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Junior Cert TRIGONOMETRY Junior Cert TRIGONOMETRY

Junior Cert TRIGONOMETRY - PowerPoint Presentation

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Junior Cert TRIGONOMETRY - PPT Presentation

Make sure the calculator is in Degree Mode DRG button Practice getting the sinecostan of various angles Inverse functions 2 nd F button Use of backets is important when finding inverses ID: 749263

cos sohcahtoa angle sin sohcahtoa cos sin angle tan angled hypotenuse triangles adjacent elevation hyp depression

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Presentation Transcript

Slide1

Junior Cert

TRIGONOMETRYSlide2

Make sure the calculator is in Degree Mode (DRG button)

Practice getting the sine/cos/tan of various anglesInverse functions: [2nd F button] Use of backets is important when finding inverses:e.g

2

Some considerationsSlide3

SECTION 1

RIGHT ANGLED TRIANGLESSlide4

RIGHT ANGLED TRIANGLES

HYPOTHENUSE

90

0

A

OPPOSITE

ADJACENT

HYPOTHENUSE

90

0

A

OPPOSITE

ADJACENTSlide5

a

b

c

a

2

+b

2

= c

2

PYTHAGORAS THEOREM

The square of the hypotenuse is equal to the sum of the squares on the other 2 sides.

This theorem is used when you are looking for the length of one side of a triangle when you are given the measurements of the other 2 sides.

( Remember this theorem only works for right angled triangles).Slide6

Hypotenuse [H]Slide7

Hypotenuse [H]

A

Opposite [O]

Adjacent [A]Slide8

Hypotenuse [H]

A

Opposite [O]

Adjacent [A]Slide9

[H]

A

[O]

[A]

Cosine

Cos A =

A

H

Sine

Sin A =

O

H

Tangent

Tan A =

O

A

SOHCAHTOASlide10

[5]

[3]

[4]

A

SOHCAHTOA

[H]

[O]

[A]

Sin A =

O

H

=

3

5Slide11

[5]

A

[3]

[4]

SOHCAHTOA

[H]

[O]

[A]

Cos A =

A

H

=

4

5Slide12

[3]

SOHCAHTOA

[H]

[5]

A

[4]

[O]

[A]

Tan A =

O

A

=

3

4Slide13

[13]

A

[12]

[5]

SOHCAHTOA

[H]

[O]

[A]

Sin A =

O

H

=

12

13Slide14

[13]

A

[12]

[5]

SOHCAHTOA

[H]

[O]

[A]

Cos A =

A

H

=

5

13Slide15

[13]

A

[12]

[5]

SOHCAHTOA

[H]

[O]

[A]

Tan A =

O

A

=

12

5Slide16

[15]

30

0

x

SOHCAHTOA

[H]

[O]

[A]

Sin 30

0

=

O

H

=

x

15

Looking for x

O

Given

H

Sin 30

0

= 0.5

x

15

0.5

1

=

x

=

15(0.5)

= 7.5Slide17

[15]

50

0

x

SOHCAHTOA

[H]

[O]

[A]

tan 50

o

=

O

A

=

x

15

Looking for x

O

Given

A

Tan 50

o

= 1.1917

x

=

15(1.1918)

= 17.876

x

15

1.1917

1

=Slide18

[15]

35

o

16’

x

SOHCAHTOA

[H]

[O]

[A]

Cos 35

o

16’ =

A

H

=

15

x

Looking for x

H

Given

A

Cos 35

o

16’ = 0.8164

x(0.8165)

= 15

x =

15

x

0.8164

1

=

15

0.8165

= 18.37Slide19

THE ANGLE OF ELEVATION AND DEPRESSION

(b) Angle of elevation = Angle looking up

depression

elevation

(a) Angle of depression = Angle looking downSlide20

Example 1

A plane takes of at an angle of 200 to the level ground. After

flying for 100m how high is it off the ground.

20

0

100m

height

90

0

QUESTIONS ON RIGHT ANGLED TRIANGLESSlide21

20

0

100m

height

90

0

HYP

opp

In this we are given the

Hyp

. And we are looking for the

Opp

So we use the

Sin

FormulaSlide22

10m

14mSlide23

10m

8mSlide24

Note: If given ratio always draw right angled triangle

Adj = 5

Hyp = 13

x