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1.1 Solving One step Equations 1.1 Solving One step Equations

1.1 Solving One step Equations - PowerPoint Presentation

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Uploaded On 2019-02-06

1.1 Solving One step Equations - PPT Presentation

What we will learn Solve linear equations using addition and subtraction Solve linear equations using multiplication and division Use linear equations to solve reallife problems Needed Vocab Equation ID: 750662

equations solve linear equation solve equations equation linear sign original positive temperature divide negative answer multiply ticket price problems

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Slide1

1.1 Solving One step EquationsSlide2

What we will learn

Solve linear equations using addition and subtraction

Solve linear equations using multiplication and division

Use linear equations to solve real-life problemsSlide3

Needed Vocab

Equation:

statement that two expressions are equal

Linear equation in one variable:

ax + b = 0

Solution:

value that makes equation true

Equivalent equations:

equations that have the same solution

Inverse operations:

do

the oppositeSlide4

Ex. 1 solving by Adding/subtracting

Solve each equation

Do the opposite

X – 3 = -5

+3 +3

X = -2

.9 = y + 2.8

-2.8 -2.8-1.9 = y

Same sign, add and keep sign

Different sign, subtract and keep sign of bigger numberSlide5

Your Practice

Solve

n + 3 = -7

-3 -3

n = -10

Solve

-6.5 = p + 3.9

-3.9 -3.9

-10.4 = p

Slide6

Ex. 2 Solve by Multiply/divide

Solve each equation

1.3z = 5.2

Divide by 1.3

z = 4

-

3

Multiply by -5

Always want letter to be positive

n = 15

 

When multiplying or dividing two negatives or two positives, the answer will be positive

When multiplying or dividing a negative and a positive, the answer will be negativeSlide7

Your practice

Solve

y = -18

 

Solve

.05w = 1.4

w = 28

 Slide8

Exs

. 3 and 4 Story problems

A discounted amusement park ticket costs $12.95 less than the original price p. You paid $44. Write and solve an equation to find the original price.

Ticket = original – 12.95

44 = p – 12.95

+12.95 +12.95

56.95 = p

The temperature at 5 pm is 20 F. The temperature at 10 pm is -5 F. How many degrees did the temperature fall?

t = 20 – (-5)

t = 25