/
int x = 100; int x = 100;

int x = 100; - PowerPoint Presentation

stefany-barnette
stefany-barnette . @stefany-barnette
Follow
394 views
Uploaded On 2016-06-18

int x = 100; - PPT Presentation

sub1 ampx void sub1 int pint pint pint 25 100 pint x ampx pint or dereferenced value of pint is the value of what pint points to 100 125 passing the address of x ID: 366487

int ppint pint 100 ppint int 100 pint amp points referenced sub2 passing void address sub1 malloc 125 sizeof

Share:

Link:

Embed:

Download Presentation from below link

Download Presentation The PPT/PDF document "int x = 100;" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.


Presentation Transcript

Slide1

int x = 100;sub1 (&x);void sub1 (int *pint){ *pint = *pint + 25;}

100

pint

x

&x

pint

or

de-referenced value of pint is the

value of

what pint points to

100

125

passing the address of x

Example 1Slide2

int x = 100;int *p = &x;sub1 (p);void sub1 (int *pint){

*pint = *pint + 25;}

100

pint

x

p

de-referenced value of pint is the value of what pint points to

100

125

passing the

value

of p which is the address of x

Example 2Slide3

int x = 100;int *p = &x;sub2 (&p);void sub2 (int **ppint

){

**ppint = **

ppint + 25;

}

100

ppint

x

p

double de-referenced value of

ppint

is the value of the value of what

ppint points to

100

125

passing the

address

of p

Example 3Slide4

int x = 100;int *p = &x;sub2 (&p);void sub2 (int **ppint

){

*ppint =

malloc(

sizeof(int));

**ppint = 50;

}

100

ppint

x

p

double de-referenced value of

ppint

is

the value of the value of

what

ppint

points to

passing the

address

of p

single de-referenced value of

ppint

is

the value of

what

ppint

points to. In this case, we are assigning a value to what

ppint

points to.

malloc-ed

50

Example 4Slide5

int x = 100;int *p = &x;sub2 (&p);void sub2 (int **

ppint){

ppint

= malloc

(sizeof

(int));

*ppint

= 50;}

100

ppint

x

p

single de-referenced value of

ppint

is

the value of

what

ppint

points to

passing the

address

of p

no de-referencing !! What is this changing?

malloc-ed

50

Example 5

ppint

itself

Related Contents


Next Show more