , the second subinterval has width , the th subinterval has width (again, these values need not be equal)A value is selected from anywhere in each subinterval; the value from the th subinterval is denoted ; that is, is contained in
4Slide5
Riemann Sums
At each subinterval we construct a rectangle such that the height of the rectangle is
and the width is
The area of each such rectangle is
; this value can be positive, negative, or zero
Finally we take the sum of these products
The value of the sum depends on the partition and the choice of numbers and is called the Riemann Sum for on 5Slide6
Riemann Sums
Since the subintervals may have different widths, rather than allowing the number of rectangles to approach infinity, we take the longest subinterval and allow it to approach zero
This longest subinterval is called the
norm of the partition and denoted by
Regardless of the way we choose
and each value of
, all Riemann sums converge to a common value as all subintervals tend to zero 6Slide7
The Definite Integral as a Limit of Riemann Sums
DEFINITION
Let
be a function defined on a closed interval
. For any partition
of
, let the numbers be chosen arbitrarily in the subintervals .If there exists a number such thatno matter how and the ’s are chosen, then is integrable on and is the definite integral of
over
.
7Slide8
Theorem 1: Existence of Definite Integrals
THEORM
All continuous functions are integrable. That is, if a function
is continuous on an interval
, then its definite integral over
exists.
(Note that, since the definition allows us to choose any partition, this theorem allows us to go back to using regular partitions for which all subintervals have the same length.) 8Slide9
Theorem 1: Existence of Definite Integrals
The Definite Integral of a Continuous Function on
Let
be continuous on
, and let
be partitioned into
subintervals of equal length, . Then the definite integral of over is given bywhere each is chosen arbitrarily in the th subinterval. Note that, since the norm of a partition is , then
9Slide10
Terminology and Notation
Recall that we defined the derivative as
This notation is due to Leibniz, who switched from Greek letters to Roman letters to denote the derivative
He also created notation for integrals
The Greek capital sigma was chosen to represent sums, and an elongated Roman s represents the integral
10Slide11
Terminology and Notation
We read this as “the integral from
a
to
b
of
f of x, dx” or as “the integral from a to b of f of x with respect to x”.Note that and are the endpoints of the interval and are written with the greater value on top and the lesser value on the bottom (we will see later than we can reverse this with an appropriate correction) 11Slide12
Terminology and Notation
The greater value is called the
upper limit of integration
; the lesser value is the
lower limit of integration
The symbol
is called the integral signThe function f is called the integrandThe notation dx denotes that x is the variable of integration 12Slide13
Terminology and Notation
Because the value of a definite integral depends only on the function, the letter we use as the variable of integration does not matter and is called the
dummy variable
Hence, for a given function
f
over an interval
13Slide14
Terminology and Notation
Finally, a note about the difference between an indefinite integral (or antiderivative) and a definite integral:
Taking an indefinite integral results in
a family of functions that differ by a constant
Taking a definite integral results in
a real number
You will see how these are related to each other and to derivatives in the next section 14Slide15
Example 1
The interval
is partitioned into
subintervals of equal length,
. Let
denote the midpoint of the
th subinterval. Express the limitas an integral. 15Slide16
Example 1
Using
over
we get
16Slide17
Area Under a Curve
DEFINITION
If
is nonnegative and integrable over a closed interval
, then the
area under the curve
from to is the integral of from to ,(Note that we can use integrals to calculate area, and we can use area to calculate integrals.) 17Slide18
Example 2
Evaluate the integral
18Slide19
Example 2
The graph is the upper half of a circle (i.e., a semi-circle) with radius 2. Since we know that the area of semi-circle is
and that the area under the curve is
then
19Slide20
Definite Integral and Area
The value of an integral over which a continuous function
has negative values is a negative number
Of course, this interval also covers an areaBut since we want area to be a positive value, if
20Slide21
Definite Integral and Area
The value
of integrable functions that have both positive and negative values on
is
area above
-axis
area below -axis 21Slide22
Theorem 2: Constant Functions
THEOREM
If
, where
is a constant, over
, then
PROOFUsing a Riemann Sum with regular partitions, we have . The definite integral is then
22Slide23
Theorem 2: Constant Functions
THEOREM
PROOF
Note that
is a constant with respect to summation, so
We conclude that
23Slide24
Theorem 2 Viewed Geometrically
It’s easy to show that theorem 2 holds by using geometry
24Slide25
Example 3: A Train Problem
A train moves along a track at a constant velocity of 75 mph from 7:00 AM to 9:00 AM. Express its total distance traveled as an integral. Evaluate the integral using Theorem 2.
25Slide26
Example 3: A Train Problem
By Theorem 2, with
,
, and
More importantly, note the units:
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Example 3: A Train Problem
27Slide28
Example 3: A Train Problem
Let’s try to make some connections among the things you have learned
The integral is defined as the limit of a Riemann Sum when the number of rectangles approaches infinity
A Riemann Sum gives the area under a curve (or the negative value of that area if the curve lies under the x-axis)In the train problem, the integral is a distance, specifically, the distance that the train traveled from 7:00 AM to 9:00 AMBut distance traveled over a given period of time is given by the
position
function, not the velocity function
On the other hand, we know that the velocity function is obtained as derivative of the position functionWhat seems to be the relation between the definite integral ( and hence, the area under the curve) of a velocity function and the position of the train?28Slide29
Integrals on a Calculator
As we proceed through this chapter, and later on the AP exam, there will be instances where it is either very difficult or impossible to calculate a definite integral
You
must learn how to use your calculator to determine integralsOn a TI84, finding a definite integral is intuitive; just remember that this function is accessed through the MATH key29Slide30
Integrals on a Calculator
Directions for using the TI89 are below (from the TI89 manual, which can be downloaded from the internet)
30Slide31
Example 4: Evaluating Definite Integrals on a Calculator
Use a calculator to evaluate the following integrals numerically.
31Slide32
Example 4: Evaluating Definite Integrals on a Calculator
Evaluate the following integrals numerically.
32Slide33
Example 4: Evaluating Definite Integrals on a Calculator
Integrals can also be evaluated from the Graph screen. This will not only give the value of the integral between the limits of integration, but will also shade the area.
Note that
is the basic form of the Gaussian curve (or the normal curve). It turns out that it is impossible to find an explicit value for this integral. If we want to know the area under the curve, we
must
approximate it using a Riemann Sum (and the calculator does this much more efficiently that any human ever could). You will encounter many more functions like this, so knowing how to use the calculator is essential.
33Slide34
Discontinuous Integrable Functions
By Theorem 1, a function that is continuous over an interval is guaranteed to be integrable
That is, continuity implies
integrability (compare this with what we learned about derivatives: differentiability implies continuity)But it is sometimes the case that a function that has a discontinuity over some interval can still be integratedIn general, some functions with jump discontinuities or point discontinuities (but not unbounded discontinuities) are integrable
34Slide35
Example 5: Integrating a Discontinuous Function
Find
35Slide36
Example 5: Integrating a Discontinuous Function
We use the fact that the area (actually, the
net area)
under a curve over a given interval is equal to the definite integral evaluated over the interval.The given function is equal to 1 for
and to
for
; it is not defined at and this is where the discontinuity occurs. 36Slide37
Example 5: Integrating a Discontinuous Function
37Slide38
Example 5: Integrating a Discontinuous Function
Since the net area (as determined by
and knowing that the area between
and
is negative) is
, then
38Slide39
Definite Integral as an Accumulator Function
Example 1 from section 6.1 asked you to find the amount of snow that had fallen from 3 A.M. to 10:30 A.M.
This was solved by finding the area under the graph showing the rate of snowfall over this interval of time
If
represents the amount of snow that has fall by time
, then we can express this as an integral
where is the rate of snowfall at time 39Slide40
Definite Integral as an Accumulator Function
The definite integral makes it possible to build new functions called
accumulator functions
Note that this is a function of the value of
That is,
is a function of
, which is the upper limit of integration in the integralIn this case, we use a different variable of integration, , which is a dummy variable 40Slide41
Definition: Accumulator Function
DEFINITION:
If the function
is integrable over the closed interval
, then the definite integral of
from
defines a new function for , the accumulator function 41Slide42
Example 4: An Accumulator Function
Let
for
. Write an accumulator function
as a polynomial in
where
42Slide43
Example 4: An Accumulator Function
43Slide44
Example 4: An Accumulator Function
The area over the interval is a trapezoid with height
and bases
and
. The area of the trapezoid is the accumulation from 1 to
over the interval
. This area is 44Slide45
Exercise 6.2
Online
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