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Ch. 13 Quantum Mechanical Model Ch. 13 Quantum Mechanical Model

Ch. 13 Quantum Mechanical Model - PowerPoint Presentation

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Ch. 13 Quantum Mechanical Model - PPT Presentation

Electron Configuration Quantum Mechanical Model Quantum mechanics was developed by Erwin Schrodinger Estimates the probability of finding an e in a certain position Electrons are found in an electron cloud or orbital ID: 307509

energy floor hogs orbital floor energy orbital hogs light orbitals hog room quantum noble electron amp write sublevels hilton

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Slide1

Ch. 13 Quantum Mechanical Model

Electron ConfigurationSlide2

Quantum Mechanical Model

Quantum mechanics was developed by Erwin Schrodinger

Estimates the probability of finding an e

- in a certain positionElectrons are found in an “electron cloud” or orbitalSlide3

Radial Distribution Curve

Orbital

Orbital

(“electron cloud”)

Region in space where there is 90% probability of finding an e

-Slide4

Each orbital letter has a different shape.Slide5

“s” orbital

spherical

shaped, and holds up to 2e-Slide6

“p” orbital

Dumbbell shaped

Arranged x, y, z

axes, and can

hold up to 6e- Slide7

“d” orbital

clover

shaped, and can hold up

to 10e-Slide8

“f” orbital

f

Orbitals

combine to form a spherical shape

.

This orbital can hold up to

14e-

2s

2p

z

2p

y

2p

xSlide9

Hog Hilton

You are the manager of a prestigious new hotel in downtown Midland—the “Hog Hilton”. It’s just the “snort of the town” and you want to keep its reputation a cut above all the other hotels. Your problem is your clientele. They are hogs in the truest sense.

Your major task is to fill rooms in your hotel. The Hog Hilton only has stairs. You must fill up your hotel keeping the following rules in mind:

1) Hogs are lazy, they don’t want to walk up stairs!

2) Hogs want to room by themselves, but they would rather room with another hog than walk up more stairs.

3) If hogs are in the same room they will face in opposite directions.

4) They stink, so you can’t put more than two hogs in each room.Slide10

Hog Hilton

Your hotel looks like the diagram below:

6th floor ______

5th floor ______ ______ ______

4th floor ______

3rd floor ______ ______ ______ 2nd floor ______

1st floor ______Book 7 hogs into the rooms.Slide11

Hog Hilton

Your hotel looks like the diagram below:

6th floor ______

5th floor ______ ______ ______ 4th floor ______

3rd floor ______ ______ ______ 2nd floor ______ 1st floor ______

Book 14 hogs into the rooms.Slide12

Let’s play Hog Hilton!!Slide13

Rules for e

-

configurations

1. Aufbau principle

: e- enter orbitals of lowest energy level (

Hogs are lazy, they don’t want to walk up stairs!)2.

Pauli exclusion principle: an atomic orbital may have at most 2 e-, e-

in the same orbital will spin in opposite directions

(

They stink, so you can’t put more than two hogs in each room. & If hogs are in the same room they will face in opposite directions.)

3.

Hund’s

rule

: when e

-

occupy

orbitals

of = energy, 1 enters each orbital until all the

orbitals

contain 1 e

-

w/parallel spins

(

Hogs want to room by themselves, but they would rather room with another hog than walk up more stairs.)Slide14

Now you will relate the “Hog Hilton” to electron

orbitals

. Electron

orbitals are modeled by the picture on the left and are grouped into principal energy levels.1. Compare their similarities and differences.

2. To go between floors on the Hog Hilton did the hogs need to use energy? Would electrons need to use the energy to go between orbitals.

3d ___ ___ ___ ___ ___ n=3(4s ____) n=43p ___ ___ ___ n=3

3s ___ n=3

2p ___ ___ ___ n=2

2s ___ n=2

1s ___ n=1

6th floor ___

5th floor ___ ___ ___

4th floor ___

3rd floor ___ ___ ___

2nd floor ___

1st floor ___Slide15

A. The principle quantum numbers

,

(n)

Electrons are in designated energy levels

.

Organization of e- in the

Quantum Mechanical model

The ground state- the lowest energy state of the atomSlide16

B. Within the energy level are sublevels, designated by letters.

Principle energy level (n)

Number of sublevels

Type of Orbital

1

st

energy level

1 sublevel

“s” (1 orbital)

2

nd

2 sublevels

“s” (1) & “p” (3 orbitals)

3

rd

3 sublevels

“s”(1) , “p” (3) & “d” (5 orbitals)

4

th

4 sublevels

“s”(1), “p”(3) , “d”(5), and “f” (7)Slide17

1s

2s

2p

3p

3s

4s

3d

4p

5s

4d

5p

6s

4f

5d

6p

7s

7s 7p

6s 6p 6d 6f 6g

5s 5p 5d 5f 5g

4s 4p 4d 4f

3s 3p 3d

2s 2p

1sSlide18

Filling in orbitals then writing the electron configuration

4p _

↑↓

_ _ ↑↓ _ _

↑↓ _ 3d _ ↑↓ _ _

↑↓ _ _ ↑↓ _ _

↑↓ _ _ ↑↓ _

4s _

↑↓

_

3p _

↑↓

_ _

↑↓

_ _

↑↓

_

3s _

↑↓

_

2p _

↑↓

_ _

↑↓

_ _

↑↓

_

2s _

↑↓

_

1s _

↑↓

_

1s

2

2s

2

2p

6

3s

2

3p

6

4s

2

3d

10

4p

6Slide19

1. Noble Gases – outermost

s

&

p

sublevels filled

Because they have their s

2

& p

6

orbitals filled they follow the:

2 + 6 =

OCTET RULE

D. According to their e- configs, elements can be classified into 4 main groupsSlide20

2. Representative Elements – outermost

s

or

p sublevel is only partially filled, energy level same as period #

The pink elements excluding the Noble Gases.

s

1

s

2

p

1

p

2

p

3

p

4

p

5Slide21

3. Transition metals – outermost

s

sublevel & nearby

d sublevel contain e

- , energy level is the same as the period # minus 1

d

1

d

2

d

3

d

4

d

5

d

6

d

7

d

8

d

9

d

10Slide22

4. Inner Transition metals - outermost

s

& nearby

f generally contain e

-

f

1

f

14Slide23

d

1

d

2

d

3

d

4

d

5

d

6

d

7

d

8

d

9

d

10

f

1

f

14

s

1

s

2

p

1

p

2

p

3

p

4

p

5

s

2

p

6

Your Periodic Table should look like this.Slide24

How many electrons are present in the d sublevel of a neutral atom of Manganese?

Learning Check

1 2 3 4 5

5 electronsSlide25

What element has the electron configuration 1s

2

2s

22p63s23p4?

Add together all the exponents, then find that atomic number. = Sulfur 16Slide26

E.

Using the Noble Gases to write Shorthand

Write the noble gas that is in the previous row.

Use the symbol of the noble gas, put it in brackets, then write the rest of the configuration.

Write the e- config for Tin (Sn).

[Kr]

5s

2

4d

10

5p

2

Write the e- config using Noble Gas notation for Cobalt.

It would be written [Ar] 4s2 3d7Slide27

Learning Check

Using the Noble Gas Shorthand write the

e

- configuration 1. Cr

2. Br

3. Te4. Ba

[Ar] 4s

2

3d

4

[Ar] 4s

2

3d

10

4p

5

[Kr] 5s

2

4d

10

5p

4

[Xe] 6s

2Slide28

Electromagnetic Spectrum

The electromagnetic spectrum (see p. 373) includes radio waves, microwaves, infrared waves, visible light, ultraviolet waves, x-rays, and gamma rays.

Visible light is in the middle of the spectrum.

The speed of light is 3.0 X 108 m/s.The formula for light is c =ƛʋ

C = speed of light, ƛ = wavelength, ʋ = frequencyVisible light has many wavelengths of light that can be separated into red, orange, yellow, green, blue, indigo, and violet (ROY G BIV)Slide29

Atomic Emission Spectrum

Every element gives off light when it is excited by the passage of an electric current through its gas or vapor.

The atomic emission spectrum occurs when the light that is given off by an element in its excited state is passed through a prism. It consists of a few lines called a line spectra or discontinuous spectra. Each line on the spectra corresponds with a frequency.

See page 374.Work problems # 11 and 12 on page 375.Slide30

Planck’s Constant

In 1900, German Physicist Max Planck used math to explain why objects, such as iron, that are heated change color.

He said energy can be quantized. The size of an emitted or absorbed quantum depends on the size of the energy change. A small energy change involves the emission or absorption of low frequency radiation. A large energy change involves the emission or absorption of high frequency radiation.Slide31

Planck’s constant cont.

The math formula used is:

E = h x vE = radiant energy of a unit (quantum)h = Planck’s constant = 6.6262 x 10 -34v = frequency of radiationSlide32

Planck’s constant cont.

In 1905, Albert Einstein used Planck’s work to call quanta of light photons. He then used this information to explain the photoelectric effect (metals eject/emit electrons called photoelectrons when light shines on them).

Work problems 13 and 14 on p. 379.