/
11.3 11.3

11.3 - PowerPoint Presentation

marina-yarberry
marina-yarberry . @marina-yarberry
Follow
371 views
Uploaded On 2017-07-17

11.3 - PPT Presentation

The Dot Product of Two Vectors The dot product of u and v in the plane is The dot product of u and v in space is Two vectors u and v are orthogonal ID: 570717

east direction due airplane direction east airplane due vector wind vectors find speed dot ground north mph encounters product

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "11.3" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

11.3

The Dot Product of Two VectorsSlide2

The

dot product

of

u and v in the plane is

The dot product of u and v in space is

Two vectors u and v are orthogonal if they meet at a right angle. if and only if u ∙ v = 0 (since slopes are opposite reciprocal)

(Read “u dot v”)

DefinitionsSlide3

ExamplesSlide4

Another form of the

Dot Product

:

PropertiesSlide5

Find the angle between vectors

u

and v:

ExamplesSlide6

Angles between a vector

v

and 3 unit vectors i, j

and k are called direction angles of

v, denoted by α, β, and γ respectively. Since

we obtain the following 3 direction cosines of

v: So any vector v has the normalized form:

Direction CosinesSlide7

Let

u

and

v be nonzero vectors.

w1 is called the vector component of u along v (or projection of u onto v), and is denoted by

projvu w2 is called the vector component of

u orthogonal to v

w

2

w

1

u

v

Vector ComponentsSlide8

A Boeing 727 airplane, flying due east at 500mph in still air, encounters a 70-mph tail wind acting in the direction of 60

o

north of east. The airplane holds its compass heading due east but, because of the wind, acquires a new ground speed and direction. What are they?

N

E

ApplicationSlide9

A Boeing 727 airplane, flying due

east at 500mph

in still air, encounters a 70-mph tail wind acting in the direction of 60o north of east. The airplane holds its compass heading due east but, because of the wind, acquires a new ground speed and direction. What are they?

N

E

uSlide10

A Boeing 727 airplane, flying due east at 500mph in still air, encounters a

70-mph

tail wind acting in the direction of 60o

north of east. The airplane holds its compass heading due east but, because of the wind, acquires a new ground speed and direction. What are they?

N

E

v

u

60

oSlide11

A Boeing 727 airplane, flying due east at 500mph in still air, encounters a 70-mph tail wind acting in the direction of 60

o

north of east. The airplane holds its compass heading due east but, because of the wind, acquires a new ground speed and direction. What are they?

N

E

v

u

We need to find the magnitude and direction of the resultant vector u +

v

.

u+vSlide12

N

E

v

u

The component forms of

u

and v are:

u+v

500

70

Therefore:

and:Slide13

N

E

The new ground speed of the airplane is about 538.4 mph, and its new direction is about 6.5

o

north of east.

538.4

6.5oSlide14

1) Compute

2) Compute

4) Find the angle between vectors

v

and

w.3) List pairs of orthogonal and/or parallel vectors.

6) Find the projection of w onto u.5) Find the unit vector in the direction u.

7) Find vector component of w orthogonal to u.

Examples

Related Contents


Next Show more