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Section 6.1-D Distribution of Section 6.1-D Distribution of

Section 6.1-D Distribution of - PowerPoint Presentation

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Section 6.1-D Distribution of - PPT Presentation

Section 61D Distribution of a Proportion Review statistic parameter null value data standard error The Central Limit Theorem applies to the distribution of the Owned Homes The 2010 census reports that of all the nations occupied housing units 651 are owned by the occupants The SE ID: 765971

vote plan proportion citizens plan vote citizens proportion 500 random error sample test 280 upcoming election evidence margin confidence

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Section 6.1-D Distribution of a Proportion

Review statistic parameter null value data standard error The Central Limit Theorem applies to the distribution of the

Owned Homes The 2010 census reports that, of all the nation’s occupied housing units, 65.1% are owned by the occupants. The SE is 0.048. If we were to take random samples of 100 homes, what would be the distribution of ?   N(0.651, 0.048) N(0.048, 0.651) N(0, 0.048) N(0, 0.651)

Bi-Lingual in Oregon The 2010 census reports that 14.6% of the residents of Oregon speak a language other than English at home. If we were to take random samples of 100 residents, what would the standard error of be?   0.146 0.0146 0.035 0.0035

Bi-Lingual in Oregon The 2010 census reports that 14.6% of the residents of Oregon speak a language other than English at home. Recall that SE = 0.035. If we were to take random samples of 100 residents, what would be the distribution of ?   N(0,0.146) N(0,0.035) N(0.035,0.146) N(0.146,0.035)

Section 6.1-CI Confidence Interval for a Proportion

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We plan to construct a 90% confidence interval for the proportion of US citizens who plan to vote. What is the sample proportion? 280 500 56 0.561.96

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We plan to construct a 90% confidence interval for the proportion of US citizens who plan to vote. What is the value of z*? 0.56 1.28 1.645 1.962.576

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We plan to construct a 90% confidence interval for the proportion of US citizens who plan to vote. What is the standard error? 0.56 500 0.00049 0.03650.0222 =0.0222  

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We plan to construct a 90% confidence interval for the proportion of US citizens who plan to vote. What is the margin of error? 0.56 500 0.00049 0.03650.0222 CI = statistic  margin of error

Margin of Error For a single proportion, what is the margin of error? *  2  *    CI = statistic  margin of error CI: *   

Margin of Error Suppose we want to estimate a proportion with a margin of error of 0.03 with 95% confidence. How large a sample size do we need? About 100 About 500 About 1000 About 5000 n    n   

Section 6.1-HT Hypothesis Test for a Proportion

Of the 2430 Major League Baseball (MLB) games played in 2009, the home team won in 54.9% of the games. If we consider 2009 as a representative sample of all MLB games, is this evidence of a home field advantage in Major League Baseball? (a) Yes (b) No (c) No idea The p-value is very small, so we have very strong evidence of a home field advantage. Baseball Home Field Advantage

Baseball Home Field Advantage Counts are greater than 10 in each category Based on this data, there is strong evidence of a home field advantage in major league baseball.   H 0 : p = 0.5 H a : p > 0.5 p-value = 6.2  10 -7

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We want to test to see if this provides evidence that the proportion of US citizens who plan to vote is greater than half. Is this test: Right-tailed Left-tailed Two-tailed No-tailed

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We want to test to see if this provides evidence that the proportion of US citizens who plan to vote is greater than half. What is the standard error for the test? 0.0222 0.0365 0.02236 0.040.06329 We use the null proportion 0.5 in computing the standard error for the test.

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We want to test to see if this provides evidence that the proportion of US citizens who plan to vote is greater than half. What is the test statistic? 2.703 25.225 25.045 2.6830.05 =2.683  

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We want to test to see if this provides evidence that the proportion of US citizens who plan to vote is greater than half. The test statistic is z=2.683. What is the p-value? 0.0072 0.0036 0.036 0.0720.05

In a random sample of 500 US citizens, 280 plan to vote in the upcoming election. We want to test to see if this provides evidence that the proportion of US citizens who plan to vote is greater than half. What is the conclusion at a 5% level? Reject H 0 and conclude that more than half of US citizens plan to vote. Reject H0 and conclude that it is not true that more than half of US citizens plan to vote.Do not reject H 0 and conclude that more than half of US citizens plan to vote. Do not reject H 0 and conclude that it is not true that more than half of US citizens plan to vote.