Mesh Analysis Read Alexander amp Sadiku Sections 34 to 310 Homework 4 and Lab 4 due next week Quiz next week Mesh Analysis Weve seen that nodal analysis is a systematic method for analyzing circuits ID: 549389
Download Presentation The PPT/PDF document "EGR 2201 Unit 4" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.
Slide1
EGR 2201 Unit 4Mesh Analysis
Read Alexander &
Sadiku
, Sections
3.4 to 3.10.
Homework #4 and Lab #4 due next week.
Quiz next week.Slide2
Mesh Analysis
We’ve seen that nodal analysis is
a systematic method for analyzing circuits.
It’s based on Kirchhoff’s
current law (KCL
).
It gives us the node voltages in
a circuit
.
Once we have these node voltages, we can find any other voltage or current.
Mesh analysis
is another
systematic method for analyzing circuits.
It’s
based on Kirchhoff’s
voltage law
(
KVL)
.
It
gives us the
mesh currents in
a circuit
.
Once we have these
mesh currents
, we can find any other
current or voltage.Slide3
Meshes Versus Loops
Recall that a
loop
is any closed path in a circuit.
Example: This circuit has six loops.
A mesh is a loop that does not contain any other loop within it.Example: The circuit above has three meshes.Slide4
Mesh Currents Versus Branch Currents
A
mesh current
is a current that we imagine to travel around a mesh.
You can imagine them to travel in either direction, but most people assume clockwise.
A branch current is a current that passes through a branch (i.e., an element).If we know the values of all the mesh currents in a circuit, we can compute any branch current.In many diagrams, our textbook uses:Lowercase i and a looping arrow for mesh currents
Uppercase
I
and a
straight arrow
for
branch currentsSlide5
Example: Mesh Currents Versus Branch Currents
In this circuit, the
mesh currents are
labeled
i
1 and i2. The branch currents
are labeled
I
1
,
I
2
,
and
I
3
.
Suppose you were
given the values of
the mesh currents.
Then you could easily
compute the branch currents, since:
I
1
=
i
1
and
I
2
=
i
2
and
I
3
=
i
1
i
2
Slide6
Steps in Performing Mesh Analysis on a Circuit with No Current Sources
Given
a circuit with
n
meshes, without current sources, follow these steps:Assign mesh currents i1, i2, …, in to the n meshes.Apply KVL to each of the n meshes. Use Ohm’s law to express the voltages in terms of mesh currents. Then simplify the equations.Solve the resulting n simultaneous equations to obtain the unknown mesh currents.Slide7
Example: Step 1 (Assign the Mesh Currents)
Consider this circuit
from the book’s
Example 3.5.
Step 1 has
already been performed for us, since the mesh currents are labeled i1 and i2.If an assumed current direction is wrong, that’s no problem. The math will still work out.Slide8
Apply KVL (and
Ohm’s law) to
mesh 1:
15 + 10
i
2 = 5i1 + 10i1 + 10Apply KVL (and Ohm’s law) to mesh 2: 10 + 10i1 = 10i2 + 6i2 + 4i2Example: Step 2 (Apply KVL)Part 1 of 2Slide9
Next we use algebra to simplify our equations.
For mesh 1:
15
+ 10
i
2 = 5i1 + 10i1 + 10 becomes For mesh 2: 10 + 10i1 = 10i2 + 6i2 + 4i2 becomes
We now have our two equations in two variables.
Example: Step 2 (Apply KVL)
Part
2
of
2Slide10
Next we use any of our methods—substitution, Cramer’s rule, matrix inversion, MATLAB—to solve our two
equations in two variables.
Using MATLAB, the solution to
is
i
1 = 1 A and i2 = 1 A Example: Step 3 (Solve)Slide11
Mesh analysis has
given us the values
of the mesh
currents
i
1 and i2. We can find all other currentsand voltages in the circuit once we know these mesh currents.Example: Knowing that i1 = 1 A and i2 = 1 A, how would we find I3?Example: Extending the AnalysisSlide12
Review: Steps in Performing Mesh Analysis on a Circuit with No Current Sources
Given
a circuit with
n
meshes, without current sources, follow these steps:Assign mesh currents i1, i2, …, in to the n meshes.Apply KVL to each of the n meshes. Use Ohm’s law to express the voltages in terms of mesh currents. Then simplify the equations.Solve the resulting n simultaneous equations to obtain the unknown mesh currents.Slide13
MATLAB’s
format
command
MATLAB’s
format
command lets you control the way MATLAB displays answers (for example, whether to use engineering notation in answers).For a list of options, type help format in MATLAB or see this web page.By default, the format is set to short.Usually this works well, but sometimes format shortg or format shorteng works better. See example on next slide.Slide14
Much nicer!
Example: MATLAB’s
format
command
This is telling you to multiply each number displayed below by
0.001. Ugly! Nicer! Slide15
As described above, our mesh-analysis procedure applies only to circuits
without
current sources.
But it’s not hard to extend the procedure to circuits
with
current sources.The way you handle a current source depends on whether the source is located in only one mesh or is shared by two meshes….What About Circuits with Current Sources?Slide16
Case 1: A Current Source Located in Only One Mesh
A current source
located in only
one mesh
is easy to
handle, because itimmediately reveals the mesh current in that mesh.
Example: In the circuit shown, we can immediately see that
i
2
=
5
A.Slide17
Case 2: A Current Source Shared by Two Meshes
A current source
shared by two
meshes is
trickier.
To handle it,
we create a
supermesh
by excluding the
current source
and any elements
in series with it.Slide18
We apply KVL
and
KCL to the super-
mesh to get two
equations.Example: Here, KVL around the
supermesh
gives
20 =
6
i
1
+ 10
i
2
+ 4
i
2
And KCL
gives
i
2 = i1 +6How to Handle a SupermeshSlide19
We Still Get
Enough Equations
If this circuit did
not have a super-
mesh, we would
get one equation by applying KVLto mesh 1 and another by applying KVL to mesh 2.
With the
supermesh
, we get one equation
by applying
KCL and another
by applying
KVL
to
the
supermesh
.Slide20
Nodal Analysis and Mesh Analysis “By Inspection”
With practice, you’ll become good at writing down the set of simultaneous equations that describe a circuit using either nodal or mesh analysis.
As discussed in Section 3.6, there is a shortcut way to write down the equations quickly by looking at a circuit without even thinking in terms of KCL or KVL.
I won’t expect you to learn this shortcut method, but you can use it if you wish.Slide21
Which Should You Use: Nodal Analysis or Mesh Analysis?
Most circuits can be analyzed using either method, and
the
results from the two methods will agree with each other.
But as discussed in Section 3.7, in some cases you’ll get the answer with less work if you’re smart about picking the better method for your circuit.
See next slide for example.Slide22
Examples: Should You Use Nodal Analysis or Mesh Analysis?
Recommendation:
Use nodal analysis for circuits with fewer nodes than meshes, and use mesh analysis
for circuits with fewer
meshes than nodes.
How many nodes does this circuit have?
How many meshes?Slide23
Dot Convention to Show Intersections
Before we look at the next example, note that our textbook usually does not follow the widespread convention of using a dot to show intersection points between wires.
Examples from
Multisim
:
If you saw this in Multisim, you would know that these two wires cross without intersecting.
If you saw this in
Multisim
, you would know that
these wires intersect.Slide24
More Examples: Should You Use Nodal Analysis or Mesh Analysis?
As also noted in Section 3.7, mesh analysis cannot be applied to
nonplanar
circuits.
A circuit is
planar if it can be drawn on a plane with no branches crossing each other; otherwise it is nonplanar.We will only deal with planar circuits in this course.Slide25
Example of a Planar Circuit
This circuit, in which branches cross, can be redrawn with no crossing branches (as on the right below), so it is a planar circuit.
Crossing branches:
No intersections here.Slide26
Example of a
Nonplanar
Circuit
There is no way
to
redraw this circuit without crossing branches, so it is a nonplanar circuit. So you cannot use mesh analysis on this circuit.Crossing branches:No intersections here.
Crossing branches:
No intersections here.Slide27
The Rest of Today’s Class
Use the remaining time today to:
Finish Lab #4.
Review
Homework #3
(particularly the super-node problems, Problems 3.13 and 3.18) and make sure you understand how to do them.Work on Homework #4, which is due at our next class.In preparation for the Midterm Exam, review earlier homeworks and practice sheets, and work on your crib sheet.