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Challenge Problem Challenge Problem

Challenge Problem - PowerPoint Presentation

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Uploaded On 2016-12-07

Challenge Problem - PPT Presentation

When nitrogen and hydrogen react they form ammonia gas which has the formula NH 3 If 560 g of nitrogen are used up in the reaction how many grams of ammonia will be produced Episode 802 ID: 498488

yield mol grams co2 mol yield co2 grams nh3 802 episode sodium 1mol na2o naco3 produced h2o actual c3h8

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Slide1

Challenge Problem

When nitrogen and hydrogen react, they form ammonia gas, which has the formula NH3. If 56.0 g of nitrogen are used up in the reaction, how many grams of ammonia will be produced?

Episode 802

N2 (g) + 3H2 (g)  2NH3 (g)

? g NH3 = 56.0 g N2

28g N2

1 mol N2

1 mol N2

1 mol NH3

2 mol NH3

17g NH3

= 68g NH3Slide2

Sodium metal reacts with oxygen to produce solid sodium oxide. How many grams of sodium must react to produce

42.0 grams of sodium oxide?

When 12.0

grams of hydrogen reacts with oxygen, how many grams of water are produced?4Na (s) + O2 (g)  2Na2O (s)

2H2 (g) + O2 (g)

 2H2O (l)

? g Na = 42.0g Na2O

62g Na2

O1 mol Na2

O2 mol Na2

O4 mol Na

1 mol Na

23g Na

= 31g Na

? g H

2

O = 12.0g H

2

2g H

2

1 mol H

2

2

mol H

2

2

mol H

2

O

1

mol H

2

O

18g H

2

O

= 108g H

2

O

Episode

802Slide3

Actual Yield

Amount of product produced when the reaction is performed in a

labTheoretical YieldAmount of product

expected to be produced based on the balanced equation and the amount of reactantsCalculated using stoichiometryPercent Yield(actual

yield/theoretical yield) x 100%Episode 802Slide4

Percent Yield in Lab

Actual yield of CO2 =

0.13g(from lab data)Calculated theoretical yield

from the balanced equation:NaHCO3 + HCl  NaCl + CO2

+ H2O? g CO2 = 0.23g NaCO

384g NaCO

3

1mol NaCO3

1mol NaCO31mol CO

21mol CO2

44g CO2

= 0.12g CO

2

% yield =

0.13g

0.12g

x

100 =

108%

Episode

802Slide5

What is the % yield of carbon dioxide when 5.99 grams of propane are burned and 12.052 grams of carbon dioxide are collected?

C

3H8 + 5O

2  3CO2 + 4H2O? g CO

2 = 5.99g C3H8

44g C

3H8

1 mol C3

H8

1 mol C3

H8

3 mol CO2

1 mol CO

2

44g CO

2

= 17.97g CO

2

% yield =

12.052g

17.97g

x

100 =

67%

Episode

802