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Chemistry 20 – Unit 3 Chemistry 20 – Unit 3

Chemistry 20 – Unit 3 - PowerPoint Presentation

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Chemistry 20 – Unit 3 - PPT Presentation

Matter as Solutions Acids and Bases Dilution Chemistry 20 Dilution A standard solution is any solution whose concentration is accurately known Dilution involves the addition of solvent to a solution in order to decrease its concentration ID: 536162

mol solution water stock solution mol stock water volume concentration dilution standard solute flask acid solutions mass concentrated dissolving

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Slide1

Chemistry 20 – Unit 3

Matter as Solutions, Acids and BasesSlide2

Dilution

Chemistry 20Slide3

Dilution

A

standard solution

is any solution whose concentration is accurately known

.

Dilution

involves the addition of solvent to a solution in order to decrease its concentration

.

For aqueous solutions, water is added to dilute the solution. This increases the overall volume without affecting the amount of dissolved solute.Slide4

Dilution

Since the amount of solute remains constant throughout dilution, the following relationship exists:

 Slide5

Standard Solutions

The

stock solution

is the more concentrated solution that is being diluted. It is generally a standard solution

.

By diluting a solution carefully and with accurate measurements, the dilute solution will also be a standard solution.Slide6

Example

300 mL of water is added to 17.2 mL of 5.14

mol

/L

HBr

(

aq

). Calculate the resulting concentration.Slide7

Example

300 mL of water is added to 17.2 mL of 5.14

mol

/L

HBr

(

aq

). Calculate the resulting concentration.0.278 mol/LSlide8

Example

For a class experiment, a teacher must prepare 1.00 L of 0.170

mol

/L sulfuric acid, H

2

SO

4(

aq). This acid is usually sold as a 17.8 mol/L concentrated solution. How much of the concentrated solution should be used to make a new solution with the correct concentration?Slide9

Example

For a class experiment, a teacher must prepare 1.00 L of 0.170

mol

/L sulfuric acid, H

2

SO

4(

aq). This acid is usually sold as a 17.8 mol/L concentrated solution. How much of the concentrated solution should be used to make a new solution with the correct concentration?9.55 mLSlide10

Example

30.0 mL of a stock solution of CaCl

2(

aq

)

is diluted to a total volume of 500.0

mL.

The dilute solution is analyzed and found to have a concentration of 15.8 mmol/L. What was the molarity of the stock solution?Slide11

Example

30.0 mL of a stock solution of CaCl

2(

aq

)

is diluted to a total volume of 500.0

mL.

The dilute solution is analyzed and found to have a concentration of 15.8 mmol/L. What was the molarity of the stock solution?0.263 mol/LSlide12

Preparing Standard Solutions

The two common ways of preparing a standard solution include:

dissolving

a measured mass of pure solute in a certain volume of solution

diluting

a stock solution by adding a known volume of solventSlide13

When dissolving a measured mass of pure solute, the steps to follow are:

Calculate

the mass of solute that will need to be measured out.

Measure

out this mass of solute accurately with an electronic balance.

Dissolve

the solute in a minimum volume of water.

Transfer solution into a volumetric flask that is half-filled with water.Fill the volumetric flask with water up to the calibration line.Stopper the flask and mix the solution. http://www.youtube.com/watch?v=XMtm4hVCGWgSlide14

Example

How would a 0.180

mol

/L solution of lithium nitrate be properly prepared by dissolving the solid chemical?Slide15

Example

How would a 0.180

mol

/L solution of lithium nitrate be properly prepared by dissolving the solid chemical

?

mass of LiNO

3

= 12.411 g Slide16

When diluting a stock solution, the steps to follow are:

Calculate

the volume of stock solution that will need to be measured.

Measure

out this volume of solution accurately with a pipette.

Transfer

solution into a volumetric flask that is half-filled with water.

Fill the volumetric flask with water up to the calibration line.Stopper the flask and mix the solution.http://www.youtube.com/watch?v=kMDC4vNEoVoSlide17

Example

How would a 0.220

mol

/L solution of acetic acid be properly prepared by dilution of a 3.50

mol

/L stock solution?Slide18

Example

How would a 0.220

mol

/L solution of acetic acid be properly prepared by dilution of a 3.50

mol

/L stock solution

?

62.9 mLSlide19

Homework

Dilution and Standard Solutions Practice Questions

Solutions Quiz Wednesday