100 kg 75 kg F G m 1 m 2 r ² m 1 100 kg m 2 75 kg r 2 m 2 m F 667 x 10 11 Nm ²kg² 100kg 75kg 2m² 125 E 7 N UGA EXAMPLE 1 Two particles are separated in space with a center to center distance of 0478 m The mass of A is 365 kg and ID: 654388
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Slide1
Two students are separated in the classroom with a center to center distance of 2 m. The mass of A is 100 kg and the mass of B is 75 kg. Find the magnitude and direction of the net gravitational force acting on the students.
100 kg
75 kg
F = G (m
1
m2 / r²)m1 = 100 kgm2 = 75 kgr = 2 m
2 m
F = 6.67 x 10
–11 Nm²/kg² (100kg * 75kg) / (2m)²
= 1.25 E -7 N
UGA EXAMPLE 1Slide2
Two particles are separated in space with a center to center distance of 0.478 m. The mass of A is 365 kg and the mass of B is 765 kg. Find the magnitude and direction of the net gravitational force acting on the particles.
365 kg
765 kg
F = G (m
1
m2 / r²)m1 = 365 kgm2 = 765 kgr = 0.478 m
0.478 m
F = 6.67 x 10
–11 Nm²/s² (365kg * 765kg) / (.478m)²
= 8.15 E -5 N
UGA EXAMPLE 2Slide3
Calculate the acceleration of gravity on the earth if you know its mass to be 5.98 E 24 kg.
365 kg
765 kg
a= G (m
2
/ r²)m1 = 365 kgm2 = 765 kgr = 0.478 m
0.478 m
F = 6.67 x 10
–11 Nm²/s² (365kg * 765kg) / (.478m)²
= 8.15 E -5 NEXAMPLE In progressSlide4
Calculate μ when a 6 kg box requires 3 N of force to slide at
constant velocity on a
horizontal surface.
6 kg
F
pull= 3 NFg = 6 kg (10 m/s
²) = 60
N
FN = 60 N
v= constanta= 0 m/s
²
F
net
= 0
μ= F
F
/
F
N
F
F
= 3 N
F
g
=
F
w
=F
N
=
60
N
μ= 3 N
/
60
N
=
.05
F
F
=
3 NSlide5
Calculate μ when a 4 kg box requires 30 N of force to slide at
constant velocity on a
horizontal surface.
4 kg
F
pull= 30 NFg = 4 kg * 10
m/s² = 40 N
F
N = 40 N
v= constanta= 0 m/s
²
F
net
= 0
μ= F
f
/ F
N
F
F
= 30 N
F
g
=
F
w
=F
N
=
40
N
μ= 30 N /
40
N
=
.
75
F
F
=
30 NSlide6
Calculate μ when it takes
186 N to slide a 59.9 kg box across a horizontal slushy ice rink at an acceleration of 0 m/s
2?
59.9 kg
F
pull= 186 N
Fg = 59.9 kg * 10 m/s
² = 599 N
F
N = 599 N
a= 0 m/s
²
F
net
is 0
μ= F
f
/ F
N
F
F
= 186 N
μ= 186 N /
599
N
=
0.31
F
F
=
186 N
F
g
=
F
w
=F
N
=
599
N