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Ideal Gas Equation  pV = Ideal Gas Equation  pV =

Ideal Gas Equation pV = - PowerPoint Presentation

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Uploaded On 2018-11-10

Ideal Gas Equation pV = - PPT Presentation

nRT The Ideal Gas Equation Objective To be able to use the Ideal Gas Equation pV nRT Outcomes To know the ideal gas equation To use the ideal gas equation To rearrange the ideal gas equation ID: 726537

ideal gas volume equation gas ideal equation volume pressure temperature nrt mass molar moles kpa 100 syringe calculate liquid

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Slide1

Ideal Gas Equation pV= nRTSlide2

The Ideal Gas Equation

Objective:

To be able to use the Ideal Gas Equation (

pV

=

nRT

)

Outcomes:

To know the ideal gas equation

To use the ideal gas equation

To rearrange the ideal gas equation

To use the ideal gas equation to find molecular

formuale

of gases and volatile liquidsSlide3

Molar volumes of gases

If the temperature and pressure are fixed at convenient standard values, the molar volume of a gas can be determined.

Standard temperature is 273 K

(0

o

C) and

pressure is 101.3 kPa.

At standard temperature and pressure (s.t.p) 1 mole of any gas occupies a volume of 22.4 dm3. This is the molar gas volume.

At room temperature and pressure (

r.t.p) 1 mole of any gas will occupy a volume of 24 dm3 mol-1 . R. T.P is 293 K (20o C) and 101.3 kPa. This is the molar gas volume.

Last lesson we learnt thisSlide4

Ideal gas equation

The

ideal gas equation

relates pressure, volume, number of moles and temperature for a gas.

pV

=

nRT

p

= pressure in Pa

V = volume in m3

How is the number of moles in a gas at other temperatures and pressures calculated?

n

= number of moles

R

= gas constant: 8.31JK

-1

mol-1T = temperature in Kelvin

A gas that obeys this law under all conditions is called an

ideal gas

.Slide5

Ideal gas equation: converting units

It is very important when using the ideal gas equation that the values are in the correct units.

The units of pressure, volume or temperature often need to be converted before using the formula.

Pressure

to convert

kPa

to Pa:

× 1000

Volume

to convert dm

3

to m

3

:

to convert cm

3

to m

3:

÷

1000 (10

3

)

÷

1

000

000 (106)

Temperatureto convert °C to Kelvin:

+ 273Slide6

Starters for 10Slide7

Finding the molecular formula of a gas using

pV

=

nRT

At a temperature of 60oC and a pressure of 250 kPa, a gaseous hydrocarbon occupied a volume of 1100 cm3

and had a mass of 1.60 g. Find the molecular formula of the hydrocarbon.n = pV/RT = (250 x 103) x (1.1 x 10

-3) / (8.31 x 333) = 0.0993 moles0.0993 moles = 1.60 g so Mr= 1.60 / 0.0993 = 16.1 gMolar mass is 16 gThe only hydrocarbon with a molar mass of 16 is methane, CH4Slide8

Finding the molecular formula of a gas using

pV

=

nRT

A cylinder of gas X weighed 242.487 g. After it was used to release some gas into a gas syringe, the cylinder weighed 242.313 g.Calculate the mass of the gas releasedThe reading on the gas syringe was 75 cm3

, the temperature was 27oC and the atmospheric pressure was 100 kPa. Calculate the number of moles of gas released into the syringe.Use your answers to parts a) and b) to calculate the Mr of the gas.

Old AQA page 49Slide9

Find the molar mass of a volatile liquidA volatile liquid evaporates easily.

You can use the ideal gas equation to find the molar mass of an unknown volatile liquid.

Put a known

mass

of the liquid in a flask, then attach it to a sealed gas syringe . Gently warm the apparatus in a water bath until the liquid completely evaporates.Record the volume of gas in the syringe and the temperature of the water bath

Use the ideal gas equation to work out how many moles of the liquid were in your sample and the equation molar mass = mass / moles to calculate the molar massSlide10

Example

Calculate the volume in cm

3

occupied by 0.0200

mol of oxygen in 298 K and 100 kPa pressure.pV =

nRT=4.95 x 10-4 m3

Volume = 4.95 x 10-4 x 106 = 495 cm3(x 1000 000)Slide11

ExampleCalculate the volume which 2.2 g of carbon monoxide would occupy at a temperature of 20

o

C and a pressure of 6500 Pa.

n = 2.2 / 28

pV = nRT = 6500 x V = 0.07857 x 8.31 x 293V= 0.07857 x 8.31 x 293 / 6500

V =0.02943 m3 = 29430 cm3= 29.43 dm3Slide12

Example

What is the volume of 2.50 g of hydrogen gas at a temperature of 293 K and a pressure of 100

kPa

Moles = 2.50/2 = 1.25

pV = nRT V= nRT

/P= 1.25 x 8.31x 293 / 100 000= 3043.538 / 100 000=0.0304353 m3 = 30435 cm

3 = 30.4 dm3Slide13

The Ideal Gas Equation

Objective:

To be able to use the Ideal Gas Equation (

pV

= nRT)Outcomes:To know the ideal gas equation

To use the ideal gas equationTo rearrange the ideal gas equationTo use the ideal gas equation to find molecular formuale of gases and volatile liquids