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dtordz dOnceyouhavedonethisyoucansimplifyandintegrateasnormalFormoreinformationonparameterisationofcurvesrefertothelecturenotes. 2cos( )(S.1)betweentheaspectratio,thecontactangle45degoftheunderlyingsubstrate,andthe Thecharactercontributionsare:E 3 C2 1 C3 0 C4 1 C5 1+p 5 2 C6 2  1 i 3 S3 2 S4 1 S6 0 Cn 1+2cos(2 n) Sn 1+2cos(2 n)Thenredbecomes0red=h21;0;1;3;3;3;1;0;5;3iRepeatingthedotproduct(andnorm AB=a c;cosA=AC AB=b c;andsinB=AC AB=b c;cosB=BC AB=a c:Applyingtheseformulaetotheright-angledtriangleABC,wherea=1;b=p 3;c=2,weinferthatAhas30degreesor=6radians,Bhas60degreesor=3radians,andChas90degr 1+x=1+x=2+O(x2):E(x;l)=E0"cos 2l + lxd 22!+cos 2l + lx+d 22!#=2E0cos2l +2 lx2+d2 4cos2d lxwherewealsousedcos+cos=2cos+ 2cos 2.Theoscillatorydependenceonxofthemeasur 2cos(k^x)(jeihgj+jgihej);(B.4)91 Suzy Jackson – based on previous talks by Alex Dunning & Graeme Carrad. The Basic Structure of a typical Radio Telescope. CSIRO.. Receiver Systems for Radio Astronomy. Ours look like this.... cscucosu=1 secutanu=1 cotucotu=1 tanucscu=1 sinusecu=1 cosu cosucotu=cosu sinuCo-FunctionIdentitiessin( 2�u)=cosucos( 2�u)=sinutan( 2�u)=cotucot( 2�u)=tanucsc Fourier transform of x(t) = 3sinc. 2. (4t-2)cos(2. p. 30t). Find the energy of x(t). Solution. FT of sinc. 2. (t) = . L. (f) (duality). Let z(t) = sinc. 2. (t-2), Z(f) = . L. (f)e. -j4. p. f. .. Let y(t) = z(4t) = sinc.