Warm up How do you get a genetic disorder Can you catch it Are you born with it Can it be cured Can you get rid of it If your parents have it will you You need to audit on WEDNESDAY this week ID: 1044377
Download Presentation The PPT/PDF document "HW # 65- Work on the INDIVIDUAL p..." is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.
1. HW # 65- Work on the INDIVIDUAL portion of the Genetic Disorder Project.Warm up How do you get a genetic disorder? Can you catch it? Are you born with it? Can it be cured? Can you “get rid” of it? If your parents have it, will you?You need to audit on WEDNESDAY this week.Week 20, Day Two
2. Warm up Response x
3. Homework Response/CheckGenetics of a Smile worksheet- it should be completed.
4. Goals for TodayGuest SpeakerDiscuss Karyotyping ResultsReceive your Genetic Disorder for your projectIndividual Research due 2/8Group Essay to be started in class on 2/8, due 2/11Rubric online
5. Guest SpeakerDr. Jeanette White (Cole’s mom)
6. Suspect Karyotype Results…
7. Normal Male
8. Normal Female
9. Sam Stubs
10. Norma Nanny
11. Captain Relish
12. Glen Glendora
13. Fred Fleckstone
14. Theresa Thyme
15. Genetic Disorder ProjectIndividual Research due 2/82. Group Essay (3 people) started in class on 2/8, due 2/11 This will be completed using GoogleDocs. You will begin and share the document during class on Friday.Be sure you READ and UNDERSTAND the rubric found at the end of the GoogleDocs prompt (already shared with you). You will also find a copy of the rubric posted on the class web site.
16. Stop hereThe rest is for next week on Punnett squares
17. White fur (b)Punnett Square and ProbabilityUsed to predict the possible gene makeup of offspring – Punnett SquareExample: Black fur (B) is dominant to white fur (b) in miceCross a heterozygous male with a homozygous recessive female.Black fur (B)White fur (b)Heterozygous maleWhite fur (b)Homozygous recessive female
18. BbBbbbbbWrite the ratios in the following orders:Genotypic ratiohomozygous : heterozygous : homozygous dominant recessivePhenotypic ratio dominant : recessivebbb BPossible offspring – 2N Male gametes - N(One gene in sperm)Female gametes – N (One gene in egg)Male = Bb X Female = bbGenotypic ratio = 2 Bb : 2 bb 50% Bb : 50% bbPhenotypic ratio = 2 black : 2 white 50% black : 50% white
19. BBBbBb bbBbBGenotypic ratio = 1 BB : 2 Bb : 1 bb 25% BB : 50% Bb : 25% bbPhenotypic ratio = 3 black : 1 white 75% black : 25% whiteCross 2 hybrid mice and give the genotypic ratio and phenotypic ratio. Bb X Bb b
20. BBBbBbbbBbBbExample: A man and woman, both with brown eyes (B) marry and have a blue eyed (b) child. What are the genotypes of the man, woman and child?Bb X Bb Man = BbWoman = Bb
21. 1 brown and curlyBBHHBBHhBbHHBbHhBBHhBBhhBbHhBbhhBbHHBbHhbbHHbbHhBbHhBbhhbbHhbbhhBHBHBhBhbHbHbhbh9 black and straight3 black and curly3 brown and straightGametesCrossing involving 2 traits – Dihybrid crossesExample: In rabbits black coat (B) is dominant over brown (b) and straight hair (H) is dominant to curly (h). Cross 2 hybrid rabbits and give the phenotypic ratio for the first generation of offspring.Possible gametes: BbHh X BbHhBH BHBh BhbH bHbh bhPhenotypes - 9:3:3:1
22. BBHHBBHhGametesGametesBHBHBh100% black and straightExample: In rabbits black coat (B) is dominant over brown (b) and straight hair (H) is dominant to curly (h). Cross a rabbit that is homozygous dominant for both traits with a rabbit that is homozygous dominant for black coat and heterozygous for straight hair. Then give the phenotypic ratio for the first generation of offspring. BBHH X BBHh Possible gametes: BH BH Bh(Hint: Only design Punnett squares to suit the number of possible gametes.)Phenotypes:
23. Sex DeterminationPeople – 46 chromosomes or 23 pairs22 pairs are homologous (look alike) – called autosomes – determine body traits 1 pair is the sex chromosomes – determines sex (male or female)Females – sex chromosomes are homologous (look alike) – label XX Males – sex chromosomes are different – label XY
24. XXXXXYXYXYWhat is the probability of a couple having a boy? Or a girl? Chance of having female baby? 50% male baby? 50%Who determines the sex of the child? fatherXX
25. Incomplete dominance and CodominanceWhen one allele is NOT completely dominant over another (they blend) – incomplete dominance Example: In carnations the color red (R) is incompletely dominant over white (W). The hybrid color is pink. Give the genotypic and phenotypic ratio from a cross between 2 pink flowers. RW X RWRRRWRWWWRWRWGenotypic = 1 RR : 2 RW : 1 WWPhenotypic = 1 red : 2 pink : 1 white
26. When both alleles are expressed – Codominance Example: In certain chickens black feathers are codominant with white feathers. Heterozygous chickens have black and white speckled feathers.
27. Sex – linked TraitsGenes for these traits are located only on the X chromosome (NOT on the Y chromosome)X linked alleles always show up in males whether dominant or recessive because males have only one X chromosome
28. Examples of recessive sex-linked disorders:colorblindness – inability to distinguish between certain colors Color blindness is the inability to distinguish the differences between certain colors. The most common type is red-green color blindness, where red and green are seen as the same color. You should see 58 (upper left), 18 (upper right), E (lower left) and 17 (lower right).
29. 2. hemophilia – blood won’t clot
30. XNXNXNXnXNYXnYXNXnXNYPhenotype: 2 normal vision females 1 normal vision male 1 colorblind maleExample: A female that has normal vision but is a carrier for colorblindness marries a male with normal vision. Give the expected phenotypes of their children. N = normal vision n = colorblindness XN Xn X XN Y
31. PedigreesGraphic representation of how a trait is passed from parents to offspringTips for making a pedigreeCircles are for femalesSquares are for malesHorizontal lines connecting a male and a female represent a marriageVertical line and brackets connect parent to offspringA shaded circle or square indicates a person has the traitA circle or square NOT shaded represents an individual who does NOT have the traitPartial shade indicates a carrier – someone who is heterozygous for the trait
32. Example: Make a pedigree chart for the following couple. Dana is color blind; her husband Jeff is not. They have two boys and two girls. HINT: Colorblindness is a recessive sex-linked trait.XNYHas traitCan pass trait to offspringXnXn
33. Multiple Alleles 3 or more alleles of the same gene that code for a single traitIn humans, blood type is determined by 3 alleles – A, B, and O BUT each human can only inherit 2 allelesDominant – A and B (codominance)Recessive – O 2. Blood type – A = AA or AO B = BB or BO AB = AB O = OO
34. ABExample: What would be the possible blood types of children born to a female with type AB blood and a male with type O blood?AB X OOAOBOAOBOOOChildren would be type A or B only
35. MutationsMutation – sudden genetic change (change in base pair sequence of DNA)Can be : Harmful mutations – organism less able to survive: genetic disorders, cancer, deathBeneficial mutations – allows organism to better survive: provides genetic variationNeutral mutations – neither harmful nor helpful to organismMutations can occur in 2 ways: chromosomal mutation or gene/point mutation
36. Chromosomal mutation:less common than a gene mutationmore drastic – affects entire chromosome, so affects many genes rather than just onecaused by failure of the homologous chromosomes to separate normally during meiosischromosome pairs no longer look the same – too few or too many genes, different shape
37.
38. Examples:Down’s syndrome – (Trisomy 21) 47 chromosomes, extra chromosome at pair #21
39. Turner’s syndrome – only 45 chromosomes, missing a sex chromosome (X) Girls affected – short, slow growth, heart problems
40. Klinefelter’s syndrome – 47 chromosomes, extra X chromosomes (XXY) Boys affected – low testosterone levels, underdeveloped muscles, sparse facial hair
41. Having an extra set of chromosomes is fatal in animals, but in plants it makes them larger and hardier.Hardier
42. Gene or Point Mutationmost common and least drasticonly one gene is altered
43. Examples: Recessive gene mutations:Sickle cell anemia – red blood cells are sickle shaped instead of round and cannot carry enough oxygen to the body tissues – heterozygous condition protects people from malaria
44. Cystic fibrosis – mucous builds up in the lungsTay-Sachs Disease – deterioration of the nervous system – early deathMutated genes produce enzymes that are less effective than normal at breaking down fatty cell products known as gangliosides. As a result, gangliosides build up in the lysosomes and overload cells. Their buildup ultimately causes damage to nerve cells.
45. Phenylketonuria (PKU) – an amino acid common in milk cannot be broken down and as it builds up it causes mental retardation – newborns are tested for this Dominant gene mutations:Huntington’s disease – gradual deterioration of brain tissue, shows up in middle age and is fatalDwarfism – variety of skeletal abnormalities
46. Detecting Genetic Disorderspicture of an individual’s chromosomes – karyotypeamniotic fluid surrounding the embryo is removed for analysis – amniocentesis Female with Down’s syndrome