/
5.2  Nuclear Reactions In the nuclear equation for alpha decay, the mass number of the 5.2  Nuclear Reactions In the nuclear equation for alpha decay, the mass number of the

5.2 Nuclear Reactions In the nuclear equation for alpha decay, the mass number of the - PowerPoint Presentation

roy
roy . @roy
Follow
343 views
Uploaded On 2022-06-15

5.2 Nuclear Reactions In the nuclear equation for alpha decay, the mass number of the - PPT Presentation

Learning Goal Write a balanced nuclear equation showing mass numbers and atomic numbers for radioactive decay Balancing Nuclear Equations In a process called radioactive decay the nucleus breaks down by emitting radiation ID: 918858

equation number nucleus nuclear number equation nuclear nucleus step atomic decay mass alpha write beta determine radioactive particle missing

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "5.2 Nuclear Reactions In the nuclear eq..." is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

5.2 Nuclear Reactions

In the nuclear equation for alpha decay, the mass number of the new nucleus decreases by 4 and its atomic number decreases by 2.

Learning Goal Write a balanced nuclear equation showing mass numbers and atomic numbers for radioactive decay.

Slide2

Balancing Nuclear Equations

In a process called radioactive decay, the nucleus breaks down by emitting radiation.

The process is represented by a nuclear in whichthe mass number and atomic number may change.the sum of the mass numbers and the sum of the atomic numbers are equal for the reactants and the products: Mass number sum: 251 = 251 251Cf  247Cm + 4He 98 96 2

Atomic number sum: 98 = 98

Core Chemistry Skill

Writing Nuclear Equations

Slide3

Alpha Decay

Alpha decay occurs when a radioactive nucleus emits an alpha particle

, forming a new nucleus with a mass number that is decreased by 4 and an atomic number that is decreased by 2.

Slide4

Guide to Completing Nuclear Equations

Slide5

Equation for Alpha Emission

Complete the following nuclear equation for the decay of

americium-241:STEP 1 Write the incomplete nuclear equation.

ANALYZE Given

Need

THE PROBLEM

Am-241, balanced nuclear equation

alpha decay

4

2

He

Slide6

Equation for Alpha Emission

Complete the following nuclear equation for the decay of

americium-241:STEP 2 Determine the missing mass number. 241 = ? + 4 241 − 4 = ? 241 – 4 = 237 (mass number of new nucleus)

STEP 3

Determine the missing atomic number.

95

= ? + 2 95 – 2 = ? 95 − 2 = 93 (atomic number of new nucleus)4

2

He

Slide7

Equation for Alpha Emission

Complete the following nuclear equation for the decay ofamericium-241:

STEP 4 Determine the symbol of the new nucleus. The element that has atomic number 93 is neptunium, Np. STEP 5 Complete the nuclear equation. 42

He

Slide8

Beta Decay

In the nuclear equation for beta decay, a beta particle, an electron, is emitted from the nucleus when a neutron in the nucleus breaks down, forming a proton and a beta particle and increasing the atomic number by 1.

0–1e

Slide9

Equation for Beta Decay

Write an equation for the decay of 42

K, a beta emitter.STEP 1 Write the incomplete nuclear equation.

0

–1

e

Slide10

Equation for Beta Decay

Write an equation for the decay of

42K, a beta emitter.STEP 2 Determine the missing mass number. 42 = ? + 0 42 – 0 = ? 42 − 0 = 42 (mass number of new nucleus)STEP 3

Determine the missing atomic number.

19

= ? − 1 19 + 1 = ? 19 + 1 = 20 (atomic number of new nucleus) 0–1

e

Slide11

Equation for Beta Decay

Write an equation for the decay of

42K, a beta emitter.STEP 4 Determine the symbol of the new nucleus. The element that has atomic number 20 is calcium (Ca). STEP 5 Complete the nuclear equation.

0

–1

e

Slide12

Study Check

Write the nuclear equation for the beta decay of

60Co.

Slide13

Solution

Write the nuclear equation for the beta decay of 60Co.

STEP 1 Write the incomplete nuclear equation.

Slide14

Solution

Write the nuclear equation for the beta decay of 60

Co.STEP 2 Determine the missing mass number. 60 = ? + 0 60 – 0 = ? 60 − 0 = 60 (mass number of new nucleus)STEP 3 Determine the missing atomic number. 27

= ? − 1

27 + 1 = ?

27 + 1 = 28 (atomic number of new nucleus)

Slide15

Solution

Write the nuclear equation for the beta decay of 60

Co.STEP 4 Determine the symbol of the new nucleus. The element that has atomic number 28 is nickel (Ni). STEP 5 Complete the nuclear equation.

Slide16

Positron Emission

In positron emission,

a proton is converted to a neutron and a positron.the mass number of the new nucleus is the same, but the atomic number decreases by 1. 0+1e

Slide17

Gamma Radiation

In gamma radiation

,energy is emitted from an unstable nucleus, indicated by m following the mass number.the mass number and the atomic number of the new nucleus are the same.00γ

Slide18

Summary of Types of Radiation

When the nuclei of alpha, beta, positron, and gamma

emitters emit radiation, new and more stable nuclei are produced.

Slide19

Producing Radioactive Isotopes

Radioactive isotopes are produced

when a stable nucleus is converted to a radioactive nucleus by bombarding it with a small particle.in a process called transmutation.

When nonradioactive B-10 is bombarded by an alpha particle, the products are radioactive N-13 and a neutron.

Slide20

Equation for Producing New Isotopes by Bombardment

Write the balanced nuclear equation for the bombardment of nickel-58 by a proton, , which produces a radioactive isotope and an alpha particle.

STEP 1 Write the incomplete nuclear equation.

Slide21

Equation for Producing New Isotopes by Bombardment

Write the balanced nuclear equation for the bombardment of nickel-58 by a proton,

, which produces a radioactive isotope and an alpha particle.STEP 2 Determine the missing mass number. 1 + 58 = ? + 4 59 – 4 = ? 59 − 4 = 55 (mass number of new nucleus)STEP 3 Determine the missing atomic number.

1 + 28 = ? + 2

29 − 2 = ?

29 − 2 = 27 (atomic number of new nucleus

)

Slide22

Equation for Producing New Isotopes by Bombardment

Write the balanced nuclear equation for the bombardment of nickel-58 by a proton,

, which produces a radioactive isotope and an alpha particle.STEP 4 Determine the symbol of the new nucleus. The element that has atomic number 27 is cobalt (Co). STEP 5 Complete the nuclear equation.

Slide23

Study Check

What radioactive isotope is produced when a neutron bombards

98Tc, releasing an alpha particle?

Slide24

Solution

What radioactive isotope is produced when a neutron bombards 98

Tc, releasing an alpha particle?STEP 1 Write the incomplete nuclear equation.

ANALYZE Given Need

THE PROBLEM

neutron bombardment balanced nuclear

Tc-98

equation

Slide25

Solution

What radioactive isotope is produced when a neutron bombards

98Tc, releasing an alpha particle?STEP 2 Determine the missing mass number. 1 + 98 = ? + 4 99 – 4 = ? 99

− 4 = 95 (mass number of new nucleus)

STEP

3

Determine the missing atomic number. 43 + 0 = ? + 2 43 − 2 = ? 43 − 2 = 41 (atomic number of new nucleus)

Slide26

Solution

What radioactive isotope is produced when a neutron bombards

98Tc, releasing an alpha particle?STEP 4 Determine the symbol of the new nucleus. The element that has atomic number 41 is niobium (Nb).

STEP

5

Complete the nuclear equation

.