PPT-Empirical Knowledge Representation

Author : liane-varnes | Published Date : 2015-11-28

Enrico Motta Knowledge Media Institute The Open University UK Introduction KR OntEng research traditionally follows a topdown approach formalisms are designed

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Empirical Knowledge Representation: Transcript


Enrico Motta Knowledge Media Institute The Open University UK Introduction KR OntEng research traditionally follows a topdown approach formalisms are designed on the basis of modelling needs and computational . The Edwin Smith papyrus. Title:. Instructions for treating a fracture of the cheekbone.. Symptoms:. If you examine a man with a fracture of the cheekbone, you will find a salient and red fluxion, bordering the wound.. How can conjectural variation models help?. Alan Crawford and . Benoît. Durand. OFT Seminar. The questions. Can we use conjectural variation models to . measure empirically market power?. identify the source of market power? Can we use conjectural variation models to tell whether market power is the result of product differentiation or collusion? . . Learning. for. . Word, Sense, Phrase, Document and Knowledge. Natural . Language Processing . Lab. , Tsinghua . University. Yu Zhao. , Xinxiong Chen, Yankai Lin, Yang Liu. Zhiyuan Liu. , Maosong Sun. Objectives. To learn how to work out the percentage composition by weight of a compound. To use percentage composition to work out empirical formulae. Percentage compositions. This means what percentage of each element is present in a compound, and therefore tells you what masses of each element are present in any given mass of a compound. . How can conjectural variation models help?. Alan Crawford and . Benoît. Durand. OFT Seminar. The questions. Can we use conjectural variation models to . measure empirically market power?. identify the source of market power? Can we use conjectural variation models to tell whether market power is the result of product differentiation or collusion? . Chemistry GT 3/20/15. Drill. Calculate the percent composition of Na. 2. SO. 4. .. HW: Molecular Formula WS (pg. 4). MM. =142.05 . g. /mol. 32.37% Na, 22.58% S, 45.05% O. Chem. Joke of the Day. The photon checked into a hotel. What did it say when the bellhop asked for its bag?. Molecular Formulas. Let’s use those mole conversions!. Empirical formula . tells you the lowest ratio of atoms within a molecule. Molecular formula . tells you the actual ratio of atoms within a molecule. and Scientific Thinking . Brendan Conway. Corrine Vicari. Kaitlyn Creel. Matt Graham . Empirical Thought . Empirical thinking depends on past habit.. Based on observation and experience.. Ex. A-“It will probably rain tomorrow”. Part II. Description Logic . & . Introduction to Protégé. Jan Pettersen Nytun. 1. The Semantic . Web. Knowledge Representation Part II, JPN, UiA. 2. ". The Semantic Web is not a separate Web but an extension of the current one, in which information is given well-defined meaning, better enabling computers and people to work in cooperation.“. Chitta. . Baral. Arizona State University. Apologies. For not being here physically on this special occasion. My early history with SMS. My . Ph.D. during 1987-1991. Finding the “right” semantics of negation in logic programming was an important topic . Concepts, Category, Networks, and Schemas. Concepts- . an idea about something that provides means of understanding the world. Organization of Declarative Knowledge. Category – . Determining Molecular Formulas. Calculate the molecular formula of a compound whose molar mass is 60.0 g/mol and has an empirical formula of CH4N.. What you need:. Empirical Formula. Molar Mass. Calculate the molar mass of the empirical formula. Objectives:. -         . The student will determine an empirical, or simplest, formula from percentage composition data..  . PA Science and Technology Standards: 3.4.10.A; 3.4.12.A. PA Mathematics Standards: 2.2.11.A, 2.3.11.C, 2.4.11.E, 2.5.11.A. Percent Composition. ~percent by mass of atoms present in a compound. = (mass of atom). . (total molar mass) x 100. water is . 88.81 . % Oxygen and . 11.19 . % Hydrogen. O- 16.00/18.016 x 100 = . 88.81 .

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