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Thermochemical Equations Thermochemical Equations

Thermochemical Equations - PowerPoint Presentation

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Uploaded On 2018-01-10

Thermochemical Equations - PPT Presentation

Using the grid to solve for desired quanties Recap An exothermic change is a reaction that releases energy energy can be thought of as a product An endothermic change is one in which the energy must be added for the reaction to occur energy can be thought of as a reactant ID: 622056

mole energy rxn enthalpy energy mole enthalpy rxn gram exothermic c6h12o6

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Slide1

Thermochemical Equations

Using the grid to solve for desired

quanties

Slide2

Recap

An

exothermic

change is a reaction that releases energy: energy can be thought of as a product

An

endothermic

change is one in which the energy must be added for the reaction to occur: energy can be thought of as a reactant

Enthalpy (H)

is the energy (heat) content of a system at constant pressure

You cannot measure the actual energy or enthalpy of a substance, but you can measure the change in enthalpy ∆

H

rxn

.

 

Slide3

Complete the table:

Type of Reaction

Sign of ∆

H

rxn

Which has more energy: reactants or products?Exothermic  Endothermic  

-

+

reactants

products

Exothermic

EndothermicSlide4

Chemistry problems involving

enthalpy

changes are similar to the dimensional analysis problems. 

The amount of energy that is absorbed or released in a reaction depends on the number of moles of reactants involved. 

Example Problem:

How much heat will be released if 1.0 gram of hydrogen peroxide H2O2 decomposes? 2H2O2    2H2O  +  O2 +190 kJ  

 

1.0 gram H2O2

______ gram H

2

O2

34.02

1 mole H2O2

__mole gram H

2

O

2

2

________ kJ

190

energy @ end of

rxn

= exothermic

-

=

-

2.7924kJ

=

-

2.8 kJSlide5

1.  How much heat is absorbed during photosynthesis when 9.22 grams of

glucose

C

6

H

12O6 is produced? 6CO2   +    6H2O  +2803 kJ   C6H12O6    +  6O2  9.22 grams C6H12O6_______ grams C6H12O6180.181 mole C6H12O6____ mole C6H12O

6

1

______ kJ

2803

energy @ beggining of

rxn = endothermic

+

=143.4324564 kJ

=143 kJ Slide6

2.  How many moles of NO

2(g)

is dissolved in excess water when 177 kJ of energy is released?

3NO

2 +   H2O    2HNO3   +  NO + 138 kJ 177 kJ_______kJ138

energy @ end of rxn = exothermic

-

3 mole NO

2

=

-

3.84783 mole NO

2

=

-

3.85 mole NO

2