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D0 Now: p.338, #16 D0 Now: p.338, #16

D0 Now: p.338, #16 - PowerPoint Presentation

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D0 Now: p.338, #16 - PPT Presentation

Find the exponential function whose graph passes through the two points Initial value Equation Other point Function Applications of Exponential Change Section 64b Newtons Law of Cooling ID: 464885

skater sec temperature coast sec skater coast temperature equation law 000 newton

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Slide1

D0 Now: p.338, #16

Find the exponential function whose graph passesthrough the two points.

Initial value:

Equation:

Other point:

Function:Slide2

Applications of Exponential Change

Section 6.4bSlide3

Newton’s Law of Cooling

Suppose that you just took a delicious hot pocket outof the microwave. The tasty treat will gradually coolto the temperature of the surrounding air…As it turns out, the rate at which the hot pocket’stemperature is changing at any given time is proportional to the difference between its temperature and

the temperature of the surrounding medium!!! This leads us to derive

NEWTON’S LAW OF COOLING(which, incidentally, works for warming as well)Slide4

Let T be the temperature of the object in question at time

t,and T be the surrounding temperature. Then:

s

Since

,

we can rewrite the equation:

By the law of exponential change, the solution isSlide5

Newton’s Law of Cooling

where T is the temperature at time

t

= 0.

0Slide6

Newton’s Law of Cooling

A hard-boiled egg at 98 C is put in a pan under running 18 C

water to cool. After 5 minutes, the egg’s temperature is found tobe

38 C. How much longer will it take the egg to reach 20 ?

Define Variables:

Law of Cooling:

Substitute:Slide7

Newton’s Law of Cooling

A hard-boiled egg at 98 C is put in a pan under running 18 C

water to cool. After 5 minutes, the egg’s temperature is found tobe

38 C. How much longer will it take the egg to reach 20 ?

To find

k

, use the point (5, 38):

The Final Equation:Slide8

Newton’s Law of Cooling

A hard-boiled egg at 98 C is put in a pan under running 18 C

water to cool. After 5 minutes, the egg’s temperature is found tobe

38 C. How much longer will it take the egg to reach 20 ?

Solve analytically:

After about

13.305

minutes,the egg will reach 20 degrees C.Slide9

Resistance Proportional to Velocity

In many situations, the resistance encountered by amoving object (i.e., from friction) is proportional to theobject’s velocity…That is, the slower the object moves, the less its forward

progress is resisted by the air through which it passes…

To model such a situation, we’ll start with Newton’sSecond Law of Motion…Slide10

Resistance Proportional to Velocity

The resisting force opposing the motion:

Force = mass x acceleration

If this force is proportional to the velocity, then:

or

This is a differential equation of exponential change…

The solution:Slide11

Guided Practice

First, the general model:

For a 50-kg ice skater, the

k

in the previous equation

is about

2.5 kg/sec. How long will it take the skater to

coast from 7 m/secto 1 m/sec? How far will the skater coast before coming to acomplete stop?Slide12

Guided Practice

For a 50-kg ice skater, the

k

in the previous equation is about2.5 kg/sec. How long will it take the skater to coast from 7 m/secto 1 m/sec? How far will the skater coast before coming to a

complete stop?Now, we want the value of t

when v = 1.

The skater will reach 1 m/sec

from 7 m/sec after about

38.918

sec of coastingSlide13

Guided Practice

For a 50-kg ice skater, the

k

in the previous equation is about2.5 kg/sec. How long will it take the skater to coast from 7 m/secto 1 m/sec? How far will the skater coast before coming to a

complete stop?To find distance, we need the integral of velocity:Slide14

Guided Practice

For a 50-kg ice skater, the

k

in the previous equation is about2.5 kg/sec. How long will it take the skater to coast from 7 m/secto 1 m/sec? How far will the skater coast before coming to a

complete stop?Assuming s

= 0 when t = 0, we haveSlide15

Guided Practice

For a 50-kg ice skater, the k in the previous equation is about2.5

kg/sec. How long will it take the skater to coast from 7 m/secto 1 m/sec? How far will the skater coast before coming to a

complete stop?

Finally, for distance:

Find

Mathematically,

s

never quite reaches 140. But

for all practical purposes, the skater comes to a

complete stop after traveling 140 m…Slide16

A General Pattern

The distance traveled by a moving object thatencounters resistance proportional to its velocity:

The total distance traveled by this object:Slide17

Guided Practice

Suppose a battleship has mass around 51,000 metric tons(51,000,000

kg) and a k value of about 59,000 kg/sec. Assumethe ship loses power when it is moving at a speed of 9 m/sec.

(a)

About how long will it take the ship’s speed to drop to 1 m/sec?

The ship will reach 1 m/sec in

a

bout 1899.296 seconds, or

in about 31.655 minutesSlide18

Guided Practice

Suppose a battleship has mass around 51,000 metric tons(51,000,000

kg) and a k value of about 59,000 kg/sec. Assumethe ship loses power when it is moving at a speed of 9 m/sec.

(b)

About how far will the ship coast before it is dead in the water?

The ship will coast for a distance of about

7779.661 meters, or 7.780 kilometers

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