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First look at mass constraint First look at mass constraint

First look at mass constraint - PowerPoint Presentation

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Uploaded On 2016-06-30

First look at mass constraint - PPT Presentation

How simple can it be Two decays i pi 0 gt g g ii K 0 gt pi pi Mother particle momenta P 1 2 4 8 16 GeV Daughter momentum cut p1 p2 gt 05 ID: 383877

recon refit gev ruth refit recon ruth gev mass simple scaling true weighting scale invariant momentum constrain daughters pi0

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Presentation Transcript

Slide1

First look at mass constraint

[How simple can it be?]

Two decays:

i

)

pi

0

-> g

g

ii) K

0

-> pi+ pi-

- Mother particle

momenta

: P = 1, 2, 4, 8, 16

GeV

- Daughter momentum cut: p1, p2 > 0.5

GeV

- Simple ATLAS resolution smearing

- Very simple refitting of mass:

change p1 and p2 by the

same scale

(angular resolution not considered)

Note that a complete treatment involves relatively complex and slow chi-square fitting! Slide2

Plots

.

1. Mother particle momentum resolution (r)

for truth

, reconstructed, and

refitted daughters

r = (

p

meas

p

true

) /

p

true

This will hopefully improve after refitting

2.

Invariant

mass

for truth

, reconstructed, and

refitted daughters.

After refitting

M

should equal

MtruthSlide3

i

)

pi

0

-> g

g

M

2

= (E

1

+E

2

)

2

– P

2

=>

M

2

= 2 E

1

E

2

( 1 –

cos

A )

for

massless

photons

=>

M

2

= p

1

p

2

k

p

=

E

, and we wont change

A

“Refit”: simply scaling

p1

and

p2

by

M

pi0

/

M

will constrain the invariant mass to

M

pi0

Here we assume p

1

p

2

(true-

ish

given that we have a 0.5

GeV

momentum cut) and so we don’t care too much about weighting the scale for different resolutions.Slide4

P = 1

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide5

P = 2

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide6

P = 4

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide7

P = 8

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide8

P = 16

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide9

ii) K

0

-> pi+ pi-

M

2

= (E1+E2

)2 – P2

=> M2 = 2 E1 E

2 ( 1 – cos A )

for massless pions!!!

=> M2 = p

1

p

2

k

p

=

E!!

, and we wont change

A

“Refit”: simply scaling

p1

and

p2

by

M

K0

/

M

will constrain the invariant mass to

M

K

0

Here we assume p

1

p

2

(true-

ish

given that we have a 0.5

GeV

momentum cut) and so we don’t care too much about weighting the scale for different resolutions.

BUT we assume

massless

pions

! So this will not work so well.Slide10

P = 1

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide11

P = 2

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide12

P = 4

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide13

P = 8

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide14

P = 16

GeV

T

ruth

T

ruth

Recon

Recon

Refit

RefitSlide15

Conclusion

Simple scaling works well for the pi0 because E

1

and E

2

are similar (after energy cuts).

Weighting the scale seems to be not very important. - But I didnt

compare yet with the standard mass constraint method (Ahmet?) - Try a simple weighting scheme?

When we have massive daughters this method is not so good (the invariant mass doesn’t constrain properly). Try adding the mass effects in a simple way?

Ahmet does the scaling in the c.o.m

frame, again without weights This works well!