Luma Majeed Ahmed Fundamentals of XRD as Nanotechnology instruments lumamajeed2013gmailcom lumaahmeduokerbalaeduiq 3 under Max Planck and Sommerfeld In 1912 von Laue ID: 811737
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Slide1
In the name of
Allah
Slide2Assistance prof. Dr.
Luma
Majeed
Ahmed
Fundamentals of XRD as Nanotechnology
instruments
lumamajeed2013@gmail.com, luma.ahmed@uokerbala.edu.iq
Slide33
(
under Max Planck and
Sommerfeld
)
In
1912
, von
Laue
discovered the
diffraction
of X-rays
by crystals and won the Nobel Prize in Physics in 1914.
In
1895, Wilhelm Rontgen discovered X-rays. He won the Nobel Prize in Physics in 1901.(the range is 0.101 – 10 nm)
From Wikipedia
A Brief History of XRD
Slide44
in
1912 the
Braggs
,
father
and son
, experimentally discovered the
Bragg law of
the
X-ray
diffraction.
Bragg’s X-ray experiment led to the
discovery of the structure of DNA in 1953.Reported a book (x-rays and crystal structure) in 1915.
Sir William H. Bragg
(1862-1942)Sir William L. Bragg(1890-1971) 1918: Paul Scherrer uses X-Rays to determine crystallite size of nan-ocrystalline gold.
Paul Scherrer (1890–1969)
Slide5Law describing the
necessary condition
for diffraction
Applicable for
photons
,
electrons
and
neutrons
n: integer
Bragg’s law
Condition for efficient specular reflection
(
click for java applet
)
Bragg Diffraction Law
Slide61
3
4
2
Slide7http://prism.mit.edu/xrayThe Scherrer
Equation was published in 1918Peak width (B) is inversely proportional to crystallite size (L)B must transfer from degree to radians by multiply to
when did
Scherrer
use X-rays to estimate the crystallite size of nanophase materials?
L
= thickness of crystallite
K
= constant dependent on
crystallite(grain)
shape (0.94) is spherical(0.90) is tube or rode(0.89 or 0.85) is wire or any other shape.l = x-ray wavelength (0.15406 nmB = FWHM (full width at half max) or integral breadthqB = Bragg Angle
Scherrer’s FormulaUses of X-ray Powder Diffraction
Slide8Data Analysis
d
=
λ
/ (2 Sin
θ
B
)
λ
= 1.54 Ǻ, 2
θ
=38.3 = 1.54 Ǻ / ( 2 * Sin ( 38.3 / 2 ) ) = 2.35 ǺSimple Right!Bragg Example
L = 0.89*λ / (B Cos θB) = 0.89*1.54 Ǻ / ( 0.00174 * Cos (98.25/ 2 ) ) = 1200 Ǻ B = (0.100)x π/180 = 0.00174
Simple Right!Scherrer’s Example
λ = 1.54 Ǻ
Slide9Q/calculate the mean crystal size for TiO
2 crystal for XRD chart, where. λ= 0.15406 nm, note the crystal is spherical
L=
(111)
Slide10Thank you
For your Attention