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Lesson 1.4 - Solving Absolute Value Equations Lesson 1.4 - Solving Absolute Value Equations

Lesson 1.4 - Solving Absolute Value Equations - PowerPoint Presentation

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Lesson 1.4 - Solving Absolute Value Equations - PPT Presentation

Katherine Wu the absolute value of a number is its distance from 0 on a number line distance is nonnegative so the absolute value of a number is always positive symbol x is used to represent the absolute number of a number x ID: 778499

equations absolute number solve absolute equations solve number equation solution practice units find check plug solutions set empty constraints

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Slide1

Lesson 1.4 - Solving Absolute Value Equations

Katherine Wu

Slide2

the

absolute value of a number is its distance from 0 on a number line

distance is nonnegative so the absolute value of a number is always positive

symbol |x| is used to represent the absolute number of a number x

Example

1: Find the absolute value of 5.

|5| = 5

5 is 5 units away from 0, so |5| = 5.

Example 2: Find the absolute value of -8.|-8| = 8-8 is 8 units away from 0, so |-8| = 8.

5 units

8 units

| Absolute Value Equations |

Slide3

| Absolute Value Equations |

some equations contain absolute value expressions

the absolute value of a number is always positive or zero, so an equation like |x| = -4 is never true. The solution for this type of equation is the

empty set

.the empty set is symbolized by { } or ø

Example 1: Solve |x + 12| = 9

x + 12 = 9 x + 12 = -9

x = -3 x = -21

Plug-In to Check

|-3 + 12| = 9

|9| = 9

x = -3 or -21

Example 2: Solve |x + 13| = -6|x + 13| ≠ -6x = øBecause an absolute value equation cannot result in a negative number|-21 + 12| = 9|-9| = 9

Slide4

| Absolute Value Equations |

a

constraint is a condition that a solution must satisfy

equations can be viewed as the constraints of a problem

solutions of the equation meet the constraints of the problem

even if the correct procedure is used to solve an equation, the answers may not be the actual solutions to the original equation. This is called an

extraneous solution.

Example 1: Solve |2x + 12| = 4x

2x + 12 = 4x 2x + 12 = -4x

2x = 12 6x = -12

x = 6 x = -2

Plug-In to Check|2(6) + 12| = 4(6) |2(-2) + 12| = 4(-2)|24| = 24 |8| ≠ -8

There is only one solution; x = 6Example 2: Solve |x + 10| = 4x - 8x + 10 = 4x - 8 x + 10 = -(4x - 8)-3x = -18 5x = -2x = 6 x = -⅖Plug-In to Check|6 + 10| = 4(6) -8 |-⅖ + 10| = 4(-⅖) - 8

|16| = 16 |-9.6| ≠ -9.6

There is only one solution; x = 6

Slide5

Practice 1: Solve |4x + 10| = 6x Practice 2: Solve 3|2a - 4| = 0

Practice 3: Find the absolute value of -24.

Practice 4: Find the absolute value of 0.

| Absolute Value Equations : Practice |

x = 5

a = 2

|-24| = 24

|0| = 0

Slide6

GOOD LUCK

Go home and study for the final on Thursday