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Creed Reilly, Sophomore, Engineering Creed Reilly, Sophomore, Engineering

Creed Reilly, Sophomore, Engineering - PowerPoint Presentation

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Creed Reilly, Sophomore, Engineering - PPT Presentation

Advisor Professor Anna Mazzucato Graduate Student Yajie Zhang Solving a Transmission Problem for the 1D Diffusion Equation Transmission Problem for the 1D Heat Equation Diffusion coefficient c jumps at x12 the interface Impose transmission conditions at interface Solve equation in ID: 799260

error equation method 094 equation error 094 method transmission heat 093 condition diffusion solution general 09e displacement 89e 29e

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Presentation Transcript

Slide1

Creed Reilly, Sophomore, EngineeringAdvisor: Professor Anna MazzucatoGraduate Student: Yajie Zhang

Solving a Transmission Problem for the 1D Diffusion Equation

Slide2

Transmission Problem for the 1D Heat EquationDiffusion coefficient c jumps at x=1/2 (the interface). Impose transmission conditions at interface. Solve equation in [0,1]. Impose Dirichlet boundary conditions at x=0,1. Initial condition is sin(πx).

 

 

 

    

     

General Heat Equation in 1 Dimension with Transmission Condition

Slide3

Our Project has Major Real World Applications

Model Composite Materials:

Slide4

This is the simplest (explicit) first-order finite difference method to solve the heat equation.First order Taylor expansion was used for the time derivative (Ut)The center-difference method was used for the second space derivative (Uxx)

Because this is an explicit method, a convergence condition had to be observed:

The Method Used was Forward Euler’s

 

Slide5

The General Equation was then DiscretizedDiscretization of the Exact Solution

:

 

 

Discretization of the Exact Solution: 

 

Slide6

The L2 Error Calculation is shown below:

The program

used is

seen to converge as long as the L2 error decreases as the displacement step decreases.

Since the error change is on a logarithmic scale, the equation should approach the value α of approximately 1. The L2 Error Calculation Proved Most BeneficialCL=1 CR=2 Δx=0.1CL=1 CR=2 Δx=0.025

Slide7

Graphs and Tables

Δx

L2(1)

Linf(1)

L2(2)Linf(2)LogE0.13.03E-094.51E-094.05E-096.02E-09-0.422060.054.05E-096.02E-093.29E-094.89E-090.3028070.0253.29E-094.89E-092.09E-093.10E-09

0.656120.01252.09E-093.10E-091.17E-091.74E-090.829307

0.006251.17E-09

1.74E-09

6.23E-10

9.24E-10

0.915078

0.003125

6.23E-10

9.24E-10

No Mem

No Mem

N/A

Table 1: L2 and L∞ error for various displacement

steps

Graph 1: Diffusion of energy when the left half has a C=1 and the right has a C=2.

Graph 2: Diffusion of energy when the left half has a C=1 and the right has a C=100.