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Groundwater P = Q   ET Groundwater P = Q   ET

Groundwater P = Q ET - PowerPoint Presentation

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Groundwater P = Q ET - PPT Presentation

G D S What is an Aquifer Rocks and sediments have pores spaces Rock limestone granite sandstone etc Sand and gravel When pores are full of water that media is saturated Contiguous areas of saturated media form an aquifer ID: 677534

000 water aquifer ksat water 000 ksat aquifer groundwater day surface 000m saturated floridan potential media high pressure leakage dir potentiometric law

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Presentation Transcript

Slide1

Groundwater

P = Q + ET +

G

+

D

SSlide2

What is an Aquifer?

Rocks and sediments have pores (spaces)Rock (limestone, granite, sandstone etc.)Sand and gravel

When pores are

full of water

that media is saturated

Contiguous areas of saturated media form an aquifer

Aquifers can be layered

Confined vs. Unconfined

Aquifers have the capacity to transmit water through interconnected poresSlide3

Floridan Aquifer

ExtentSlide4

High Plains Aquifer

(

Ogalalla

)Slide5

ConfinementSlide6

Cross-Section– Floridan AquiferSlide7

Transmissivity

How much water can be moved horizontallyFunction of thickness and Ksat

Good measure of well productivity

Floridan is the most transmissive aquifer in the worldSlide8
Slide9

Loss of PotentialSlide10
Slide11

Artesian Springs

Where a confining layer exists, there may be a pressure potential in the aquifer HIGHER than the gravity potential of the surface.When tapped, water flows upwardsSlide12

Potentiometric Surface

Elevation of “free water surface”Where this surface and the ground intersect (and there’s no confinement) water seeps Slide13
Slide14
Slide15

Relevant Questions

Where is the water going?Potentiometric (piezometric) surfaceHow much water is moving? How quickly?Potentiometric surface and Darcys LawWhat level of natural assimilation is occuring?

Water quality modelingSlide16

Gainesville’s Well Field

Also Lake City

Jasper

Geology

Land use

Conservation EasementSlide17

Murphree Wellfield Cone of Depression

1988 (Observed)

2010 (Predicted)Slide18

How to make a sinkhole

Pray for lots of Rain

Suck a lot of waterSlide19

Freeze Protection

To protect strawberry yield during a January freeze in 2010, ~ 2 billion gallons per day of water pumped over a 5 day period. Voila.Slide20

Invasion

Fire

Subsidence

Degraded wildlife habitatSlide21

Soil water movement across a watershed boundary.

P=Q+ET+

G

+

Δ

S

Q

groundwater

= K A

Δ

H/L

Darcy’s Law

Darcy’s law

can calculate

vertical leakage through a clay

layer AND lateral flow through a seepage face.

Q is water crossing the defined area of the boundary in m

3

/daySlide22

K is hydraulic

conductivity, or the capacity of the media to transmit water

Most meaningful as saturated hydraulic conductivity

K

sat

(m/day). Why?

Q=

K

A

Δ

H/LSlide23

Measuring

Ksat

Constant Head Method

Constant depth of water (~50mm) on top of a saturated soil column with known dimensions (diameter, length)

Outflow volume collected over a period of time (e.g., 5

hrs

)

Darcy’s Law to solve for

KsatSlide24

Measuring Ksat

Hvorslev MethodField measurement in screened wells

K only

determined

2

4

6

8

10

minutes

.1

1

.2

.3

.4

.5

.6

.7

.8

H/H

o

t

37

Log scale

Linear scale

H/H

o

=.37

casing

Gravel pack

S

creen

L

e

L

e

/R must be >8

R

high K

material

rSlide25

Approximate

Ksat and Uses

Ksat

(cm/h)

Comments

>50

Beach sand/Golf Course Greens

5

Very sandy soils, cannot filter pollutants

0.5

Suitable for most agricultural, recreational, and urban uses

0.05

Clayey, Too slow for most uses

<0.005

Extremely slow; good if compacted material is neededSlide26

Δ

H is the difference in H between two points

Water flows from high

pressure

to

low

pressure (could

be “up”)

H

= level of water in an open well above some datum

H

A

= ? H

B

= ?

Δ

H = ?

Flow Direction?!?Slide27

H @ D?

H@F?ΔH?

Direction?

10

9

8

7

6

5

4

3

2

1

0Slide28

Δ

H AD? Dir?

Δ

H BF? Dir?

Δ

H AF? Dir?

Δ

H/L BF?Slide29

Q=K A

ΔH/L

K?

A?

Δ

H?

L?

Vertical leakage problem

Ksat

=0.001m/d

Watershed=100 ha

0

1

2

3

4

5

6

DatumSlide30

Q = K *

A * ΔH/L

K = 0.001 m/d

A = 100ha = 1,000,000 m

2

Δ

H = 5-3 = 2m

L = 2m

Q = 0.001m/d x 1,000,000m

2

x 2m / 2m

Q = 1,000 m

3

/day or 365,000 m

3

/year

Q surface depth = 365,000 m

3

/ 1,000,000 m

2

= 0.365mSlide31

Q=K A

Δ

H/L

K=0.1m/d

A=100m x 50m

=5,000m

2

Δ

H=108m-105m

=3m

L=1,000m

Qm

3

/d=

0.1m/d * 5,000m

2

*0.003 = 1.5m

3

/d

Lateral leakage problemSlide32

Groundwater Flowpaths at StreamsSlide33

Groundwater DischargesSlide34

Groundwater FlowpathsSlide35

Next Time…

Soil Water Storage