Bellwork Use the Ohms law equation to determine the missing values in the following circuits Drawing Electrical Circuit Diagrams name variable unit symbol source of emf ε volts V ID: 460859
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Slide1
Electrical Circuits and Circuit DiagramsSlide2
Bellwork
: Use the Ohm's law equation to determine the missing values in the following circuits.Slide3Slide4
Drawing Electrical
Circuit DiagramsSlide5
name variable unit symbol
source of
emf
ε volts V
Resistor R ohms
Ω
wires n/a
n/a
switch n/a n/a Ammeter I amperes A voltmeter U orV volts V
Commonly Used
Symbols for DC CircuitsSlide6
A current is said to exist whenever _____.
a. a wire is charged
b. a battery is present
c. electric charges are unbalanced
d. electric charges move in a loop Slide7
a. + charges move
b. - electrons move
c. + electrons move
2. Current has a direction. By convention, current is in the direction which ___.Slide8
A. water pressure
B. gallons of water flowing down slide per minute
C. water
D. bottom of the slide
E. water pump
F. top of the slide
3. If an electric circuit could be compared to a water circuit at a water park, then the current would be analogous to the ____.Slide9
a. 0.10
b. 0.25
c. 0.50
d. 1.0
e. 5.0
f. 20
g. 10
h. 40
5. The diagram at the right depicts a conducting wire. Two cross-sectional areas are located 50 cm apart. Every 2.0 seconds, 10 C of charge flow through each of these areas. The current in this wire is ____ A.Slide10
a. A current of one ampere is a flow of charge at the rate of _______ coulomb per second.
b. When a charge of 8 C flows past any point along a circuit in 2 seconds, the current is _____ A.
c. If 5 C of charge flow past point A
in 10 seconds, then the current is___ A.
d. If the current at point D is 2.0 A, then
___ C of charge flow past point D in
10 seconds.
e. If 12 C of charge flow past point A in 3 seconds, then 8 C of charge will flow past point E in ________ seconds.
6. Use the diagram at the right to complete the following statements:Slide11
True or False:
The current at point E is considerably less than the current at point A since charge is being used up in the light bulbs.Slide12Slide13
Power
Power: the rate at which work is done or energy is used
Power = Work/time or Power = Energy/time
Measured in watts
1 watt = 1 J/sec
Power is CONSERVED in circuits; that is, the power supplied by the battery must be equal to the power consumed by all of the resistors in the circuit.
Joule’s Law: P = IV
Combined with Ohm’s Law: P = I
2R = V2/RSlide14
Example
Problems
Which would be thicker (wider) - the filament of a 60-Watt light bulb or the filament of a 100-W light bulb? Explain.
Calculate the resistance and the current of a 7.5-Watt night light bulb plugged into a US household outlet (120 V).
Calculate the resistance and the current of a 1500-Watt electric hair dryer plugged into a US household outlet (120 V).
The box on a table saw indicates that the amperage at startup is 15 Amps. Determine the resistance and the power of the motor during this time. Slide15
The sticker on a compact disc player says that it draws 288
mA
of current when powered by a 9 Volt battery. What is the power (in Watts) of the CD player?
A 541-Watt toaster is connected to a 120-V household outlet. What is the resistance (in ohms) of the toaster?
A color TV has a current of 1.99 Amps when connected to a 120-Volt household circuit. What is the resistance (in ohms) of the TV set?
More Power ProblemsSlide16
Electricity in SeriesSlide17
Electricity In Series Circuits
The current must be the same through all resistors when the resistors are in series
R
eq
= R
1
+ R
2
+ R3 Veq = V1 + V2 + V3 Ieq = I1 = I2 = I3Slide18
Example Problems
What would be the equivalent resistance of the resistors shown above?
When the 2A current flows through the resistors, what total voltage will be lost across this combination?
How much power is dissipated by these resistors?Slide19
Electricity
in ParallelSlide20
Electricity in Parallel Circuits
When
resistors are connected in parallel, the voltage drop across each resistor is the same. The current divides among the resistors.
It divides proportionally with the larger ratio going along the "path of least resistance."
I =V/R
I
eq
= I
1 + I2 + I3I = V/R1+V/R2+V/R3 …=V(1/R1 + 1/R2 + 1/R3 …)Slide21
Example Problems
If R
1
= 6 Ω and R
2
= 6 Ω, how much current flows through each resistor?
If R
1
= 6 Ω and R
2 = 12 Ω, how much current flows through each resistor now?
If R
1 = 18 Ω and R2 = 6 Ω, how much current flows through each resistor?
What is their equivalent resistance?
What is the total voltage lost between points X and Y?
How much current flows through each resistor in the circuit shown above? Slide22
Practice – Resistors in Series and Parallel Circuits Mini-Lab
Log
on to the
PhET
website and select the DC Circuit Construction Kit.
http://phet.colorado.edu/simulations/sims.php?sim=Circuit_Construction_Kit_DC_Only
Answer the questions in your instruction sheet as you go. Make sure you accomplish all experiments requiring real lab equipment BEFORE you leave class today!
Electrical Circuits Quiz Friday 03/20/09Slide23
A color TV has a current of 1.99 Amps when connected to a 120-Volt household circuit. What is the resistance (in ohms) of the TV set?
WarmUpSlide24
Combinations of Circuits
Series Circuits
The current is the same in every resistor;
this current is equal to that in the battery.
The sum of the voltage drops across the individual resistors is equal to the voltage rating of the battery.
The overall resistance of the collection of resistors is equal to the sum of the individual resistance values,
R
tot
= R1 + R2 + R3 + ... Parallel CircuitsThe voltage drop is the same across each parallel branch. The sum of the current in each individual branch is equal to the current outside the branches. The equivalent or overall resistance of the collection of resistors is given by the equation 1/Req
= 1/R1+1/R2+1/R
3Slide25
Simplifying a Circuit DiagramSlide26
Problem Solving Strategy
If a schematic diagram is not provided, take the time to construct one.
Take the time to organize yourself, writing down known values and equating them with a symbol such as
I
tot
, I
1
, R
3, V2, etc. Know and use the appropriate formulas for the equivalent resistance of series-connected and parallel-connected resistors.Simply the circuit into a series circuit by replacing the parallel section with a single resistor.Use the Ohm's law equation (V = I • R) often and appropriately. Slide27
Use Ohm’s Law to simplify the circuit
Evaluating Combination CircuitsSlide28
Example Problem 15Slide29
Solution to Problem 15Slide30
Example Problem 16 Slide31
Solution to Problem 16Slide32
Complete the following Chart