Assistant Professor email imtiazhussainfacultymuetedupk URL httpimtiazhussainkalwarweeblycom Lecture6 Thyristor Gate Control Circuits 1 Outline Introduction Voltage Divider Triggering ID: 934446
Download Presentation The PPT/PDF document "Power Electronics Dr. Imtiaz Hussain" is the property of its rightful owner. Permission is granted to download and print the materials on this web site for personal, non-commercial use only, and to display it on your personal computer provided you do not modify the materials and that you retain all copyright notices contained in the materials. By downloading content from our website, you accept the terms of this agreement.
Slide1
Power Electronics
Dr. Imtiaz HussainAssistant Professoremail: imtiaz.hussain@faculty.muet.edu.pkURL :http://imtiazhussainkalwar.weebly.com/
Lecture-6Thyristor Gate Control Circuits
1
Slide2Outline
IntroductionVoltage Divider TriggeringRC TriggeringDouble RC Triggering
Slide3Introduction
The popular terms used to describe how SCR is operating are conduction angle and firing delay angle. Conduction angle is the number of degrees of an ac cycle during which the SCR is turned ON.Firing delay angle is the number of degrees of an ac cycle that elapses before the SCR is turned ON.
Of course, these terms are based on the notion of total cycle time (3600)
Slide4Introduction
An SCR is fired by a short burst of current into the gate (IG).The amount of gate current needed to a fire particular SCR is symbolized as IGT.Most SCRs require current between 0.1 and 50mA.
Since there is a standard pn-junction between gate and cathode, voltage between these two terminals (VGK) must be slightly greater than 0.7 volt.
Slide5Example-1
For the circuit shown in figure below, what voltage is required at point X to fire the SCR? The gate current needed to fire 2N3669 is 20mA under normal conditions.
Solution
The voltage between point X and cathode must be sufficient to forward bias the junction between X and K (0.7V).
And also at least cause 20mA
to flow
from 150
Ω
resistor.
For 20mA current to flow in XG branch we need
Therefore,
Gate Control Circuits
Gate Control Circuit DesignConsideration must be given to the following points when designing gate control circuits.
The gate signal should be removed after the thyristor has been turned on. A continuous gate signal will increase the power loss in the gate junction.
No gate signal should be applied when the thyristor is reversed biased. If a gate signal is applied under these conditions, the thyristor may fail due to an increased leakage current.
The width of the gate pulse must be greater than the time required for the anode current to rise to the holding current. In practice, the gate pulse width is made wider than the turn-on time of the thyristor.
6
Slide7A simple type of gate control circuit (triggering circuit) is shown in following figure.
Gate Control Circuits
When SW is closed, there will be current into the gate when supply voltage goes positive.
Firing delay angle is determined by setting of R
2
.
Slide8One disadvantage of this simple triggering circuit is that the firing delay angle is adjustable is only from about 0
0 to 900.Gate Control Circuits
This can be understood by referring to following figure.
Slide9Example-2
For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 20o. To what value should R2
be adjusted?
Solution
At 20o instantaneous supply voltage is
34
3K
Ω
40
Ω
Voltage drop across Load
Example-2
Total resistance in the gate lead is given by
3K
Ω
40
Ω
Therefore, R
2
is
Example-3
For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 30o. To what value should R2
be adjusted?
Solution
At 30o instantaneous supply voltage is
3K
Ω
40
Ω
Voltage drop across Load
Example-3
Total resistance in the gate lead is given by
3K
Ω
40
Ω
Therefore, R
2
is
Example-4
For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 60o. To what value should R2
be adjusted?
Solution
At 30o instantaneous supply voltage is
3K
Ω
40
Ω
Voltage drop across Load
Example-4
Total resistance in the gate lead is given by
3K
Ω
40
Ω
Therefore, R
2
is
Example-5
For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 90o. To what value should R2
be adjusted?
Solution
At 90o instantaneous supply voltage is
3K
Ω
40
Ω
Voltage drop across Load
Example-5
Total resistance in the gate lead is given by
3K
Ω
40
Ω
Therefore, R
2
is
Example-6
For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 150o. To what value should R2
be adjusted?
Solution
3K
Ω
40
Ω
At 150
o
instantaneous supply voltage is
Voltage drop across Load
Example-6
Total resistance in the gate lead is given by
3K
Ω
5
Ω
Therefore, R
2
is
R
2
is same as it was for firing angle of 30
o
. Therefore with this circuit arrangement it is not possible to fire SCR beyond 90
o
.
Slide19Example-7
For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 10o. To what value should R2
be adjusted?
Solution
At 10o instantaneous supply voltage is
3
3K
Ω
40
Ω
Voltage drop across Load
Example-7
Total resistance in the gate lead is given by
3K
Ω
40
Ω
Therefore, R
2
is
Cannot have firing angle of 10
o
. For extended firing angle R
3
can be made smaller.
Slide21Example-8
For following figure assume that the supply is 115V rms, IGT=15mA, and R1=3KΩ. The firing delay is desired to be 18o. To what value should R2
be adjusted?
Solution
At 15o instantaneous supply voltage is
3K
Ω
40
Ω
Voltage drop across Load
Example-8
Total resistance in the gate lead is given by
3K
Ω
40
Ω
Therefore, R
2
is
Conclusion
The value of resistor R2 is increasing as firing angle is further delayed. S. NoFiring Angle
R21
10o-1.21KΩ
218160Ω3
20o
600
Ω
4
30
o
2.3K
Ω
5
60
o
9.3K
Ω690o7.7KΩ7150o2.37.7KΩ
Range of Firing Angles
Slide24RC Triggering Circuits
The simplest method of improving gate control is to add a capacitor at the bottom of the gate lead resistance as shown in following figure.
Advantage of this circuit is that the firing delay angle can be adjusted past 90
o
.
Slide25RC Triggering Circuits
This can be understood by focusing on the voltage across Capacitor C.
When the ac supply is –
ve
, the reverse voltage across SCR is applied to RC triggering circuit, charging the capacitor –
ve
on top plate and +
ve
on bottom plate.
When the supply enters its positive half cycle, the forward voltage drop across SCR tends to charge C in opposite direction.
However, voltage buildup in new direction is delayed until the –
ve
charge is removed.
Slide26RC Triggering Circuits
The idea can be extended to achieve even extended firing angles by modifying the circuit slightly.
A resistor has been inserted into the gate lead, requiring the capacitor to charge higher than 0.7 V to trigger the SCR.
With the resistor in place, capacitor voltage must reach a value large enough to force sufficient current (I
GT
) through the resistor.
Slide27RC Triggering Circuits
The firing delay angle can further be extended by the use of double RC network as shown in following figure.
The delayed voltage across C
1
is
used
to charge C
2
resulting in even further delay in building up the gate voltage.
Slide28Triggering
50Hz sine wave takes 1/50 seconds to complete one cycle.
RC Triggering Circuits
Capacitors in RC triggering circuits usually fall in the range from 0.01µF to 1µF.
For the given capacitor sizes minimum firing delay angle (maximum load current) is set by fixed resistors R
1
and R
3
.
The maximum firing angle (minimum load current) is set mostly by variable resistor R
2
.
When these gate control circuits are used with 50Hz AC supply, the time constant of the RC circuit should fall in the range of 1-20ms.
Slide30RC Triggering Circuits
For single RC circuit of fig (a) the product (R
1
+R
2
)C
1
should fall in the range 1ms to 20ms.
For double RC circuit of fig(b
) (R
1
+R
2
)C
1
should fall in that range and R
3C2 should also fall in that range.
Fig(a)
Fig(b)
Slide31Example-9
For the circuit shown in following figure approximate the R1, R2 and R3 to give wide range of firing adjustment.
Example-9
The total time constant must fall in the range of 1ms-20ms.Let us set
and
. RC ntwork-1 must provide 1ms-18ms of firing delay and RC netwrork-2 2ms of delay.
Minimum time constant occurs in RC network-1 when R
2
is set to minimum.
Example-9
Maximum time constant occurs in RC netwrok-1 when R
2
is set to maximum.
Example-9
Time constant of RC netwrok-2 is 2ms.
Example-9
Minimum and maximum firing angles are (18
o
=1ms)
Example-10
For the circuit shown in following figure, to what value the potentiometer be set to obtain a firing delay angle of 120o.
Use of Break Over Devices
The firing circuits discussed so far share two disadvantages.Temperature dependenceInconsistent firing behaviour between SCRs of same typeThese problems can be eliminated by introducing a break over device at gate terminal
Slide38Use of Break Over Devices
Four layer diode (Shockley Diode) has certain break over voltage.
Slide39Shockley Diode
Slide40End of Lecture-6
To download this lecture visithttp://imtiazhussainkalwar.weebly.com/