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Avogadro’s Law Avogadro’s Principle – Avogadro’s Law Avogadro’s Principle –

Avogadro’s Law Avogadro’s Principle – - PowerPoint Presentation

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Uploaded On 2019-11-27

Avogadro’s Law Avogadro’s Principle – - PPT Presentation

Avogadros Law Avogadros Principle equal volumes of gases at the same temperature and pressure contain equal numbers of particles What is Avogadros Law Avogadros Formula V 1 V 2 ID: 768331

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Avogadro’s Law

Avogadro’s Principle – equal volumes of gases at the same temperature and pressure contain equal numbers of particles What is Avogadro’s Law

Avogadro’s Formula V 1= V2 n1 n2 This is a direct relationship! So if the amount of gas increases, then the volume will ___________. If the amount of gas decreases, then the volume will __________. increase decrease * n represents the amount of gas

Graph for Avogadro’s Law What Laws have we learned were also direct relationships, in which their graphs were similar to Avogadro’s?

Avogadro’s Law Molar Volume – for a gas is the volume that one mole of that gas occupies at STPAvogadro showed experimentally that 1 mole of any gas will occupy a volume of 22.4L at STP** Conversion Factor: 1 mol (any gas) = 22.4 L at STP **

Avogadro’s Law: Example 1 Calculate the volume that 0.881 moles of oxygen gas at STP will occupy.

Avogadro’s Law: Example 1 Answer Formula: V1 = V 2 n1 n2 V 1 = ? L n1 = 0.881 mol O2V2 = 22.4 L n 2 = 1 mol O 2 Remember, at STP : 22.4 L/ mol V 1 = 22.4 L .881 mol O2 1 mol O2After cross multiplying you end up withV1(1 mol O2) = (22.4 L)(.881 mol O2) 1 mol O2 1 mol O2V1 = ___________ ---------- ---------- ----------- ---------- 19.7 L

Avogadro’s Law: Example 2 How many grams of N2 will be contained in a 2.0 L flask at STP? (Remember- one mole WEIGHS the formula mass in grams)

Avogadro’s Law: Example 2 AnswerFormula: V1 = V 2 n 1 n2 V 1 = 2.0 L n1 = ? g N 2V2 = 22.4 Ln2 = 1 mol N 2 Remember, at STP : 22.4 L/ mol First , solve for the number of moles of N 2 : 2 L N2 | 1 mol N2 = .089 mol N2 | 22.4 L N2Then, use dimensional analysis to convert from moles of N2 to grams of N2:.089 mol N 2 | 28.014 g N 2 = | 1 mol N 2\ 2.5 g N 2