/
Math Extravaganza Math Extravaganza

Math Extravaganza - PowerPoint Presentation

celsa-spraggs
celsa-spraggs . @celsa-spraggs
Follow
369 views
Uploaded On 2017-12-11

Math Extravaganza - PPT Presentation

BY Audrey Alexis Lexi amp Mathew Scenario 1 The marketing director of a Hollister interviewed 50 customers who had bought clothes the previous week They found that 20 of the customers bought jeans and 40 of the customers bought tops Also 48 of the customers bought an item other ID: 614279

algebra students probability facs students algebra facs probability bought part customers surveyed top 349 student jeans selected random takes fractions simplified multiplied

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "Math Extravaganza" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

Math Extravaganza

BY: Audrey

Alexis

Lexi

&

MathewSlide2

Scenario #1

The marketing director of a Hollister interviewed 50 customers who had bought clothes the previous week. They found that 20% of the customers bought jeans and 40% of the customers bought tops. Also, 48% of the customers bought an item other than jeans or a top.Slide3

Part A

What is the probability that a surveyed customer selected at random both bought jeans and a top?

20% of 50 = 1/5

40% of 50= 2/5

1/5 * 2/5= 2/25

First we changed the percents into fractions that we could work with more easily.

Next we multiplied the two fractions to figure out the probability that a randomly selected customer bought both a shirt and top.

So 2/25 is our answerSlide4

Part B) Of the fifty costumers surveyed, how many were likely to have bought jeans and a top?

2/25 = 4x/50

2/25 * 2 = 4/50

X = 4

First we multiplied 2/25 by 2.When we did we got 4/50.

So 4 is our answer.Slide5

Scenario #2

Scott surveyed thirty students in a 7

th

grade English class. 12 students take FACS, 5 of the students take Algebra 1, and 15 students take neither FACS nor Algebra 1.Slide6

P

art A)

What is the probability that a student selected a random takes FACS? Algebra 1?

12/30 simplified to 2/5

2/5 of students will take FACS

5/30 is simplified to 1/6

The probability that a student will take FACS is 2/5

The probability that a student will take Algebra 1 is 1/6Slide7

Part B)

How many students take FACS and Algebra 1?

There are 2 students that take FACS and Algebra 1.Slide8

Part C)

What is the probability that a student selected at random takes both FACS and Algebra?

2/30 simplifies to 1/5

The probability is 1/5 Slide9

Part D)

Suppose the classes taken by the students that Scott surveyed are representative of the classes taken by the 349 7

th

graders in the school

.

Predict the number of students who take both FACS and Algebra 1.

x/349 * 1/15 =

349*15x=

23

The number of students out of 349 would be 23 students.