Gausss Law 32 Is that the finger Happenings Wednesday You should be finished with the Electric Field and today we start Gausss Law Friday Yup more Gauss and oh yes a QUIZ Watch for a new WA on Gauss to appear suddenly ID: 688140
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Slide1
May the flux be with you
Gauss’s Law3.2
Is that the finger???Slide2
HappeningsWednesday – You should be finished with the Electric Field and today we start Gauss’s LawFriday – Yup, more Gauss and, oh yes, a QUIZ!Watch for a new WA on Gauss to appear suddenly.
Monday … Gauss should be history so on to new stuff. (Sorry)Slide3
What is the electric field at the center of the square array?
Superposition and SymmetrySlide4
A rigid electric dipole is free to move in the electric field represented in the
figure.Which
one of the following phrases most accurately describes the initial motion of the dipole if it is released from rest in the position shown?
A) It moves to the left.
B) It moves to the right.
C) It does not move at all.
D) It moves toward to the top of the page.
E) It moves toward the bottom of the page.
A Bit Tricky!Slide5
Consider the drawing, where the solid lines with arrows represent the electric field due to the charged object. An electron is placed at the point P and released at rest. Which of the following vectors represents the direction of the force, if any, on the electron?Slide6
Which One Of These Is Possible?Slide7
Gauss’s LawSlide8
Let’s ask some questions of ourselvesGiven a distribution of charges can we figure out the Electric Field at a point in space?Yes … just add the effects of each charge (kq
/d2)OK. How about the other direction – can we determine the distribution of charges if we know the Electric Field at a number of places.Sometimes. This is the topic that Gauss addressed and his answer, a mathematical theorem, is quite important in solving a certain class of problems.
Let’s take a look…..Slide9
Last timeWe can use a vector to represent a small flat area:It’s length is proportional to the area.Its direction is perpendicular to the areaThe area need not be square, round or anything else. It must be small. Very small. Teeny Tiny small.
There is an ambiguity in which of two ways the vector can point for a particular small area.Slide10
What would you guess is inside the cube?Slide11
What about now?Slide12
How about this??
Positive point charge
Negative point charge
Large Sheet of charge
No charge
You can’t tell from thisSlide13
FLUX
How Much Stuff Is There?Slide14
An object entering a solid region is the same thing as a negative object leaving!Think about this…..A Strange StatementSlide15
Sphere
Light Bulb Emitting
N Photons per sec.
How many photons
leave the sphere each
second?Slide16
Sphere
Light Bulb Emitting
N Photons per sec.
How many photons
leave the sphere
each
second?Slide17
Sphere
Light Bulb Emitting
N Photons per sec.
How many photons
leave the sphere
each
second?Slide18
This was a brief intro to Gauss’s Law. Now ..START YOUR UNITS (on G’s Law …)