/
Volume and surface area of a sphere Volume and surface area of a sphere

Volume and surface area of a sphere - PowerPoint Presentation

kittie-lecroy
kittie-lecroy . @kittie-lecroy
Follow
358 views
Uploaded On 2018-11-02

Volume and surface area of a sphere - PPT Presentation

Warm Up Find each measurement 1 the radius of circle M if the diameter is 25 cm 2 the circumference of circle X if the radius is 425 in 3 the area of circle T if the diameter is 26 ft ID: 709673

volume area sphere surface area volume surface sphere find figure composite radius hemisphere cylinder substitute terms circle give great

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "Volume and surface area of a sphere" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

Volume and surface area of a sphereSlide2

Warm Up

Find each measurement.

1. the radius of circle M if the diameter is 25 cm2. the circumference of circle X if the radius is 42.5 in.3. the area of circle T if the diameter is 26 ft 4. the circumference of circle N if the area is 625 cm2

12.5 cm

85 in.

169 ft2

50

cmSlide3

Learn and apply the formula for the volume of a sphere.

Learn and apply the formula for the surface area of a sphere.

ObjectivesSlide4

sphere

center of a sphere

radius of a spherehemispheregreat circleVocabularySlide5

A

sphere

is the locus of points in space that are a fixed distance from a given point called the center of a sphere. A radius of a sphere connects the center of the sphere to any point on the sphere. A hemisphere is half of a sphere. A great circle divides a sphere into two hemispheresSlide6

The figure shows a hemisphere and a cylinder with a cone removed from its interior. The cross sections have the same area at every level, so the volumes are equal by Cavalieri’s Principle. You will prove that the cross sections have equal areas in Exercise 39.

The height of the hemisphere is equal to the radius.Slide7

V

(hemisphere) =

V(cylinder) – V(cone)The volume of a sphere with radius r is twice the volume of the hemisphere, or .Slide8
Slide9

Example 1A: Finding Volumes of Spheres

Find the volume of the sphere. Give your answer in terms of

.

= 2304

 in3

Simplify.

Volume of a sphere.Slide10

Example 1B: Finding Volumes of Spheres

Find the diameter of a sphere with volume 36,000

 cm3.

Substitute 36,000

 for V.

27,000 = r3r = 30

d

= 60 cm

d = 2r

Take the cube root of both sides.

Volume of a sphere.Slide11

Example 1C: Finding Volumes of Spheres

Find the volume of the hemisphere.

Volume of a hemisphere

Substitute 15 for r.

= 2250

m

3

Simplify.Slide12

Check It Out!

Example 1

Find the radius of a sphere with volume 2304 ft

3.Volume of a sphere

Substitute for V.

r = 12 ft

Simplify.Slide13

Example 2: Sports Application

A sporting goods store sells exercise balls in two sizes, standard (22-in. diameter) and jumbo (34-in. diameter). How many times as great is the volume of a jumbo ball as the volume of a standard ball?

standard ball:

jumbo ball:

A jumbo ball is about 3.7 times as great in volume as a standard ball.Slide14

Check It Out!

Example 2

A hummingbird eyeball has a diameter of approximately 0.6 cm. How many times as great is the volume of a human eyeball as the volume of a hummingbird eyeball?

hummingbird:

human:

The human eyeball is about 72.3 times as great in volume as a hummingbird eyeball. Slide15

In the figure, the vertex of the pyramid is at the center of the sphere. The height of the pyramid is approximately the radius

r

of the sphere. Suppose the entire sphere is filled with n pyramids that each have base area B and height r.Slide16

4

r2 ≈ nBIf the pyramids fill the sphere, the total area of the bases is approximately equal to the surface area of the sphere S, so 4r2 ≈

S. As the number of pyramids increases, the approximation gets closer to the actual surface area.Slide17
Slide18

Example 3A: Finding Surface Area of Spheres

Find the surface area of a sphere with diameter 76 cm. Give your answers in terms of

.

S = 4r2

S = 4(38)2 = 5776

cm2

Surface area of a sphereSlide19

Example 3B: Finding Surface Area of Spheres

Find the volume of a sphere with surface area 324

 in2. Give your answers in terms of .

Substitute 324

 for S.

324 = 4r2

r

= 9

Solve for r.

Substitute 9 for r.

The volume of the sphere is 972

in

2

.

S

= 4

r

2

Surface area of a sphereSlide20

Example 3C: Finding Surface Area of Spheres

Find the surface area of a sphere with a great circle that has an area of 49

 mi2.

Substitute 49

for A.49

 = 

r

2

r

= 7

Solve for r.

S

= 4

r

2

= 4

(7)

2

= 196

mi

2

Substitute 7 for r.

A

=

r

2

Area of a circleSlide21

Check It Out!

Example 3

Find the surface area of the sphere.

Substitute 25 for r.

S = 2500

 cm2S = 4r2

S

= 4

(25)

2

Surface area of a sphereSlide22

Example 4: Exploring Effects of Changing Dimensions

The radius of the sphere is multiplied by . Describe the effect on the volume.

original dimensions:

radius multiplied by :

Notice that . If the radius is multiplied by , the volume is multiplied by , or .Slide23

Check It Out!

Example 4

The radius of the sphere is divided by 3. Describe the effect on the surface area.

original dimensions:

dimensions divided by 3:

The surface area is divided by 9.

S

= 4

r

2

= 4

(3)

2

=

36

m

3

S

= 4

r

2

= 4

(1)

2

=

4

m

3Slide24

Example 5: Finding Surface Areas and Volumes of Composite Figures

Find the surface area and volume of the composite figure. Give your answer in terms of

.

Step 1

Find the surface area of the composite figure.

The surface area of the composite figure is the sum of the curved surface area of the hemisphere, the lateral area of the cylinder, and the base area of the cylinder. Slide25

Example 5 Continued

The surface area of the composite figure is

L

(cylinder) = 2rh = 2(6)(9) = 108

in2B(cylinder) = r

2 = (6)2 = 36 in2

72

+ 108

 +

36

= 216

in

2

.

Find the surface area and volume of the composite figure. Give your answer in terms of

.Slide26

Step 2

Find the volume of the composite figure.

Example 5 Continued

Find the surface area and volume of the composite figure. Give your answer in terms of .

The volume of the composite figure is the sum of the volume of the hemisphere and the volume of the cylinder.

The volume of the composite figure is 144 + 324 = 468

in

3

.

Slide27

Check It Out!

Example 5

Find the surface area and volume of the composite figure.

Step 1

Find the surface area of the composite figure.

The surface area of the composite figure is the sum of the curved surface area of the hemisphere, the lateral area of the cylinder, and the base area of the cylinder. Slide28

Check It Out!

Example 5 Continued

The surface area of the composite figure is

Find the surface area and volume of the composite figure.

L

(cylinder) = 2rh = 2(3)(5) = 30 ft2

B

(cylinder) =

r

2

=

(3)

2

= 9

ft

2

18

+ 30

 +

9

= 57

ft

2

.Slide29

Step 2

Find the volume of the composite figure.

Find the surface area and volume of the composite figure.

Check It Out!

Example 5 Continued

The volume of the composite figure is the volume of the cylinder minus the volume of the hemisphere. V = 45 – 18 = 27

ft

3Slide30

Lesson Quiz: Part I

Find each measurement. Give your answers in terms of

.1. the volume and surface area of the sphere 2. the volume and surface area of a sphere with great circle area 36 in23. the volume and surface area of the hemisphere

V

= 36 cm3; S = 36 cm2

V

=

288

in

3

;

S

=

144

in

2

V

=

23,958

ft

3

;

S

=

3267

ft

2Slide31

Lesson Quiz: Part II

4.

A sphere has radius 4. If the radius is multiplied by 5, describe what happens to the surface area.

5. Find the volume and surface area of the composite figure. Give your answer in terms of .

The surface area is multiplied by 25.

V = 522 ft3; S = 267 ft2