Solution Let 14 6 0 Note that 0 and 1 2 0 therefore based on the Intermediate Value Theorem sinc is continuous there is 0 1 such that 0 Let 0 1 with 0 0 Let 0 5 and we have 6250 0 the same sign as therefore 0 5 1 and repeat 0 75 Th ID: 38716
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