Series and parallel combinations Energy in a capacitor Dielectrics Dielectric strength 25 12 Series combinations reduce the capacitance Equal C reduce by the number involved In parallel the capacitance increases ID: 760222
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Slide1
Slide2summary
CapacitanceParallel plates, coaxial cables, EarthSeries and parallel combinationsEnergy in a capacitorDielectricsDielectric strength
Slide3Slide4(25 - 12)
Slide5Series combinations reduce the capacitance. Equal C reduce by the number involved.
In parallel the capacitance increases.
A basket of 4 capacitors, each of C = 6
nF
. How can you arrange them to get
1.5
nF
2
nF
g) 2.4
nF
3
nF
h) 3.6
nF
4
nF
i
) 4.5
nF
j) 6
nF
12
nF
k) 18
nF
24
nF
Slide6clicker
All C’s are 8.00 nF. The battery is 12 V.What is the equivalent capacitance?
4
nF
6
nF
8
nF
10
nF
12
nF
Slide7All C’s are 8.00 nF. The battery is 12 V.What is the equivalent capacitance?
C
12 = 4 nFC123 = 12 nFQ123 = C123 x V = 144 nCQ3 = C3 x V = 96 nCQ12 = C12 x V = 48 nC
U
123
=
½ C
123
V
2
= ½ x 12x10
-9
x12
2
= 864
nJ
U
1
= ½ C
1
V
1
2
= ½ x 8x10
-9
x6
2
= 144
nJ
= U
2
U
3
= ½ x 8x10
-9
x12
2
= 576
nF
C
3
stores most energy, also the highest electric field and most charge, the
most stressed
part of the circuit
.
Slide8Slide9Slide10Slide11Slide12Slide13Slide14Circuits
All capacitors being the same, rank the equivalent capacitances of the four circuits.
Slide15C
123 2.4 µF, q = 28.8 µCC2 C24 = 12 µFC1234 = 3 µF q =36 µCΔq = 7.2 µC
C
1
= C
3
= 8.00
μ
F,
C
2
= C
4
= 6.00
μ
F,
V = 12V
When the switch S is closed, how much charge flows through point P
Slide16Slide17q
-q
q
'
q
q
-q
'
-q
-q
V
V
V
V
'
(25 - 15)
Slide18q
-q
q
'
q
q
-q
'
-q
-q
V
V
V
V
'
(25 - 16)
Slide19If the areas are A
1 and A-A1.
C
123 2.4 µF, q = 28.8 µCC2 C24 = 12 µFC1234 = 3 µF q =36 µC
Effect of a dielectric : C
κ
C
Slide20The force on a filling dielectric as it is inserted between the parallel plates of a capacitor.
x
L
With the battery connected,
U
1
= ½CV
2
With the battery disconnected,
U
2
= Q
2
/2C
With the battery connected, since x is increasing downwards, a negative force is upwards, pushing the dielectric away.
With the battery disconnected, the force is positive and pointed downwards, pulling in the dielectric.
The force is proportional to (
κ
-1) and inversely to L.
Slide21Slide22Slide23A question
What is the equivalent capacitance between the points A and B?
1 μF B. 2 μF 4 μF 10μF None of these
A
B
What would a 10V battery do, i.e. how much charge will it provide,
when it is connected across A and B? 40
μ
C
Slide24Question
A parallel-plate capacitor has a plate area of 0.3m2 and a plate separation of 0.1mm. If the charge on each plate has a magnitude of 5x10-6 C then the force exerted by one plate on the other has a magnitude of about:0 5N 0. 9N 1 x104 N 9 x 105 N
The electric field =
σ
/2
ε
o
why?
Slide25Question
A parallel-plate capacitor has a plate area of 0.3m
2
and a plate separation of 0.1mm. If the charge on each plate has a magnitude of 5x10
-6
C then the force exerted by one plate on the other has a magnitude of about:
A. 0 B. 5N C. 9N D. 1 x10
4
N E. 9 x 10
5
N
Slide26A question
Each of the four capacitors shown is 500
μ
F. The voltmeter reads 1000V. The magnitude of the charge, in coulombs, on each capacitor plate is:
A. 0.2 B. 0.5 C. 20 D. 50 E. none of these
Slide27HITT
A parallel-plate capacitor has a plate area of 0.2m
2
and a plate separation of 0.1 mm. To obtain an electric field of 2.0 x 10
6
V/m between the plates, the magnitude of the charge on each plate should be:
A. 8.9 x 10
-7
C B. 1.8 x 10
-6
C C. 3.5 x 10
-6
C D. 7.1 x 10
-6
C E. 1.4 x 10
-5
C