PPT-An Empirical Characterization of

Stream Programs and its Implications for Language and Compiler Design Bill Thies 1 and Saman Amarasinghe 2 1 Microsoft Research India 2 Massachusetts Institute of Technology PACT 2010 What Does it Take to. Characterization. . – . the way an author reveals the special qualities and personalities of a character in a story, making the character believable. . Analyzing Character Traits. We try to figure out what a character in a book is like by paying attention to the clues the author gives us. This is called “. David L. . Baumer. , NC State University. Academy of Legal Scholars in Business, August 2010 Annual Conference. Empirical Research. Although not all legal scholarship requires empirical research, clearly in some instances, empirical research enhances the credibility of contentions made in scholarly legal writings. Do Now. Honors/Warnings/Transitions. Complete self-evaluation.. Review as class & share comments. Do Now. Split into partners. Review active reading strategies. Name THREE things you might annotate for. . Molecular Formulas. Let’s use those mole conversions!. Empirical formula . tells you the lowest ratio of atoms within a molecule. Molecular formula . tells you the actual ratio of atoms within a molecule. You should know this for the quiz!. Empirical and Molecular Formulae. Empirical Formula. If needed, change % to g.. Do . a molar conversion to change from . g. mol. Divide each of these numbers by the smallest number. Objectives. To learn how to work out the percentage composition by weight of a compound. To use percentage composition to work out empirical formulae. Percentage compositions. This means what percentage of each element is present in a compound, and therefore tells you what masses of each element are present in any given mass of a compound. . Chemistry GT 3/20/15. Drill. Calculate the percent composition of Na. 2. SO. 4. .. HW: Molecular Formula WS (pg. 4). MM. =142.05 . g. /mol. 32.37% Na, 22.58% S, 45.05% O. Chem. Joke of the Day. The photon checked into a hotel. What did it say when the bellhop asked for its bag?. The Mole. Chemist’s counting number. amount. of a substance . 1 mole is equal to 6.022 x 10. 23. atoms or particles or molecules (Avogadro’s number). There are always 6.022 x 10. 23 . particles in . Percent Composition. Percent . Composition – . the . percentage . by mass of . each . element in a . compound (*note: not the ratio of elements in the compound). Law of Definite Proportions . – compounds always contain the same proportions of elements by mass.. Percent Composition. Breaks down the amount of an element in a compound by percentage. Total mass of element / total mass of compound. Result will always be a decimal. Multiply by 100 to get the final percentage. Percent Composition. ~percent by mass of atoms present in a compound. = (mass of atom). . (total molar mass) x 100. water is . 88.81 . % Oxygen and . 11.19 . % Hydrogen. O- 16.00/18.016 x 100 = . 88.81 . Daniel Friedman, R. . Mark . Isaac, . Duncan . James . , and Shyam Sunder. Fifth . LeeX. International Conference on . Theoretical and Experimental Macroeconomics . Barcelona GSE Summer Forum, . Universitat. Approach. Derive new empirical parameters to represent (1) the dynamic evolution of SOAs in smog chambers as a function of NO. x. -dependent multigenerational chemistry and (2) losses of gases and particles to walls. We have discussed theoretical analysis of algorithms mostly in terms of asymptotic worst case and average case big O complexities. What we often care about even more is what will our typical or average case complexity be for our actual problem of interest.