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 GCSE  Circle Theorems Dr J Frost (jfrost@tiffin.kingston.sch.uk  GCSE  Circle Theorems Dr J Frost (jfrost@tiffin.kingston.sch.uk

GCSE Circle Theorems Dr J Frost (jfrost@tiffin.kingston.sch.uk - PowerPoint Presentation

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GCSE Circle Theorems Dr J Frost (jfrost@tiffin.kingston.sch.uk - PPT Presentation

wwwdrfrostmathscom Last modified 31 st August 2015 RECAP Parts of a Circle Sector Minor Segment Diameter Radius Tangent Chord Minor Arc Circumference ID: 776499

angle angles circle add angle angles circle add theorems quadrilateral segment equal triangle tangent radius circumference 180 theorem lengths

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Slide1

GCSE Circle Theorems

Dr J Frost (jfrost@tiffin.kingston.sch.uk)www.drfrostmaths.com

Last modified:

31

st

August 2015

Slide2

RECAP

: Parts of a Circle

Sector

(Minor)

Segment

Diameter

Radius

Tangent

Chord

(Minor) Arc

Circumference

?

?

?

?

?

!

?

?

?

Slide3

What are Circle Theorems

Circle Theorems are laws that apply to both

angles

and

lengths when circles are involved. We’ll deal with them in groups.

#1 Non-Circle Theorems

These are not circle theorems, but are useful in questions involving circle theorems.

50

130

?

Angles in a quadrilateral add up to 360.

The radius is of constant length

Bro Tip

: When you have multiple radii, put a mark on each of them to remind yourself they’re the same length.

Slide4

#2 Circle Theorems Involving Right Angles

!

radius

tangent

“Angle between radius and tangent is 90

”.

“Angle in semicircle is 90

.”

Note that the hypotenuse of the triangle MUST be the diameter.

Bro Tip:

Remember the wording in the black boxes, because you’re often required to justify in words a particular angle in an exam.

Slide5

#3 Circle Theorems Involving Other Angles

!

“Angles in same segment are equal.”

“Angle at centre is twice the angle at the circumference.”

a

a

a

2a

Slide6

#3 Circle Theorems Involving Other Angles

!

Opposite angles of

cyclic quadrilateral

add up to 180.

x

x

180-x

Slide7

#4 Circle Theorems Involving Lengths

Lengths of the tangents from a point to the circle are equal.

There’s only one you need to know...

Slide8

Which Circle Theorem?

Identify which circle theorems you could use to solve each question.

O

160

100

?

Angle in

semicircle

is 90

Angle between

tangent and radius

is 90

Opposite angles of

cyclic quadrilateral

add to 180

Angles in same segment are equal

Angle at centre is twice angle at circumference

Lengths of the tangents from a point to the circle are equal

Two angles in isosceles triangle the same

Angles of quadrilateral add to 360

Reveal

Slide9

Which Circle Theorem?

Identify which circle theorems you could use to solve each question.

70

60

70

?

Angle in

semicircle

is 90

Angle between

tangent and radius

is 90

Opposite angles of

cyclic quadrilateral

add to 180

Angles in same segment are equal

Angle at centre is twice angle at circumference

Lengths of the tangents from a point to the circle are equal

Two angles in isosceles triangle the same

Angles of quadrilateral add to 360

Reveal

Slide10

Which Circle Theorem?

Identify which circle theorems you could use to solve each question.

115

?

Angle in

semicircle

is 90

Angle between tangent and radius is 90

Opposite angles of cyclic quadrilateral add to 180

Angles in same segment are equal

Angle at centre is twice angle at circumference

Lengths of the tangents from a point to the circle are equal

Two angles in isosceles triangle the same

Angles of quadrilateral add to 360

Reveal

Slide11

Which Circle Theorem?

Identify which circle theorems you could use to solve each question.

70

?

Angle in

semicircle

is 90

Angle between

tangent and radius is 90

Opposite angles of cyclic quadrilateral add to 180

Angles in same segment are equal

Angle at centre is twice angle at circumference

Lengths of the tangents from a point to the circle are equal

Two angles in isosceles triangle the same

Angles of quadrilateral add to 360

Reveal

Slide12

Which Circle Theorem?

Identify which circle theorems you could use to solve each question.

Angle in

semicircle

is 90

Angle between tangent and radius is 90

Opposite angles of cyclic quadrilateral add to 180

Angles in same segment are equal

Angle at centre is twice angle at circumference

Lengths of the tangents from a point to the circle are equal

32

?

Two angles in isosceles triangle the same

Angles of

quadrilateral add to 360

Reveal

Slide13

Which Circle Theorem?

Identify which circle theorems you could use to solve each question.

Angle in

semicircle

is 90

Angle between tangent and radius is 90

Opposite angles of cyclic quadrilateral add to 180

Angles in same segment are equal

Angle at centre is twice angle at circumference

Lengths of the tangents from a point to the circle are equal

31

?

Two angles in isosceles triangle the same

Angles of

quadrilateral add to 360

Reveal

Slide14

#5 Alternate Segment Theorem

This one is probably the hardest to remember and a particular favourite in the Intermediate/Senior Maths Challenges.

!

The angle between the tangent and a chord...

tangent

chord

Click to Start

Bromanimation

...is equal to the angle in the

alternate segment

This is called the

alternate segment

because it’s the segment on the other side of the chord.

Slide15

Check Your Understanding

z = 58

?

Slide16

Check Your Understanding

Angle ABC =

Give a reason:

Angle AOC =

Give a reason:

Angle CAE =

Give a reason:

112

Supplementary angles of cyclic quadrilateral add up to 180.

136

68

Angle at centre is double angle at circumference.

Alternate Segment Theorem.

?

?

?

?

?

?

Source: IGCSE Jan 2014 (R)

Slide17

Exercises

Printed collection of past GCSE questions.

Slide18

Answers to more difficult questions

Determine angle ADB.

Source: IGCSE May 2013

39

77

64

?

?

?

Slide19

Answers to more difficult questions

(Towards the end of your sheet)

116

32

42

?

1

?

2

?

3

Angle at

centre

is twice angle at circumference

Alternate Segment Theorem

Two angles in isosceles triangle the same

Slide20

APPENDIX

: Proofs

A

B

C

O

a

a

180-2a

2a

90-a

90-a

Let angle BAO be a. Triangle ABO is isosceles so ABO = a. Remaining angle in triangle must be 180-2a. Thus BOC = 2a. Since triangle BOC is isosceles, angle BOC = OCB = 90 – a. Thus angle ABC = ABO + OBC = a + 90 – a = 90.

?

?

?

?

?

Slide21

!

x

a

APPENDIX

: Proofs

b

b

a

?

?

Opposite angles of

cyclic quadrilateral

add up to 180.

This combined angle

= 180 – a – b

(angles in a triangle)

?

Adding opposite angles:

a + b + 180

– a – b = 180

Slide22

APPENDIX

: Proofs

Alternate Segment Theorem

1

: Angle between tangent and radius is 90, so angle CAD = 90 -

90-

A

B

C

D

?

1

?

3

?

2

2

: Angle in semicircle is 90.

3

: Angles in triangle add up to 180.

?

4

4

: But any other angle in the same segment will be the same.